Myrna’s Observations:
a+b=c (first two digits sum to the third digit).
d+e=c (last two digits also sum to the third digit).
Deon’s Observations:
c (the third digit) is a factor of:
10a+b (two-digit number formed by the first two digits).
10d+e (two-digit number formed by the last two digits).
Kermit’s Observations:
The values of the digits increase from a to c and then decrease from c to e.
All digits are unique.
Available Options for d and e:
Fourth digit (d): 0,3,4,5,7,8.
Fifth digit (e): 0,3,4,5,7,8.
Step 1: Determine c (the third digit).
c must be between 1 and 9, and both
a+b=c and d+e=c must hold.
c>a,b,d,e, since the digits increase to c and decrease afterward.
Let’s test possible values for c.
If c=8:
d+e=8.
Possible pairs are: (d,e)=(5,3),(4,4),(7,1).
Among these, only (d,e)=(5,3) fits the decreasing sequence (c>d>e).
d=5, e=3.
If c=7:
d+e=7.
Possible pairs are:(d,e)=(4,3),(5,2).
Among these, (d,e)=(4,3) fits the decreasing sequence (c>d>e).
d=4, e=3.
If c=6:
d+e=6.
Possible pairs are:(d,e)=(5,1),(4,2),(3,3).
Among these, (d,e)=(5,1) fits the decreasing sequence (c>d>e).
d=5, e=1.
Step 2: Eliminate invalid pairs based on options.
From the available options for d and e (fourth and fifth digits): 0,3,4,5,7,8.
(d,e)=(5,3): Valid.
(d,e)=(4,3): Valid.
(d,e)=(5,1): Invalid (1 is not an option).
Step 3: Cross-check all observations.
For (d,e)=(5,3),
c=8:
a+b=8, so a,b could be (3,5) or (2,6).
c=8 is a factor of 10a+b (e.g., 35 or 26):
35mod8=3: Invalid.
26mod8=2: Invalid.
For (d,e)=(4,3),
c=7: a+b=7, so a,b could be (3,4) or (2,5).
c=7 is a factor of 10a+b (e.g., 34 or 25):
34mod7=6: Invalid.
25mod7=4: Invalid.
Thus, (d, e) = (5, 3) fits best.
Final Answer:
Fourth digit: 5
Fifth digit: 3