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55 people live in an apartment complex with three fitness

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55 people live in an apartment complex with three fitness  [#permalink]

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New post Updated on: 15 Apr 2013, 06:36
3
17
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

48% (02:21) correct 52% (02:17) wrong based on 555 sessions

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55 people live in an apartment complex with three fitness clubs (A, B, and C). Of the 55 residents, 40 residents are members of exactly one of the three fitness clubs in the complex. Are any of the 55 residents members of both fitness clubs A and C but not members of fitness club B?

(1) 2 of the 55 residents are members of all three of the fitness clubs in the apartment complex.
(2) 8 of the 55 residents are members of fitness club B and exactly one other fitness club in the apartment complex.

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Originally posted by Tagger on 14 Apr 2013, 16:17.
Last edited by Tagger on 15 Apr 2013, 06:36, edited 2 times in total.
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Re: 55 people live in an apartment complex with three fitness cl  [#permalink]

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New post Updated on: 15 Apr 2013, 05:47
5
5
We know that 55-40 people are numbers of 2 or more clubs.
Lets call a the members of only AC, b the members of only AB, c the members of only CB and d the members of all three. And consider n that are the members of none of those clubs!
\(n+a+b+c+d=15\)
Now the question is: is a >0? there are members in AC only?

1) tells us that d=2. We cannot say anything about a
\(m+a+b+2=15\)
2)tells us that b+c=8.Again not sufficient
\(n+a+8+d=15\)

1+2)\(n+a+8+2=15\) We cannot say anything about A.
E
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Originally posted by Zarrolou on 14 Apr 2013, 22:05.
Last edited by Zarrolou on 15 Apr 2013, 05:47, edited 1 time in total.
Edited: thanks Transcendentalist
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Re: 55 people live in an apartment complex with three fitness cl  [#permalink]

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New post 14 Apr 2013, 18:55
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1
2
Answer is C

I would use the 3 overlapping sets formula to evaluate whether the stat 1 and 2 are sufficient.

Total people = people enrolled in A + people enrolled in B + people enrolled in C - (people enrolled in A & B only + people enrolled in B & C only + people enrolled in A &C only ) - 2 (people enrolled in A, B, and C).

Equation based on question stem :

55 = 40 - (people enrolled in A & B only + people enrolled in B & C only + people enrolled in A &C only ) - 2 (people enrolled in A, B, and C).

Stmt 1 gives only 2 (people enrolled in A, B, and C) - Not Sufficient

Stmt 2 gives only (people enrolled in A & B only + people enrolled in B & C only + people enrolled in A &C only ) - Not Sufficient

Considering Stmt 1 and Stmt 2 people enrolled in A &C only can be calculated.

//kudos please, if above explanation is good
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Re: 55 people live in an apartment complex with three fitness cl  [#permalink]

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New post 15 Apr 2013, 05:38
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The question does not specify if there are people not member of any clubs. So isn't E a possibility as well?

Assume there are 5 people not a part of any club
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Re: 55 people live in an apartment complex with three fitness cl  [#permalink]

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New post 15 Apr 2013, 05:46
Transcendentalist wrote:
The question does not specify if there are people not member of any clubs. So isn't E a possibility as well?

Assume there are 5 people not a part of any club


Indeed my friend, you are right. The question written as it is has E as answer
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55 people live in an apartment complex with three fitness  [#permalink]

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New post 21 Aug 2015, 10:58
Tagger wrote:
55 people live in an apartment complex with three fitness clubs (A, B, and C). Of the 55 residents, 40 residents are members of exactly one of the three fitness clubs in the complex. Are any of the 55 residents members of both fitness clubs A and C but not members of fitness club B?

(1) 2 of the 55 residents are members of all three of the fitness clubs in the apartment complex.
(2) 8 of the 55 residents are members of fitness club B and exactly one other fitness club in the apartment complex.


Ans - D

(since the question does not mention that "every resident belongs to at least one fitness club")

Had the question included the above condition the answer would've been an easy C.

That's the beauty of GMAT math questions. It not only checks one's ability to solve a question but also his/her ability of analyzing the question.
As they say, on good math question on GMAT will also check your verbal skills! :)

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Re: 55 people live in an apartment complex with three fitness  [#permalink]

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New post 03 Apr 2017, 11:36
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Tagger wrote:
55 people live in an apartment complex with three fitness clubs (A, B, and C). Of the 55 residents, 40 residents are members of exactly one of the three fitness clubs in the complex. Are any of the 55 residents members of both fitness clubs A and C but not members of fitness club B?

(1) 2 of the 55 residents are members of all three of the fitness clubs in the apartment complex.
(2) 8 of the 55 residents are members of fitness club B and exactly one other fitness club in the apartment complex.



Can anybody please explain the second statement with a venn diagram ?
What does the bold part means in venn diagram? 8 of the 55 residents are members of fitness club B and exactly one other fitness club in the apartment complex

Thanks..
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Re: 55 people live in an apartment complex with three fitness  [#permalink]

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New post 17 Oct 2018, 00:30
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: 55 people live in an apartment complex with three fitness   [#permalink] 17 Oct 2018, 00:30
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