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01 Sep 2016, 03:55
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63% (01:43) correct
37%
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A jar contains 30 coins, of which 20 are nickels and 10 are dimes. If 7 coins are removed, how many nickels are left?
(1) More nickels are removed than dimes.
(2) The remaining coins in the jar are worth $1.55.
(1) More nickels are removed than dimes.
(2) The remaining coins in the jar are worth $1.55.
Senthil1981
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01 Sep 2016, 08:44
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Bunuel
A jar contains 30 coins, of which 20 are nickels and 10 are dimes. If 7 coins are removed, how many nickels are left?
(1) More nickels are removed than dimes.
(2) The remaining coins in the jar are worth $1.55.
(1) More nickels are removed than dimes.
(2) The remaining coins in the jar are worth $1.55.
A Nickel is worth 5 US cents = 0.05 $
A Dime is worth 10 US cents = 0.10 $
So the total worth of money in the jar is 20 * 0.05 + 10 * 0.10 = $2.00
Consider 1) Out of 7 , it can be all 7 nickels or 6 nickels + 1 dime or 5 nickels + 2 dime or 4 nickels + 3 dime.
Not sufficient. Eliminate A and D
Consider 2) Remaining worth is $1.55
Let N be the remaining nickels and D be the remaining Dime
So N + D = 23
and 0.05 N + 0.1 D = 1.55
Solve this for N and D.
Sufficient B
Answer is B.
Balajikarthick1990
01 Sep 2016, 22:48
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Bunuel
A jar contains 30 coins, of which 20 are nickels and 10 are dimes. If 7 coins are removed, how many nickels are left?
(1) More nickels are removed than dimes.
(2) The remaining coins in the jar are worth $1.55.
(1) More nickels are removed than dimes.
(2) The remaining coins in the jar are worth $1.55.
Hi Bunuel, Does GMAT expect you to remember the equivalent of nickles and dimes to dollars?
