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04 Jun 2015, 04:08
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:21) correct
31%
(01:36)
wrong
based on 558
sessions
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Which of the following equations represents a line perpendicular to line k in the figure above?
(A) 3y + 2x = –12
(B) 2y + x = 0
(C) 2y – x = 0
(D) y + 2x = 12
(E) y – 2x = 12
Attachment:
2015-06-04_1507.png [ 19.63 KiB | Viewed 12434 times ]
04 Jun 2015, 04:24
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Slope of line k is (y2-y1)/ (x2-x1)
= 0- (-6)/ 12-0 = 1/2
Slope of the line perpendicular to line k will have slope of -2 (For perpendicular lines slopes are negative reciprocal of each other)
Only option D has a slope of -2.
Answer D
= 0- (-6)/ 12-0 = 1/2
Slope of the line perpendicular to line k will have slope of -2 (For perpendicular lines slopes are negative reciprocal of each other)
Only option D has a slope of -2.
Answer D
08 Jun 2015, 04:51
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Bunuel
MANHATTAN GMAT OFFICIAL SOLUTION:
The product of the slopes of two perpendicular lines is –1. The slope of line k is given by:
\(\frac{rise}{run}=\frac{change \ in \ y}{change \ in \ x}=\frac{0-(-6)}{12-0}=\frac{1}{2}\).
Thus, the slope of the line perpendicular to k is –2.
Put each choice in slope-intercept form: y = mx + b form, where the slope is m.
Attachment:
2015-06-08_1549.png [ 84.62 KiB | Viewed 11106 times ]
