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A company has two types of machines, type R and type S

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A company has two types of machines, type R and type S  [#permalink]

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New post 02 Apr 2012, 13:55
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A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 36 hrs and a machine of type S does the same job in 18 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?

A. 3
B. 4
C. 6
D. 9
E. 12

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A company has two types of machines, type R and type S  [#permalink]

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New post 02 Apr 2012, 17:58
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enigma123 wrote:
A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 36 hrs and a machine of type S does the same job in 18 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?

A. 3
B. 4
C. 6
D. 9
E. 12


Rate of A - \(\frac{1}{36}\) job/hour, rate of x machines of A - \(\frac{1}{36}x\) job/hour;
Rate of B - \(\frac{1}{18}\) job/hour, rate of x machines of B - \(\frac{1}{18}x\) job/hour, (same number of each type);

Remember that we can sum the rates, hence combined rate of A and B is \(\frac{1}{36}x+\frac{1}{18}x=\frac{3}{36}x=\frac{1}{12}x\) job/hour.

We are told that together equal number (x in our case) of machines A and B can do the job (1 job) in 2 hours --> \(Time*Rate=2*\frac{1}{12}x=1=Job\) --> \(x=6\).

Answer: C.
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 08 Jan 2017, 00:55
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Clearly R does 1/3 of the work and S does 2/3 of the work.
The time taken is 2 hours.

Number of machines of type R required are therefore , 36*(1/3)*(1/2)= 6

Similarly of S was asked it would have been , 18*(2/3)*(1/2)=6
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 03 Apr 2012, 03:56
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After tearing my hair apart for 30 mins, saw Bunuels solution and realized the question is wrong. Its 18 not 8
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 03 Apr 2012, 06:49
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enigma123 wrote:
A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 36 hrs and a machine of type S does the same job in 18 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?

A. 3
B. 4
C. 6
D. 9
E. 12


Take total work as 360

R:
work : 360
time: 36hrs
rate: 10(calculaed)

S:
Work:360
time 18hrs
rate: 20( calculated)

together

given work:360
time2 hrs
calculated: 180
rate: 180/(10+20) = 180/30 = 6 each
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A company has two types of machines, type R and type S  [#permalink]

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New post 15 Aug 2012, 11:16
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above720 wrote:
Here is a work problem from GMATPrep, Practice Test 1:

A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 36 hours and a machine of type S does the same in job in 18 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?

a) 3
b) 4
c) 6
d) 9
e) 12


Machine R does a job in 36 Hours. Machine S in 18 Hours.
Together, the machines R & S can finish the job in \(\frac{(36*18)}{(36+18)}= 12 Hours\)
In other words,
1 machine of R + 1 machine of S can finish the job together in = 12 Hours

So, to finish the job in 2 Hours, company needs 6 machines of each type - Option C
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 15 Nov 2012, 05:53
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\(Let N be the number of machines...\)
\(\frac{N}{36}+\frac{N}{18}(2hours)=1\)
\(\frac{3N}{18}=1==>N=6\)

ANswer: 6 machines
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 10 Jan 2014, 10:24
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enigma123 wrote:
A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 36 hrs and a machine of type S does the same job in 18 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?

A. 3
B. 4
C. 6
D. 9
E. 12


2x/36 + 2x/18 = 1

x = 6

C
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 25 Nov 2014, 14:51
Could someone please clarify why the answer is not 3 each? I understand how to get to 6 machines and do it quickly but why isn't this 6 machines total since it is a combined rate?
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 26 Nov 2014, 05:15
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mns18051985 wrote:
Could someone please clarify why the answer is not 3 each? I understand how to get to 6 machines and do it quickly but why isn't this 6 machines total since it is a combined rate?


x in the solution HERE is the number of type R machines as well as the number of type S machines (we are told that the company used the same number of each type of machine to do the job ). So, when we solve for x, we get what we want.
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 26 Nov 2014, 06:01
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Rate of machine R =1/36
Rate of machine S =1/18

since same no of machines used for R and S to do the same work in 2 hrs
So collective rate needed to finish the work in 2 hrs= 1/2
Let the no of machine be x

So, x/36 +x/18 =1/2
x3/36=1/2
x=36/6=6

So no of machine R is 6

Answer C
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 26 Nov 2014, 21:30
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R finishes job in 36h and S does the same in 18h. So if both work together, the job will be done in 12h:
1/36 + 1/18 will give you 1/12.
Now if one pair of R & S finishes job in 12h, how many such pairs are needed to finish the same job in 2h?
12/2 = 6 pairs of R & S. Hence 6 of R machines are required.
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 10 Jan 2015, 12:23
Doubt....

1 machine A and 1 machine B together do 1/12 of the job in 1 hour.

