Last visit was: 29 Apr 2026, 13:15 It is currently 29 Apr 2026, 13:15
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
obedear
Joined: 05 Sep 2024
Last visit: 29 Apr 2026
Posts: 63
Own Kudos:
40
 [1]
Given Kudos: 11
Products:
Posts: 63
Kudos: 40
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
poojaarora1818
Joined: 30 Jul 2019
Last visit: 29 Apr 2026
Posts: 1,631
Own Kudos:
784
 [1]
Given Kudos: 3,825
Location: India
Concentration: General Management, Economics
GPA: 3
WE:Human Resources (Real Estate)
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
flippedeclipse
Joined: 26 Apr 2025
Last visit: 29 Apr 2026
Posts: 105
Own Kudos:
73
 [1]
Given Kudos: 37
GMAT Focus 1: 655 Q80 V87 DI80
Products:
GMAT Focus 1: 655 Q80 V87 DI80
Posts: 105
Kudos: 73
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
canopyinthecity
Joined: 12 Jul 2025
Last visit: 29 Apr 2026
Posts: 92
Own Kudos:
61
 [1]
Given Kudos: 19
Products:
Posts: 92
Kudos: 61
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
D = 400 N mile
T(A) = k hours
T(B) = (k - 2.5) hours
S(B) will be higher than S(A) as its time is lesser.

As per options,

SpeedTime
2516
3212.5
4010
508
646.25
805

So the pair with 2.5 hours time difference is 32 and 40.

Therefore, S(A) = 32 and S(B) = 40
User avatar
jkkamau
Joined: 25 May 2020
Last visit: 29 Apr 2026
Posts: 226
Own Kudos:
Given Kudos: 142
Location: Kenya
Schools: Haas '25
GMAT 1: 730 Q50 V46
GPA: 3.5
Products:
Schools: Haas '25
GMAT 1: 730 Q50 V46
Posts: 226
Kudos: 190
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Assume ship Alpha speed is V1 and Beta V2.
That means 400/V1-400/V2=2.5
From the above we can test the answer choices starting with 25 for Alpha
So 400/25= 16-400/V2=2.5 yields V2 as 29.62 which is not an option
So we try 32 400/32= 12.5; 12.5-400/V2=2.5= 12.5V2-2.5V2=400 = V2=40
So for Alpha was 32 while Beta was 40
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
User avatar
rahumangal
Joined: 20 Nov 2022
Last visit: 27 Apr 2026
Posts: 71
Own Kudos:
66
 [1]
Given Kudos: 316
Location: India
Concentration: Finance, Real Estate
GPA: 3.99
WE:Engineering (Technology)
Products:
Posts: 71
Kudos: 66
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
alpha avg speed (a)= 400/k
beta avg speed (b)= 400/k-2.5
now we can se that alpha is smaller than beta we stat using values from the option to find time taken by alpha and subtract 2.5 from it and find the avg speed of beta and see if it matches any value in the table
let a= 25
400/k=25 s
k=16
k-2.5=13.5
b= 400/13.5=29.6= No value in table and so dont the value of a is not consistent with b
Let a= 32
so 400/k=32
k=50/4
k-2.5=10
b= 400/10=40
a & b are in the table and consitent
Ans- 32 ,40
User avatar
pappal
Joined: 24 Nov 2022
Last visit: 29 Apr 2026
Posts: 322
Own Kudos:
109
 [1]
Given Kudos: 100
Products:
Posts: 322
Kudos: 109
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
average speed =total distance travelled / total time taken
let average speeds of alpha=A NM/hr and of beta=B NM/hr
total distance is 400 NM
i.e. A=400/k and B=400/(k-2.5)
simply we should use k=400/A to find out the value of k which satisfy the above two equations
400/32=12.5 and 400/(12.5-2.5)=400/10=40
so A=32 and B= 40 are consistence with the given conditions
User avatar
chasing725
Joined: 22 Jun 2025
Last visit: 13 Jan 2026
Posts: 176
Own Kudos:
173
 [1]
Given Kudos: 5
Location: United States (OR)
Schools: Stanford
Schools: Stanford
Posts: 176
Kudos: 173
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.

