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12 Oct 2022, 01:30
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D
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Difficulty:
85%
(hard)
Question Stats:
55% (02:24) correct
45%
(02:30)
wrong
based on 278
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A car manufacturer, tripled the price of a car and by this quadrupled percentage of profit on it. What was the original profit percentage on the car ?
A. \(33 \frac{1}{3}\%\)
B. \(66 \frac{2}{3}\%\)
C. \(100\%\)
D. \(200\%\)
E. \(6666 \frac{2}{3}\%\)
A. \(33 \frac{1}{3}\%\)
B. \(66 \frac{2}{3}\%\)
C. \(100\%\)
D. \(200\%\)
E. \(6666 \frac{2}{3}\%\)
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12 Oct 2022, 04:26
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D. 200%
let x be the profit percentage
S.P = (1 + x/100)*C.P ... eq 1
3*S.P = (1 + 4x/100)*C.P ... eq 2
put eq 1 in eq 2
= 3*(1 + x/100) = (1 + 4x/100)
= 3 + 3x/100 = 1 + 4x/100
= 2 = (4x/100) - (3x/100)
= 2 = x/100
= x = 200
let x be the profit percentage
S.P = (1 + x/100)*C.P ... eq 1
3*S.P = (1 + 4x/100)*C.P ... eq 2
put eq 1 in eq 2
= 3*(1 + x/100) = (1 + 4x/100)
= 3 + 3x/100 = 1 + 4x/100
= 2 = (4x/100) - (3x/100)
= 2 = x/100
= x = 200
rajtare
Joined: 05 Nov 2014
Last visit: 17 Nov 2025
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Location: India
Concentration: Operations, Leadership
Schools: Sloan '26 Columbia CBS'26 Goizueta '26 Kellogg '26
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12 Oct 2022, 05:24
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Bunuel
let selling price =x
and cost price =y
profit% = ((selling price - cost price)/Cost price)*100
profit before price increase = ((x-y)/y)*100
after selling price becomes 3x, new profit becomes 4 times the old profit
i.e. (3x-y/y)*100 = 4(x-y/y)*100
3x-y =4x-4y
or x=3y
thus original profit was ((x-y)/y)*100
= ((3y-y)/y)*100
=200%
Option D
