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# A computer retailer bought 5 computers each time and sold 3

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Current Student
Joined: 11 May 2008
Posts: 553
A computer retailer bought 5 computers each time and sold 3 [#permalink]

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28 Jul 2008, 01:47
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A computer retailer bought 5 computers each time and sold 3 computers each time, and each of these purchasing or selling is regard as a transaction. Last month, if the computers in stocks increased by 14, at least how many transactions were performed during last month?
A. 3
B. 5
C. 6
D. 7
E. 8
Manager
Joined: 18 Aug 2006
Posts: 61
Location: Houston TX

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28 Jul 2008, 02:05
My ans is C.
selling: 3*2=6
20-6=14
_________________

haveaniceday

Manager
Joined: 27 May 2008
Posts: 139

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28 Jul 2008, 03:46
My answer is C as well.
Senior Manager
Joined: 10 Mar 2008
Posts: 355

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28 Jul 2008, 04:05
Chan - could you please explain this part:

selling: 3*2=6

how did you get 4 and2?
Thanks!
Manager
Joined: 27 May 2008
Posts: 139

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28 Jul 2008, 06:17
vksunder wrote:
Chan - could you please explain this part:

selling: 3*2=6

how did you get 4 and2?
Thanks!

Try to do back solving.
Senior Manager
Joined: 19 Mar 2008
Posts: 351

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28 Jul 2008, 06:44
20 - 6 = 14

Purchased 20 needs 4 transactions
Sold 6 needs 2 transactions

So, total 6 transactions

C
Manager
Joined: 27 Mar 2008
Posts: 81

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28 Jul 2008, 07:21
Not fully understanding this...

If a computer retailer bought 5 computers each time and sold 3 computers each time, I read this as buying 5 and selling 3 in a single turnaround. Is that not correct? Can we just assume that he can buy in 5 blocks and sell in 3 blocks freely?
Manager
Joined: 18 Aug 2006
Posts: 61
Location: Houston TX

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28 Jul 2008, 11:39
vksunder wrote:
Chan - could you please explain this part:

selling: 3*2=6

how did you get 4 and2?
Thanks!

This is what I think:
In order to have the least transactions to increase 14 items, we need more buying than selling,
Step by step:
5*3=15, but 15-14=1 (not divisible by 3)
5*4=20, then 20-14= 6 (divisible by 3) *, so we have 6/3=2 selling
Hope it's clear
_________________

haveaniceday

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# A computer retailer bought 5 computers each time and sold 3

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