We need to do 6/12 of the job in 1 hour...
So 6 A machines and 6 B machines will be needed for 6/12 job in 1 hour...
and 12 A and B machines will do 12/12 of the job in 2 hours...

Shouldn't the answer be E)12
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 11 Jan 2015, 11:47
gmathopeful90 wrote:
Doubt....

1 machine A and 1 machine B together do 1/12 of the job in 1 hour.

We need to do 6/12 of the job in 1 hour...
So 6 A machines and 6 B machines will be needed for 6/12 job in 1 hour...
and 12 A and B machines will do 12/12 of the job in 2 hours...

Shouldn't the answer be E)12


6 A's and 6 B's do half of the job in 1 hour, so 6 A's and 6 B's will do the whole job in 2 hour and this is what we are asked to find.
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 04 Nov 2016, 16:05
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enigma123 wrote:
A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 36 hrs and a machine of type S does the same job in 18 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?

A. 3
B. 4
C. 6
D. 9
E. 12


We have a combined worker problem for which we can use the following formula:

work (1 machine) + work (2 machine) = total work completed

Since we are completing one job, we can say:

work (1 machine) + work (2 machine) = 1

We are given that a machine of type R does a certain job in 36 hours and a machine of type S does the same job in 18 hours.

Thus, the rates for the two machines are as follows:

rate of machine R = 1/36

rate of machine S = 1/18

We are also given that the company used the same number of each type of machine to do the job in 2 hours. If we let x = the number of each machine used, we can multiply each rate by x and we have:

rate of x number of R machines = x/36

rate of x number of S machines = x/18

Finally, since we know some number of R and S machines worked for two hours, and since work = rate x time, we can calculate the work done by each type of machine.

work done by x number of R machines = 2x/36 = x/18

work done by x number of S machines = 2x/18 = x/9

Now we can determine x using the combined worker formula:

work (machine R) + work (machine S) = 1

x/18 + x/9 = 1

x/18 + 2x/18 = 1

3x/18 = 1

x/6 = 1

x = 6

Answer: C
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Work/Rate problem- A company has..  [#permalink]

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New post 01 Jan 2017, 07:10
A company has two types of machines, Type R and Type S. Operating at a certain rate, a machine of type R does a certain job in 36 hours and a machine of type S does the same job in 18 hours. If the company uses the same number of each type of machine to do the job in 2 hours, how many machines of Type R were used?

Options:
A. 3
B. 4
C. 6
D. 9
E. 12

Can anybody give me a quickest and simpler way to solve this? I took almost 3.5 min on this question to solve during a mock test. Still ended up guessing as I wasn't sure of the approach.
Thanks.
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Re: Work/Rate problem- A company has..  [#permalink]

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New post 01 Jan 2017, 07:47
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baalok88 wrote:
A company has two types of machines, Type R and Type S. Operating at a certain rate, a machine of type R does a certain job in 36 hours and a machine of type S does the same job in 18 hours. If the company uses the same number of each type of machine to do the job in 2 hours, how many machines of Type R were used?

Options:
A. 3
B. 4
C. 6
D. 9
E. 12

Can anybody give me a quickest and simpler way to solve this? I took almost 3.5 min on this question to solve during a mock test. Still ended up guessing as I wasn't sure of the approach.
Thanks.


We are given rates of each machine and that the number of machines of each type being used is the same = x.

\(\frac{x}{36} + \frac{x}{18} = \frac{1}{2}\)

\(\frac{3x}{36} = \frac{1}{2}\)

\(6x = 36\)

\(x = 6\)
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 07 Jan 2017, 22:07
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Rate(R) = \(\frac{1}{36}\)
Rate(S) = \(\frac{1}{18}\)
Combined rate of both machines ,
Rate(RS)=Rate(R) + Rate(S) = \(\frac{1}{12}\)

we have given time , T = 2hrs , Workdone = 1 (for single job)
Plug in the values :

[Rate] * [Time] * [No. of machines] = Workdone

\(\frac{1}{12}\) * 2 * [No. of machines] = 1
[No. of machines] = 6

Ans : C
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 13 Nov 2019, 06:16
\(2x(\frac{1}{36}+\frac{1}{18})=1 \implies x=6\)
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Re: A company has two types of machines, type R and type S  [#permalink]

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New post 08 Dec 2019, 20:54
Why is the total of Machine R used 6 and not 3?

I understand how to solve using the question Work = Rate x Time x Number.

I solved for each rate and then combined the rates to get Number = 6.

The questions states that the same number of Machine S and R is used. Why is 6 the number of one machine and not the total for both since we solved using combined rates of both machines?

1 = 1/36 + 1/18 x (2) x (N)

Please help!!
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Re: A company has two types of machines, type R and type S   [#permalink] 08 Dec 2019, 20:54

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