Last visit was: 20 Apr 2026, 19:16 It is currently 20 Apr 2026, 19:16
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
forestmayank
Joined: 05 Nov 2025
Last visit: 31 Mar 2026
Posts: 103
Own Kudos:
87
 [1]
Given Kudos: 6
Posts: 103
Kudos: 87
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Reon
Joined: 16 Sep 2025
Last visit: 28 Mar 2026
Posts: 134
Own Kudos:
121
 [1]
Given Kudos: 4
Posts: 134
Kudos: 121
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
linnet
Joined: 11 Dec 2025
Last visit: 22 Jan 2026
Posts: 81
Own Kudos:
42
 [1]
Given Kudos: 1
Posts: 81
Kudos: 42
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Mardee
Joined: 22 Nov 2022
Last visit: 02 Feb 2026
Posts: 225
Own Kudos:
191
 [1]
Given Kudos: 20
Posts: 225
Kudos: 191
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
We are told that,
We need GCD of 2 different positive integers which are less than 213
Neither is even and both are odd

Lets say,
One of the number is x and since even integers arent allowed, it should be an odd multiple of x
=> First number = x and Second number = 3x,5x,7x,...

To get max value of GCD, we want larget value x such that x and 3x here should be < 213

=> 3x < 213
=> x < 71
=> x <= 70

Since even number not allowed
x = 69
=> 3x = 207

Next odd number is 71, where its 3rd multiple is not less than 213, so its not possible
Therefore 69 is the valid answer here

A. 69
User avatar
msignatius
Joined: 28 Aug 2025
Last visit: 09 Apr 2026
Posts: 131
Own Kudos:
98
 [1]
Given Kudos: 31
Location: India
Concentration: Strategy, Marketing
GMAT Focus 1: 705 Q86 V85 DI84
GPA: 3.5
WE:Marketing (Consulting)
Products:
GMAT Focus 1: 705 Q86 V85 DI84
Posts: 131
Kudos: 98
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I really liked this one because it can be solved using just logic, so I will spare you of any algebra :)

We have:

The greatest possible common divisor of two different positive integers, each less than 213, neither of them even, is:

I've marked a few words as they're key to finding the answer.

We need to find the greatest common divisor - or common factor - of two unique positive integers. Each is less than 213 - so the largest of these numbers can be 212, but even that isn't the case, because none of the numbers can be even.

Now, this clearly means, if it's two odd numbers we are dealing with that have a large-ish common divisor, we need to find the smallest number that'll divide them together into an integer. An odd number will never divide by 2, so 3 is the next one, so we'll look for a multiple to 3 to start with.

Now, here's the thing. Whenever we're looking for factors of an odd number divisible by 3 - for instance, 801 - we'll never have a factor that's anything more than a third of this number (which is 267 in this case).

So, the first thing we realize when we look at the odd numbers less than 213 is, no matter whichever it is, we'll have to go at least a third of that number to find a number with which a large common divisor will be present.

Among the answer choices, you can clearly see that numbers like 209, 207, and 105 won't be common divisors, clearly because 3x of those numbers take things well out of the range.

B, 71, is the trick answer - as 71 is 1/3rd of 213, and we are only allowed positive integers less than 213.

Hence, A is the only possible solution. 69 is the greatest possible common divisor for two numbers under 213 - 207 and 69 itself.






Bunuel
What is the greatest possible common divisor of two different positive integers, each less than 213, if neither of them is even?

A. 69
B. 71
C. 105
D. 207
E. 209

Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
User avatar
Vaishbab
Joined: 29 Jan 2023
Last visit: 08 Mar 2026
Posts: 115
Own Kudos:
51
 [1]
Given Kudos: 81
Location: India
Concentration: Strategy, Operations
Posts: 115
Kudos: 51
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I answered this by finding the multiples of each of the options provided.

It should have at least 2 odd multiples lesser than 213.

For C, D & E, there are no odd multiples lesser than 213 other than themselves

For 71, we have 71 itself and the next odd multiple is 213. But that's not lesser than 213.

That leaves us with 69, for which we have 69 and then (69*3) = 207 => lesser than 213 and hence, I pick (A)
User avatar
sanjitscorps18
Joined: 26 Jan 2019
Last visit: 03 Mar 2026
Posts: 723
Own Kudos:
739
 [1]
Given Kudos: 130
Location: India
Schools: IMD'26
Products:
Schools: IMD'26
Posts: 723
Kudos: 739
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Greatest possible common divisor for two different integers less than 213. Both are odd

This could be the case when one of the numbers is the GCD. We cannot have the smaller number as half since then greater number cannot be even. Odd * Odd = Odd. We can try thirds or three times the numbers given as the first choice

1) 69
If GCD is 69 then the other number can be 69*3 = 207
This is a valid possibility

2) 71
if 71 is GCD then the other number can be 71*3 = 213. Not possible as both numbers are below 213

3) 105
We cannot double 105.
We cannot half 105. We can do a third of 105 which is 35. But this is less than 69 so ignoring.

