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# A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches

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Math Expert
Joined: 02 Sep 2009
Posts: 44586
A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches [#permalink]

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10 Apr 2018, 21:53
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Difficulty:

(N/A)

Question Stats:

92% (00:39) correct 8% (01:13) wrong based on 26 sessions

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A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches into the jar to draw and eat two candies at random, what is the probability that he eats two chocolate candies?

A. 1/2

B. 1/3

C. 2/9

D. 1/6

E. 1/9
[Reveal] Spoiler: OA

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Manager
Joined: 26 Sep 2017
Posts: 62
Re: A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches [#permalink]

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11 Apr 2018, 06:58
Total candies = 10
Probability of eating 2 choc. Candies..
6/10 * 5/9. = 1/3
B

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Intern
Joined: 08 Jun 2016
Posts: 10
Re: A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches [#permalink]

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11 Apr 2018, 07:30
Total number of ways of selection: 10C2
Selection of 2 random chocolate candies: 6C2

Probability: 6C2 / 10C2.
= 1/3.
Ans B

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Intern
Joined: 22 Jun 2017
Posts: 12
Location: Brazil
WE: Engineering (Energy and Utilities)
Re: A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches [#permalink]

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12 Apr 2018, 11:23
Option B

- 2 chocolates:

$$\frac{6}{10}$$ * $$\frac{5}{9}$$ = $$\frac{1}{3}$$
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Re: A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches [#permalink]

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12 Apr 2018, 15:57
Bunuel wrote:
A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches into the jar to draw and eat two candies at random, what is the probability that he eats two chocolate candies?

A. 1/2

B. 1/3

C. 2/9

D. 1/6

E. 1/9

The probability of selecting two chocolate candies is 6/10 x 5/9 = 30/90 = 1/3.

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Re: A jar contains 6 chocolate candies and 4 mint candies. If Ben reaches   [#permalink] 12 Apr 2018, 15:57
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