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A computer retailer bought 5 computers each time and sold 3

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A computer retailer bought 5 computers each time and sold 3 [#permalink]

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New post 28 Jul 2008, 02:47
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A computer retailer bought 5 computers each time and sold 3 computers each time, and each of these purchasing or selling is regard as a transaction. Last month, if the computers in stocks increased by 14, at least how many transactions were performed during last month?
A. 3
B. 5
C. 6
D. 7
E. 8

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Re: buying and selling [#permalink]

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New post 28 Jul 2008, 03:05
My ans is C.
buying: 5*4=20
selling: 3*2=6
20-6=14
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haveaniceday

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Re: buying and selling [#permalink]

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New post 28 Jul 2008, 04:46
My answer is C as well.

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Re: buying and selling [#permalink]

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New post 28 Jul 2008, 05:05
Chan - could you please explain this part:

buying: 5*4=20
selling: 3*2=6

how did you get 4 and2?
Thanks!

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New post 28 Jul 2008, 07:17
vksunder wrote:
Chan - could you please explain this part:

buying: 5*4=20
selling: 3*2=6

how did you get 4 and2?
Thanks!



Try to do back solving.

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Re: buying and selling [#permalink]

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New post 28 Jul 2008, 07:44
20 - 6 = 14

Purchased 20 needs 4 transactions
Sold 6 needs 2 transactions

So, total 6 transactions

C

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Re: buying and selling [#permalink]

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New post 28 Jul 2008, 08:21
Not fully understanding this...

If a computer retailer bought 5 computers each time and sold 3 computers each time, I read this as buying 5 and selling 3 in a single turnaround. Is that not correct? Can we just assume that he can buy in 5 blocks and sell in 3 blocks freely?

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Re: buying and selling [#permalink]

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New post 28 Jul 2008, 12:39
vksunder wrote:
Chan - could you please explain this part:

buying: 5*4=20
selling: 3*2=6

how did you get 4 and2?
Thanks!



This is what I think:
In order to have the least transactions to increase 14 items, we need more buying than selling,
Step by step:
5*3=15, but 15-14=1 (not divisible by 3)
5*4=20, then 20-14= 6 (divisible by 3) *, so we have 6/3=2 selling
Hope it's clear
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Re: buying and selling   [#permalink] 28 Jul 2008, 12:39
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A computer retailer bought 5 computers each time and sold 3

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