4) 207
We have already encountered 207 with option A, Since the numbers are different, the other number has to be a factor of 207. 69 is the greatest GCD possible as halving is not an option.

5) 209
The largest different number dividing 209 is 19 and that is less than 69.

Option A

Bunuel
What is the greatest possible common divisor of two different positive integers, each less than 213, if neither of them is even?

A. 69
B. 71
C. 105
D. 207
E. 209

Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
User avatar
dolortempore
Joined: 15 Aug 2025
Last visit: 22 Jan 2026
Posts: 47
Own Kudos:
44
 [1]
Given Kudos: 9
Posts: 47
Kudos: 44
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The GCD for 2 different number less than 213 and not even.

We might think like numbers are
211, 209, 207.....

So if we look at 211,209 both don't have any divisor.
But 207
has 69...

Now, the logic is
if there is any number then we cannot count multiple by 2 as it will be even so number must be odd multiple with odd number.

Now for highest number multiple by 1 and 3 should give us the maximum divisor

Now multiple of 3 with 69 can go as close as to 213 and 69 itself

Hence 69 is the possible greatest common divisor.

Hence (A)
User avatar
bhanu29
Joined: 02 Oct 2024
Last visit: 20 Apr 2026
Posts: 358
Own Kudos:
267
 [1]
Given Kudos: 262
Location: India
GMAT Focus 1: 675 Q87 V85 DI79
GMAT Focus 2: 715 Q87 V84 DI86
GPA: 9.11
WE:Engineering (Technology)
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
What is the greatest possible common divisor of two different positive integers, each less than 213, if neither of them is even?

A. 69
B. 71
C. 105
D. 207
E. 209

Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
Try options:

if GCD is 209 we cant have two numbers less than 213. Eliminate.
same reasoning for 207

For 105, multiples less than 213 are 105 and 210 but 210 i even. Eliminate

For 71, Multiples ae 71, 142, 213, odd numbers 71, 213 but 213 is equal to the limit. Eliminate

For 69, Multiples are 69, 138, 207, 69, 207 are odd and less than 213.

Correct Answer: E
User avatar
redandme21
Joined: 14 Dec 2025
Last visit: 05 Jan 2026
Posts: 97
Own Kudos:
87
 [1]
Posts: 97
Kudos: 87
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If the two positive integers must be odd, then multiples of the GCD must be GCD*1 and GCD*3.

Checking the options:
69: multiples 69 and 69*3 = 207<213 -> correct

71: multiples 71 and 71*3 = 213 (that it's not <213) -> incorrect

The other options only contain one odd multiple less than 213.

IMO A
User avatar
gemministorm
Joined: 26 May 2025
Last visit: 19 Apr 2026
Posts: 143
Own Kudos:
110
 [1]
Given Kudos: 57
GMAT Focus 1: 565 Q82 V79 DI73
GMAT Focus 2: 605 Q84 V83 DI73
GMAT Focus 2: 605 Q84 V83 DI73
Posts: 143
Kudos: 110
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
greatest common divisor of 2 odd numbers less than 213...
let's go option by option:
209 -> 209 (odd + < 213) but no other multiple of 209 possible hence no.
207 -> similar to 209 hence no
105 -> 105 (odd + < 213), 105*2 = 210 (even hence no) no other number hence no
71 -> 71 (odd + < 213), 2*71 (will become even hence no), 3*71 (213 = 213) hence no
69 -> 69 (odd + < 213), 207 (odd + < 213) hence yes
User avatar
geocircle
Joined: 14 Dec 2025
Last visit: 27 Dec 2025
Posts: 90
Own Kudos:
87
 [1]
Posts: 90
Kudos: 87
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Multiples of the greatest common divisor are GCD x 1, GCD x 2, GCD x 3, GCD x 4, GCD x 5...
Not even (odd) multiples of the greatest common divisor are GCD x 1, GCD x 3, GCD x 5...
As there are two numbers, multiples are GCD x 1 and GCD x 3.

If the two numbers must be less than 213, then GCD x 3 must be less than 213

GCD x 3 < 213
GCD < 71

Only 69 fits.

Answer A
User avatar
canopyinthecity
Joined: 12 Jul 2025
Last visit: 17 Apr 2026
Posts: 91
Own Kudos:
61
 [1]
Given Kudos: 19
Posts: 91
Kudos: 61
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The two numbers must be of the form x and 3x where x would be GCD, given the question.