Using the options

400 / 25 = 16
400 / 32 = 12.50
400 / 40 = 10

We can stop as we see a differnece of 2.5

As Beta takes less time than Alpha does, the speed of Beta is more.

Ship Beta= 40
Ship Alpha = 32
User avatar
sunshineeee
Joined: 17 May 2020
Last visit: 09 Apr 2026
Posts: 96
Own Kudos:
Given Kudos: 223
Location: Indonesia
Kudos
Add Kudos
Bookmarks
Bookmark this Post
0. Read twice, understand it's a speed rate question, and simplify the number

T(A) = k
T(B)= k-2.5
D=400
R=?
R=D/T

1.The formula would be

R=D/T

R(A) = 400/k
R(B) = 400/(k-2.5)

2. I use a trial simulation to get the answer

If R(A)=25, k=400/25=80/5=16

T(B) = K-2.5=16-2.5=13.5

R(B)=400/13.5 = 64

3. We got both the answers in the choice

R(A)=25
R(B)=64

Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
User avatar
jefferyillman
Joined: 01 Dec 2024
Last visit: 29 Apr 2026
Posts: 50
Own Kudos:
27
 [1]
Given Kudos: 3
Posts: 50
Kudos: 27
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
alpha 32 and beta 40

t = distance / velocity

400 / x = 400 /y + 2.5

400 / 32 = 12.5 hours

400 / 40 = 10 + 2.5 + 12.5 hours
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
User avatar
Rahilgaur
Joined: 24 Jun 2024
Last visit: 26 Jan 2026
Posts: 162
Own Kudos:
125
 [1]
Given Kudos: 47
GMAT Focus 1: 575 Q81 V82 DI72
Products:
GMAT Focus 1: 575 Q81 V82 DI72
Posts: 162
Kudos: 125
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.


Let the speed of ships Alpha and Beta be a & b respectively.

a < b

a = 400/k , b=400/(k-2.5) ---> k-2.5= 400/b ---k = 400/b +2.5

We need to proceed with trial method available options for a or b.

Speed option available are 25, 32, 40, 50, 64 and 80

k = 400/25+2.5 = 18.5 , -----------> a = 4000/185 = 800/37 (not an integer)
k= 100/8 +2.5 = 15 -----------------> a= 400/15 = 50/3 (not an integer)
k= 12.5 -------------------------------> a= 4000/125 = 40*4/5 = 32
k= 8+2.5 = 10.5 ----------------------> a= 4000/105= 800/21 (not an integer )
k= 100/16+2.5 = 16.66+2.5 = 19.1----> a= 400/19.1 (not an integer)
k = 5+2.5 = 7.5 -------------------------> a=4000/75 = 40*4/3 (not an integer)

Answer speeds are Ship Alpha = 32 , Ship Beta = 40.
User avatar
sriharsha4444
Joined: 06 Jun 2018
Last visit: 05 Mar 2026
Posts: 125
Own Kudos:
84
 [1]
Given Kudos: 803
Posts: 125
Kudos: 84
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
alpha -> 400/k

beta -> 400/(k-2.5)

if we take alpha speed as 32, k = 25/2 =12.5 hours
400/(12.5 -2.5) = 400 /10 = 40

ans: 32, 40 or B, C


another way
400/v1 = k

400/v2 = k-2.5

400/v2 = 400/v1 - 2.5
2.5 = 400/v1 - 400/v2

400/25 = 16
400 / 32 =12.5
400 / 40 = 10
400 / 50 = 8
400 / 64 =6.25
400 / 80 = 5

B,C will give the 2.5 hour difference.


another way:
2.5 / 400 = 1/v1 - 1/v2
1/160 = 1/v1 - 1/v2
160/v1 - 160/v2 = 1

so v1 and v2 should divide into 160.
potential options are 32, 40, 80

or both should not divide into 160
25, 60, 54 are options

filter and then ans: option B, C, or 32, 40
User avatar
gchandana
Joined: 16 May 2024
Last visit: 29 Apr 2026
Posts: 193
Own Kudos:
142
 [1]
Given Kudos: 170
Location: India
Products:
Posts: 193
Kudos: 142
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Notice that all the options are integers.

Now, let's start by testing each option for Alpha, and then we can check if we have a corresponding option for Beta.

