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vcbabu
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Hello vcbabu ,

Could you please let meknow the source.
It will be interesting to check if OA is not E.
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Bunuel
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One more for D or I'm missing something.
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we just require to know who purchased more roses as the total no of flowers is same....
and both sentences provide ans to that ...so D
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agree with D, only if total was not constant we shud find num of daisy
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I guess it's E.

None of the options mention Daisies .. so we can only get the cost of roses. Without knowing the cost of daisies we can't tell who paid more.
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pleonasm
I guess it's E.

None of the options mention Daisies .. so we can only get the cost of roses. Without knowing the cost of daisies we can't tell who paid more.

A and B bought same number of flowers, including rose and daisy. If rose is $1 each and daisy is $0.5 each. Did A cost more than B?
1). Roses A bought is twice as many as that B bought.
2). A bought 4 more rose than B

Have we to know cost of the daisies? Since we know that 1. A bought more roses in both cases; 2. the roses cost more than daisies and 3. they bought same number of flowers, doesn't it mean that A paid more than B?

I still think it's D, or I somehow misunderstood the question...
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Let no of roses A bought = R1
no of daisy A bought = D1

no of roses B bought = R2
no of daisy B bought = D2

Given, R1 + D1 = R2 + D2 - 1st
we need to find, is \(R1*1 + D1*0.5 > R2*1 + D2*0.5\)

1.) R1 = 2R2

=> using 1st
=> R2 + D1 = D2
=> D1 = D2 - R2
therefore, \(R1*1 + D1*0.5\) = 2R2 + \(\frac{(D2 -R2)}{2}\)
=> \(\frac{(4R2 + D2 - R2)}{2}\)
=> \(\frac{(3R2 + D2)}{2}\) which is greater than \(R2*1 + D2*0.5\)
Hence, sufficient.

2.) R1 = R2 + 4
=> using 1st
=> R2 + 4 +D1 = D2 + R2
=> D1 = D2 - 4
therefore, \(R1*1 + D1*0.5\) = R2 + 4 + \(\frac{(D2 - 4)}{2}\)
=> \(\frac{(2R2 + 8 + D2 -4)}{2}\)
=> R2 + \(\frac{D2}{2}\) + 2 which is greater than \(R2*1 + D2*0.5\)
Hence, sufficient.

hence, D
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A and B bought same number of flowers, including rose and daisy. If rose is $1 each and daisy is $0.5 each. Did A cost more than B?
1). Roses A bought is twice as many as that B bought.
2). A bought 4 more rose than B

Let no of flowers bought by each be a and b resp..

given: a=b; roses (r)=1 and daisies(d)= 0.5
let a=b=10

it can be understood that the cost will be higher for the one who purchases more roses.

st 1: it clearly mentions that A will buy higher no. of roses so the cost will be higher for A.
For eg: a=b=10 then possible no of roses a can buy is 2,4,6,8,10 and correspondinly no of roses B can get in 1,2,3,4,5... hence, this is suff to say tht A's cost is higher.

st 2: again, this st says that no of roses A purchases is higher. So A's set of flowers can have any of the following no of roses i.e. 4,5,6,7,8,9,10 and correspondingly the no. of roses B will have is 1,2,3,4,5,6. Under any of the above cases, the cost of bunch bought by A will be higher.

I go with D....
Pls explain the OA
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meenal8284
A and B bought same number of flowers, including rose and daisy. If rose is $1 each and daisy is $0.5 each. Did A cost more than B?
1). Roses A bought is twice as many as that B bought.
2). A bought 4 more rose than B

Let no of flowers bought by each be a and b resp..

given: a=b; roses (r)=1 and daisies(d)= 0.5
let a=b=10

it can be understood that the cost will be higher for the one who purchases more roses.

st 1: it clearly mentions that A will buy higher no. of roses so the cost will be higher for A.
For eg: a=b=10 then possible no of roses a can buy is 2,4,6,8,10 and correspondinly no of roses B can get in 1,2,3,4,5... hence, this is suff to say tht A's cost is higher.

st 2: again, this st says that no of roses A purchases is higher. So A's set of flowers can have any of the following no of roses i.e. 4,5,6,7,8,9,10 and correspondingly the no. of roses B will have is 1,2,3,4,5,6. Under any of the above cases, the cost of bunch bought by A will be higher.

I go with D....
Pls explain the OA

Yup makes sense. I didn't read the 'same number of flowers' part.
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IMO D.

Here the total numer of flowers are equal. Had all the flowers been daisy, A and B would have paid the same amount. But as rose costs .5 $ more than daisy, so whoever buys more roses, pays more.

Both 1 and 2 indicate that A buys more roses than B does. So, each statement is sufficient.
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D for me, all you need to know is which has more roses...? right?
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vcbabu
A and B bought same number of flowers, including rose and daisy. If rose is $1 each and daisy is $0.5 each. Did A cost more than B?
1). Roses A bought is twice as many as that B bought.
2). A bought 4 more rose than B

Got D

Q gives : Ra+Da=Rb+Db; Cr=$1; Cd=$0.5

St(1) gives Ra=2Rb
Ta=Cr.Ra+Cd.Da
=$1.2.Rb+$0.5.Db-Rb
=$1.5.Rb+$0.5.Db
Tb=Cr.Rb+Cd.Db
=$1.Rb+$0.5.Db
Ta>Tb -->suff
St(2) gives Ra=Rb+4, same pathway, concl.Ta>Tb -->suff

Hence D
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Since the total no.of flowers are same. person who is buying more rose than the other one will have shed more,since the cost of rose is double that of daisy.

Statement 1: A bought more rose than B.suff

Statement 2 : A bought more rose than B.Suff

so I wud go with option D



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