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B
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Difficulty:
55%
(hard)
Question Stats:
61% (01:44) correct
39%
(02:04)
wrong
based on 1065
sessions
History
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A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the four other students from the group?
(A) 5%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
(A) 5%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
09 Sep 2013, 02:59
Kudos
Bookmarks
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the four other students from the group?
(A) 5%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
The question basically asks about the probability that Bob and Lisa sit at the ends.
The total # of sitting arrangements is 5!.
Desired arrangement is either BXYZL or LXYZB. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.
P=(favorable)/(total)=(2*3!)/5!=1/10.
Answer: B.
(A) 5%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
The question basically asks about the probability that Bob and Lisa sit at the ends.
The total # of sitting arrangements is 5!.
Desired arrangement is either BXYZL or LXYZB. Now, XYZ can be arranged in 3! ways, therefore total # of favorable arrangements is 2*3!.
P=(favorable)/(total)=(2*3!)/5!=1/10.
Answer: B.
12 Aug 2013, 10:53
Kudos
Bookmarks
Countdown
A group of 5 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the four other students from the group?
(A) 5%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
Can somebody plz clarify that the answer to this prob is 4!*2 which I am getting, but the answer in the book is given something else.
use this diagram : it can help (A) 5%
(B) 10%
(C) 15%
(D) 20%
(E) 25%
Can somebody plz clarify that the answer to this prob is 4!*2 which I am getting, but the answer in the book is given something else.
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