If avg speed by Alpha is 25, then k would be 16(400/25). Then k - 2.5 would be 13.5. Avg speed of Beta = 400/13.5(not an integer); we don't have an option for this.
Next, take 32, then k would be 400/32, 12.5, k - 2.5 is 10. This gives avg speed of Beta as 40, for which we have an option.

So Alpha's avg speed is 32, Beta's avg speed is 40.
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
User avatar
Lizaza
Joined: 16 Jan 2021
Last visit: 29 Mar 2026
Posts: 240
Own Kudos:
282
 [1]
Given Kudos: 7
GMAT 1: 710 Q47 V40
GMAT 1: 710 Q47 V40
Posts: 240
Kudos: 282
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Since the time k differs by 2.5 hours, then \(\frac{400}{a} = \frac{400}{b}+2.5\)

If \(a=25\), then \(k=400/25=16\), and \(400/b=13.5\), so \(b=400/13.5=30\), which doesn't fit.
If \(a=32\), then \(k=400/32=12.5\), and \(400/b=10\), so \(b=400/10=40,\) which fits.

Therefore, the answers are 32 = Ship Alpha and 40 = Ship Beta.
User avatar
sanjitscorps18
Joined: 26 Jan 2019
Last visit: 03 Mar 2026
Posts: 723
Own Kudos:
743
 [1]
Given Kudos: 130
Location: India
Schools: IMD'26
Products:
Schools: IMD'26
Posts: 723
Kudos: 743
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Distance = 400

Alpha = k hours
Beta = (k - 2.5) hours

Alpha speed (a) = 400/k
Beta speed (b) = 400/(k - 2.5)

Checking options to substitute for 'a' and 'b'
k = 400/a
k - 2.5 = 400/b

Let a = 25 then k = 400/25 = 16
Then b = 400/(16 - 2.5) = Nearly 30
X Doesn't work

Let a = 32, then k = 400/32 = 12.5
Then b = 400/(12.5 - 2.5) = 400/10 = 40
This works.

Alpha speed = 32
Beta speed = 40

Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
User avatar
Gmat860sanskar
Joined: 05 May 2023
Last visit: 24 Apr 2026
Posts: 212
Own Kudos:
113
 [1]
Given Kudos: 79
Schools: ISB '26
GMAT Focus 1: 605 Q82 V78 DI80
Products:
Schools: ISB '26
GMAT Focus 1: 605 Q82 V78 DI80
Posts: 212
Kudos: 113
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
Given :

Total Distance: 400 N-m
Ship Alpha time to reach : k hours
Ship beta time to reach = k - 2.5 hours

Distance/ time = speed

In Most TPA question, trial and error with relevant and logical options is one of the best tools to solve the question within time limit, as the options most of the time are complimentary to each other, so here we are going to do the same.

notice here we are given different average speeds

I can see the most easy option to check here is 40 as we know 400/10 = 40, so if faster one is 40 then slower one will be k - 2.5 = 10 ; k = 12.5
400/12.5 = 32; and 32 is there in the option

so our answer is 32 & 40
User avatar
linnet
Joined: 11 Dec 2025
Last visit: 22 Jan 2026
Posts: 81
Own Kudos:
42
 [1]
Given Kudos: 1
Posts: 81
Kudos: 42
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Distance= 400 nautical miles
Alpha time= K hrs
Beta time= K-2.5 hrs
Speeds = D/T Alpha = 400/K
Beta = 400/k-2.5, that means beta has high speed than Alpha
Lets covert given speed into times- Distance/speed
25- 16hr
32- 12.5hr
40- 10hr
50- 8hr
64- 6.5h2
80-5hr
Look for the given time difference which is 2.5hrs
12.5-10= 2.5hr ( perfect match)
Slower Ship (Alpha) takes longer time which is 12.5hr and 32m/hr
Faster ship (Beta) shorter time - 10hr add 40nm/hr

Final answer: Alpha= 32
Beta= 40
User avatar
raffaeleprio
Joined: 15 Nov 2020
Last visit: 13 Apr 2026
Posts: 56
Own Kudos:
Given Kudos: 1
Location: Italy
GPA: 3.71
Posts: 56
Kudos: 59
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Recall the speed Ship A = 400/k and Sheep B = 400/(k-2)

If we decompose 400 in prime factors we get 2^4 * 5^2 hence the possible speeds for A must be a factor of 400.

