AryamaDuttaSaikia wrote:

Answer : D

Is C<200?

Area of each conference room = C

Area of each rectangular office (considering "Equal") = R

C>R

2C + 6R = 1200

S1 -

C>2R

Even if we take C= 2R, R= 120 , Since we know C>2R, then C>240. Sufficient.

S2-

2 (l+b) < 46

l+b<23

Maximum value could be l=12 , b=11

so, lb= 132 (maximum area of the rectangle)

2C+6*132=1200

C=204 (>200)

Sufficient.

statement 2: fixes the perimeter= 46= 2(L + B) which means L + B= 23, however it doesn't mention that the sides have to be integers. as you have taken values 12,11 , to prove that C > 200, there can also be values like 12.9,10.1 which gives area of office 140.61=R and area of conference room=178.17=C<200 ,thus making statement 2 insufficient