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25 Dec 2025, 06:17
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Bookmarks
given N=120 g, P=90 g, K=60 g ,a farmer has
blend green composition by weight, N:P:K=3:2:1
blend rich composition by weight, N:P:K=2:1:2
need to find the maximum amount any one type can be made at a time?
For blend green: if we take K=60 then N=180(not possible)
so for N=120 K=40 & P=80 is the valid composition for maximum weight=240 g.
similarly For blend rich: upper limit is guided by K=60 so N=60 & P=30
gross weight=150 g
above are the right choices.
blend green composition by weight, N:P:K=3:2:1
blend rich composition by weight, N:P:K=2:1:2
need to find the maximum amount any one type can be made at a time?
For blend green: if we take K=60 then N=180(not possible)
so for N=120 K=40 & P=80 is the valid composition for maximum weight=240 g.
similarly For blend rich: upper limit is guided by K=60 so N=60 & P=30
gross weight=150 g
above are the right choices.
25 Dec 2025, 06:32
Kudos
Bookmarks
Blend Green (N : P : K = 3 : 2 : 1)
Total parts = 3+2+1=6
Per 6 g of blend: N = 3 g P = 2 g K = 1 g
We need to check now how many such sets inventory allows: N: 120/3 = 40
P: 90/2 = 45
K: 60/1 = 60
Limiting nutrient = Nitrogen => 40 sets
Total blend: 40x6 = 240 g
Blend Rich (N : P : K = 2 : 1 : 2)
Total parts = 2+1+2=5
Per 5 g of blend: N = 2 g P = 1 g
K = 2 g
Checking limits: N: 120/2=60
P: 90/1=90 K: 60/2=30
Limiting nutrient = Potassium
=> 30 sets
Total blend: 30 x 5 = 150
Total parts = 3+2+1=6
Per 6 g of blend: N = 3 g P = 2 g K = 1 g
We need to check now how many such sets inventory allows: N: 120/3 = 40
P: 90/2 = 45
K: 60/1 = 60
Limiting nutrient = Nitrogen => 40 sets
Total blend: 40x6 = 240 g
Blend Rich (N : P : K = 2 : 1 : 2)
Total parts = 2+1+2=5
Per 5 g of blend: N = 2 g P = 1 g
K = 2 g
Checking limits: N: 120/2=60
P: 90/1=90 K: 60/2=30
Limiting nutrient = Potassium
=> 30 sets
Total blend: 30 x 5 = 150
Bunuel
25 Dec 2025, 06:47
Kudos
Bookmarks
Blend green
3:2:1
amounts be N=3x, P=2x, K=1x
x<120/3=40
x<90/2=45
x<60/1=60
Xmax=40
6x=6x40=240 grams
Blend rich
2:1:2
N=2y, P=1y, K=2y
y<120/2=60
y<90/1=90
y<60/2=30
total blend= 5y, 5x30=150 grams
3:2:1
amounts be N=3x, P=2x, K=1x
x<120/3=40
x<90/2=45
x<60/1=60
Xmax=40
6x=6x40=240 grams
Blend rich
2:1:2
N=2y, P=1y, K=2y
y<120/2=60
y<90/1=90
y<60/2=30
total blend= 5y, 5x30=150 grams