Choosing Va = 40 leads to 10 hours time for A, which is then 10-2=8 hours for B in case Vb = 50

hence Va = 40 and Vb = 50
User avatar
bhanu29
Joined: 02 Oct 2024
Last visit: 29 Apr 2026
Posts: 363
Own Kudos:
276
 [1]
Given Kudos: 263
Location: India
GMAT Focus 1: 675 Q87 V85 DI79
GMAT Focus 2: 715 Q87 V84 DI86
GPA: 9.11
WE:Engineering (Technology)
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
The speed for Alpha = 400/k
speed for beta = 400/(k-2.5)

speed alpha < speed beta

Try options

400/k = 25
if 400/k = 25 => k = 16
speed beta = 400/13.5 ~ 29
Not there. Eliminate

400/k = 32
if 400/k = 32 => k = 12.5
speed beta = 400/10 = 40
It's there
Ship Alpha = 32
Ship Beta = 40
User avatar
msignatius
Joined: 28 Aug 2025
Last visit: 09 Apr 2026
Posts: 131
Own Kudos:
98
 [1]
Given Kudos: 31
Location: India
Concentration: Strategy, Marketing
GMAT Focus 1: 705 Q86 V85 DI84
GPA: 3.5
WE:Marketing (Consulting)
Products:
GMAT Focus 1: 705 Q86 V85 DI84
Posts: 131
Kudos: 98
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Simplification for what we need to do here: There's one ship that takes x hours to complete a 400-mile journey, another takes x-2.5 less or 2.5 hours less than the other.

There are values we can test but with these kinds of questions, I reckon it's better to figure out a pattern that'll help lead us to the answer.

Let's take a small number. If one ship completes the journey in 5 hours, and the other will take 2.5 hours, with that, one is twice as fast as the other. Now, if one ship completes the journey in 10 hours, and the other completes it in 7.5 hours, the faster ship is 25% faster. The longer you add to the journey, the lower the percentage difference in the time covered.

Judging by this information itself, we have enough to eliminate a few answers - 80 miles / hour, which will allow one of the ships to complete the journey in 5 hours, doesn't have an equivalent for the other ship's that either good for 2.5 hours (160mph) or 7.5 hours (53.33mph). Clearly, no speed related to 80 miles / hour will feature anymore.

Is it the same for half that speed? 40mph will help one ship complete the journey in 10 hours, but we already know from above that at 7.5 hours, the ship'll need to be travelling at 53.33mph for that to work, which isn't an answer.

At 12.5 hours, we find the golden answer - 400 / 12.5 = 32 mph, and we can go ahead and mark the 32mph for Ship Alpha, and 40mph for Ship Beta.

Now, isn't this the same as just taking the answers, and solving them? No, because there's enough process of elimination to help in our favor.

- 25mph cannot be the speed of the faster ship.
- At 64mph, we see a ship take 6.25 hours to complete the journey, and any 2.5-hour addition or subtraction - leading to 8.75 or 3.75 - clearly won't connect to any of the other numbers.
- 50 won't correlate to 64 and 80 because they've been eliminate. So if we take that to be the speed of the faster ship, the only 2.5 hours slower can't logically take double the time, so 25 is out of the window. 40 is easy mental math to discard - 8 hours vs 10 hours; that's a just 2-hour difference.
- With maybe a few more math tricks, 32 and 40 can be easily reached.

PS.
I also see value in looking at the factorization for 400, but while considering .5 numbers:

0.5*800
1*400
2*200
2.5*160
4*100
5*80
8*50
10*40
12.5*32
16*25
20*20

Clearly, we see the role of 32, and that can further help narrow the choices.





Bunuel
Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more


Two cargo ships, Ship Alpha and Ship Beta, transport goods along a 400-nautical-mile channel. Ship Alpha makes the journey in k hours. Ship Beta makes the same journey in (k - 2.5) hours.

In the table, select for Ship Alpha a possible average speed (in nautical miles per hour) and select for Ship Beta a possible average speed (in nautical miles per hour) that would be jointly consistent with the given information. Make only two selections, one in each column.
   1   2   3   
Moderators:
Math Expert
109974 posts
498 posts
212 posts