213/3 =71
The x should be less than 71
Hence (A) 69 is the answer
User avatar
MANASH94
Joined: 25 Jun 2025
Last visit: 11 Apr 2026
Posts: 88
Own Kudos:
63
 [1]
Given Kudos: 16
Location: India
Schools: IIM IIM ISB
GPA: 2.9
Schools: IIM IIM ISB
Posts: 88
Kudos: 63
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let the GCD be d.
Then the two numbers must be d and at least 3d (since 2d would be even, which is not allowed).
Also, 3d<213=> d<71.
Now checking options below 71: 71 (Seems incorrect) (too large)
69 (Seems a viable option) (3×69=207<213, both odd)
Larger options will be incorrect because they can’t produce two different odd multiples below 213.

Hence Answer should be A.

Bunuel
What is the greatest possible common divisor of two different positive integers, each less than 213, if neither of them is even?

A. 69
B. 71
C. 105
D. 207
E. 209

Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
User avatar
topgmat25
Joined: 15 Dec 2025
Last visit: 05 Jan 2026
Posts: 90
Own Kudos:
87
 [1]
Posts: 90
Kudos: 87
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
d = greatest common divisor

The two numbers are a*d and b*d where the greatest common divisor of a and b is 1.
d will be greater if a and b are as small as possible.
Numbers must be odd, so a and b must be odd.
a and b must be 1 and 3.

b*d=3d that must be less than 213

3d<213
d<71

d must be 69

The answer is A
User avatar
firefox300
Joined: 15 Dec 2025
Last visit: 27 Dec 2025
Posts: 90
Own Kudos:
87
 [1]
Posts: 90
Kudos: 87
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Choosing the first two odd multiples of the options we get the answer.

The first two odd multiples of 209: 209, 627 -> not possible as only 209 is less than 213
The first two odd multiples of 207: 207, 621 -> not possible as only 207 is less than 213
The first two odd multiples of 105: 105, 315 -> not possible as only 105 is less than 213
The first two odd multiples of 71: 71, 213 -> not possible as only 71 is less than 213
The first two odd multiples of 69: 69, 207 -> possible

And 69 is the greatest possible common divisor because the next odd number, 71, is not possible.

The correct answer is A
User avatar
adityaprateek15
Joined: 26 May 2023
Last visit: 18 Apr 2026
Posts: 346
Own Kudos:
170
 [1]
Given Kudos: 323
Location: India
GPA: 2.7
Products:
Posts: 346
Kudos: 170
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If two numbers have GCD = d then the numbers could be d and 2d or higher than 2d

and2d (or higher multiples)
To maximize dd:
Both numbers must be < 213
Both numbers must be odd
The numbers must be different
Since the numbers must be odd:
d must be odd
the multiple must also be odd, so,the other number cannot be 2d
The next higher number is 3d
thus: 3d<213 => d<71

So the maximum possible GCD is 69.
[*]

Bunuel
What is the greatest possible common divisor of two different positive integers, each less than 213, if neither of them is even?

A. 69
B. 71
C. 105
D. 207
E. 209

Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
User avatar
rahumangal
Joined: 20 Nov 2022
Last visit: 07 Apr 2026
Posts: 71
Own Kudos:
66
 [1]
Given Kudos: 316
Location: India
Concentration: Finance, Real Estate
GPA: 3.99
WE:Engineering (Technology)
Products:
Posts: 71
Kudos: 66
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
What is the greatest possible common divisor of two different positive integers, each less than 213, if neither of them is even?

A. 69
B. 71
C. 105
D. 207
E. 209

Gift
12 Days of Christmas Competition
This question is part of our holiday event
Win $40,000 in prizes: courses, tests, and more
it is a fairly straight forward question which we can siolve by options
if the given option are the greatest common diviser then the nos will be its multiple, lets multiply each divisor with odd multiples and see if its below 213 ,in case if two nos gives multiples below 213 then we will see which gives nos as multiple closest to 213 and largest
A- 69 x1=69 ----ok
69x3=207
on checking we can see that no other divisor will give odd multiple less tha 213 and closest to 213 as 207
Ans=A
User avatar
whollyshiv
Joined: 11 Aug 2024
Last visit: 20 Apr 2026
Posts: 22
Own Kudos:
16
 [1]
Given Kudos: 8
GMAT Focus 1: 575 Q78 V82 DI75
GMAT Focus 1: 575 Q78 V82 DI75
Posts: 22
Kudos: 16
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Since both integers are odd, their GCD must also be odd

If GCD is x, then the two numbers could be x and 3x or any two odd multiples of x

3x < 213
=> x < 71

Hence, the two numbers are, from the options, 69 and 69x3 = 207
   1   2   3 
Moderators:
Math Expert
109701 posts
Tuck School Moderator
853 posts