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121^(1/2) - 99^(1/2) - 44^(1/2) =

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121^(1/2) - 99^(1/2) - 44^(1/2) =  [#permalink]

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New post 03 Sep 2017, 06:08
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

76% (00:58) correct 24% (01:02) wrong based on 106 sessions

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Re: 121^(1/2) - 99^(1/2) - 44^(1/2) =  [#permalink]

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New post 03 Sep 2017, 06:15
121^(1/2) - 99^(1/2) - 44^(1/2)
= 11 - (9*11)^(1/2)-(4*11)^(1/2)
= 11- 3^(1/2)-2^(1/2)
=11-5^(1/2)

Answer : D
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Re: 121^(1/2) - 99^(1/2) - 44^(1/2) =  [#permalink]

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New post 03 Sep 2017, 07:16
1
Bunuel wrote:
\(\sqrt{121} - \sqrt{99}- \sqrt{44}=\)


A. -44

B. -5

C. 1/2

D. \(11-5\sqrt{11}\)

E. \(11-\sqrt{11}\)

\(\sqrt{121} - \sqrt{99}- \sqrt{44}\)

\(11 - \sqrt{9*11}- \sqrt{4*11}\)

\(11 - 3\sqrt{11}- 2\sqrt{11}\)

\(11 - \sqrt{11} (3 + 2)\)

\(11 - 5\sqrt{11}\)

Answer (D)...
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121^(1/2) - 99^(1/2) - 44^(1/2) =  [#permalink]

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New post 03 Sep 2017, 07:48
We have been asked to find the value of the expression \(\sqrt{121} - \sqrt{99}- \sqrt{44}\)

Taking out \(\sqrt{11}\) common in the expression, we get

\(\sqrt{11}(\sqrt{11} - \sqrt{9}- \sqrt{4})\) = \(\sqrt{11}(\sqrt{11} - \sqrt{9}- \sqrt{4})\) = \(\sqrt{11}(\sqrt{11} - 3 - 2)\) = \(\sqrt{11}(\sqrt{11} -5)\) = \(11-5\sqrt{11}\)(Option D)
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Re: 121^(1/2) - 99^(1/2) - 44^(1/2) =  [#permalink]

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New post 03 Sep 2017, 10:56
Bunuel wrote:
\(\sqrt{121} - \sqrt{99}- \sqrt{44}=\)


A. -44

B. -5

C. 1/2

D. \(11-5\sqrt{11}\)

E. \(11-\sqrt{11}\)



\(\sqrt{121} - \sqrt{99}- \sqrt{44}\)
\(=11 - 3\sqrt{11}- 2\sqrt{11}\)
\(=11 - 5\sqrt{11}\)

Answer D
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Re: 121^(1/2) - 99^(1/2) - 44^(1/2) =   [#permalink] 03 Sep 2017, 10:56
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