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Thanks Bunuel. +1
A question - what is the best way u use to know if the "good" area is above or below?
i mean - what was the best way for u to know that its between -1/2 to 0
i used numbers ex. 1/4 but it consumes time! is there any better technique?
thanks.
Check the link in my previous post. There are beautiful explanations by gurpreetsingh and Karishma.
General idea is as follows:
We have: \((1+2x)*x^3*(1-2x)<0\) --> roots are -1/2, 0, and 1/2 (equate the expressions to zero to get the roots and list them in ascending order), this gives us 4 ranges: \(x<-\frac{1}{2}\), \(-\frac{1}{2}<x<0\), \(0<x<\frac{1}{2}\) and \(x>\frac{1}{2}\) --> now, test some extreme value: for example if \(x\) is very large number than first two terms ((1+2x) and x) will be positive but the third term will be negative which gives the negative product, so when \(x>\frac{1}{2}\) the expression is negative. Now the trick: as in the 4th range expression is negative then in 3rd it'll be positive, in 2nd it'l be negative again and finally in 1st it'll be positive:
+ - + -. So, the ranges when the expression is negative are: \(-\frac{1}{2}<x<0\) (2nd range) or \(x>\frac{1}{2}\) (4th range).
Hope its clear.