Suppose, the scores of the 4 boys be B1, B2, B3, B4
And, the scores of the 5 girls be G1, G2, G3, G4, G5
So, the Average score of the group =B1+B2+B3+B4+G1+G2+G3+G4+G5/9
We need to find the value of the sum (B1 + B2 + . . . + G4 + G5)
1) The average score of the boys is 23 points while the average score of the girls is 20 points means the average score of the boys is 23 points while the average score of the girls is 20 points
B1+B2+B3+B4/4=23, So, B1+B2+B3+B4=23*4
And G1+G2+G3+G4+G5/5=20, So, G1+G2+G3+G4+G5=20*5
So, B1+B2+B3+B4+G1+G2+G3+G4+G5=23*4+20*5
Therefore, we can find the value of the Average Score of the group. So sufficient.
2) If one of the girls had scored 6 points more, the average score of the group would have been 22 means if one of the girls had scored 6 points more, the average score of the group would have been 22.
Let the girl who scored 6 points be the first girl. So, her new score = G1 + 6
The new total score of the group = B1+B2+B3+B4+(G1+6)+G2+G3+G4+G5
As per Statement, B1+B2+B3+B4+(G1+6)+G2+G3+G4+G5/9=22
So, B1+B2+B3+B4+G1+G2+G3+G4+G5/9+6/9=22
Now, we can easily find the value of B1+B2+B3+B4+G1+G2+G3+G4+G5/9
So, sufficient.
Imo. D