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01 Jun 2020, 06:28
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D
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Difficulty:
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A and B started walking simultaneously in the same direction from a point on a circular track. The time taken by them to meet for the first time was five times the time that they would have taken to meet for the first time had they started walking in opposite directions. If A's speed was less than that of B's, and the speed of A was 12 km/hr, what was the speed of B?
A. 18 m/s
B. 12 m/s
C. 8 m/s
D. 5 m/s
E. 4 m/s
Are You Up For the Challenge: 700 Level Questions
A. 18 m/s
B. 12 m/s
C. 8 m/s
D. 5 m/s
E. 4 m/s
Are You Up For the Challenge: 700 Level Questions
Updated on: 01 Jun 2020, 07:12
Originally posted by GMATinsight on 01 Jun 2020, 06:48.
Last edited by GMATinsight on 01 Jun 2020, 07:12, edited 1 time in total.
Last edited by GMATinsight on 01 Jun 2020, 07:12, edited 1 time in total.
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Bunuel
Suppose their speeds are b and a
Relative speed in same direction = b-a
Relative speed in Opposite direction = b+a
Let, length fo circular track = D
\(Time = \frac{Distance }{ Speed}\)
\(\frac{D}{(b-a)} = \frac{5D}{(b+a)}\)
i.e. a+b = 5b - 5a
i.e. 6a = 4b
i.e. b = 1.5a
a = 12 kmph
i.e. b = 18 kmph
i.e. b = 18*1000/3600 = 5 m/s
Answer: Option D
General Discussion
01 Jun 2020, 06:55
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let speed of A = a and speed of B = b
total distance = x
when in same direction total time would be
x/a-b and
when in opposite direction total time ; x/a+b
given a = 12 kmph or say 12 * 5/18 ; 3.3 mps
so
x/b-a = 5x/a+b
we get
a+b=5b-5a
6a=4b
3a=2b
3*3.3=2b
b= 5 m/s ;
OPTION D
total distance = x
when in same direction total time would be
x/a-b and
when in opposite direction total time ; x/a+b
given a = 12 kmph or say 12 * 5/18 ; 3.3 mps
so
x/b-a = 5x/a+b
we get
a+b=5b-5a
6a=4b
3a=2b
3*3.3=2b
b= 5 m/s ;
OPTION D
Bunuel
