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Hi Bunuel,

I used the theory from GMAT club but got the question wrong because i assumed you need both 2 and 5. Does the rule imply that any denominator with a 2 or a 5 and not necessarily both 2 and a 5(with a positive exponent) = terminating decimal ?
Also, can we conclude that only non-terminating decimals when another prime number is in the denominator other than 2 and 5(assuming the fraction is in its most reduced form of course).
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Hi Bunuel,

I used the theory from GMAT club but got the question wrong because i assumed you need both 2 and 5. Does the rule imply that any denominator with a 2 or a 5 and not necessarily both 2 and a 5(with a positive exponent) = terminating decimal ?
Also, can we conclude that only non-terminating decimals when another prime number is in the denominator other than 2 and 5(assuming the fraction is in its most reduced form of course).

Please read the theory bit carefully. It says "\(2^n5^m\), where m and n are non-negative integers". So, n or m could be 0. This means that the denominator must have either only 2's, only 5's or any combination of 2's and 5's.

For similiar questions check Trailing Zeros Questions in our Special Questions Directory.
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Bunuel
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Hi Bunuel,

I used the theory from GMAT club but got the question wrong because i assumed you need both 2 and 5. Does the rule imply that any denominator with a 2 or a 5 and not necessarily both 2 and a 5(with a positive exponent) = terminating decimal ?
Also, can we conclude that only non-terminating decimals when another prime number is in the denominator other than 2 and 5(assuming the fraction is in its most reduced form of course).

Please read the theory bit carefully. It says "\(2^n5^m\), where m and n are non-negative integers". So, n or m could be 0. This means that the denominator must have either only 2's, only 5's or any combination of 2's and 5's.

For similiar questions check Trailing Zeros Questions in our Special Questions Directory.


I also used your approach. First I also thought that I would need 5 as well, but fortunately I remembered that we could also have 5^0

however, I convinced myself by just randomly dividing 1/2, 1/4, 1/8 and so on till I was confident enough to move on =)
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Inclusion of 3 in 12 in answer option A will lead to a non-terminating decimal.
Numbers 2 and 5 don't end in Non terminating decimals , hence answer option E.
Time taken : 4 seconds. :cool:
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Which of the following has a decimal equivalent that is a terminating decimal?

I. 1/12
II. 1/10^2
III. 1/2^10

A. I only
B. II only
C. I and II
D. I and III
E. II and III


A terminating decimal would be any number divided by 2,5, or the combination of 2 and 5 (10).

1/2 = 0.5
1/5 = 0.2
1/10 = 0.1
1/50 = 0.02 etc..

Only II and III fit this property.

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