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A movie theatre rewards its loyal customers by offering them discounts
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17 Jul 2019, 07:59
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69% (02:23) correct 31% (03:06) wrong based on 199 sessions
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A movie theatre rewards its loyal customers by offering them discounts on the ticket price. For the first 10 movies that a person watches in the movie theatre, the ticket price is $50 per movie. For each subsequent set of 10 movies, the ticket price reduces by $5 per movie till the point where the ticket price equals $25 per movie. The person then gets a lifetime discount and can watch all subsequent movies at a ticket price of $25 per movie. If John watched 95 movies in this movie theatre last year, then the dollar amount that he paid for the tickets of the 95 movies is equivalent to which of the following? A. \(200 × 10 + 35 ×25\) B. \(60 × 25 + 45 × 35\) C. \(225 × 10 + (30 + 5)(30  5)\) D. \(225 × 10 + (40 + 5)(30  5)\) E. \(225 × 10 + (40 + 5)(40  5)\)
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17 Jul 2019, 08:18
A movie theatre rewards its loyal customers by offering them discounts on the ticket price. For the first 10 movies that a person watches in the movie theatre, the ticket price is $50 per movie. For each subsequent set of 10 movies, the ticket price reduces by $5 per movie till the point where the ticket price equals $25 per movie. The person then gets a lifetime discount and can watch all subsequent movies at a ticket price of $25 per movie. If John watched 95 movies in this movie theatre last year, then the dollar amount that he paid for the tickets of the 95 movies is equivalent to which of the following? A. 200×10+35×25 B. 60×25+45×35 C. 225×10+(30+5)(30−5) D. 225×10+(40+5)(30−5) E. 225×10+(40+5)(40−5) Given: A movie theatre rewards its loyal customers by offering them discounts on the ticket price. For the first 10 movies that a person watches in the movie theatre, the ticket price is $50 per movie. For each subsequent set of 10 movies, the ticket price reduces by $5 per movie till the point where the ticket price equals $25 per movie. The person then gets a lifetime discount and can watch all subsequent movies at a ticket price of $25 per movie. John watched 95 movies in this movie theatre last year. Asked: The dollar amount that he paid for the tickets of the 95 movies is equivalent to which of the following? For first 10 movies, ticket price is $50/movie => Total ticket price for 10 movies = $500 For next 10 movies, ticket price is $45/movie => Total ticket price for next 10 movies = $450 For next 10 movies, ticket price is $40/movie => Total ticket price for next 10 movies = $400 For next 10 movies, ticket price is $35/movie => Total ticket price for next 10 movies = $350 For next 10 movies, ticket price is $30/movie => Total ticket price for next 10 movies = $300 For next 10 movies, ticket price is $25/movie => Total ticket price for next 10 movies = $250 For all other movies, ticket price is $25/movie => Total ticket price for next x movies = $25x He watched 95 = 10 + 10 + 10 + 10 + 10 + 10 + 35 movies Total ticket price = $ ( 500+450+400+350+300+250+25*35) = 50(5+6+7+8+9+10) + (305)*(30+5) = 45*50 + (305)*(30+5) = 225*10 + (305)*(30+5) IMO C
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17 Jul 2019, 08:15
I applied the brute force method. C has to be the right answer. 10(50+45+40+35+30+25)+35x25 Is there any other fast method?
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17 Jul 2019, 08:25
Movies 110  $50*10 Movies 1120  $45*10 Movies 2130  $40*10 . . . Movies 5160  $25*10 Movies 6190  $25*10 + $25*10 + $25*10 Movies 9195  $25*5
Total = 10*(50+45+40+35+30+25+25+25+25) + 125 = 3125
Since 3 out of 5 options b
3125=2250+875 = 225*10 + (25)(35) = 225*10 + (305)(30+5)
Answer is (C)



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17 Jul 2019, 08:26
Answer is D.
A movie theatre rewards its loyal customers by offering them discounts on the ticket price. For the first 10 movies that a person watches in the movie theatre, the ticket price is $50 per movie. For each subsequent set of 10 movies, the ticket price reduces by $5 per movie till the point where the ticket price equals $25 per movie. The person then gets a lifetime discount and can watch all subsequent movies at a ticket price of $25 per movie. If John watched 95 movies in this movie theatre last year, then the dollar amount that he paid for the tickets of the 95 movies is equivalent to which of the following?
First 10 movies = 10(50) Following 5 movies until it reaches 25 455=405=355=305=25 total of 5 movies the remaining movies= 90105=80 @ $25



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Re: A movie theatre rewards its loyal customers by offering them discounts
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17 Jul 2019, 08:26
Ist 10 tickets = 50*10 = 500 next 10 = 45*10=450 next 10 = 40* 10 = 400 next 10 =350 next 10 =300 next 10 = 250 next 10 = 250 next 10 = 250 next 10 = 250 next 5 = 125 total 3125 only 3rd equation satisfy this hence C



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17 Jul 2019, 08:28
IMO answer is C:
total price can be written as follows: 50*10+45*10+40*10+35*10+30*10+25*10 + 35*25 = 225*10+35*25 which matches with C



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17 Jul 2019, 08:29
Total Paid: 10 * (50 + 45 + 40 + 35 + 30) + 40*25 + 5*25 => 10*(225) + 10*75 + 5*25 =>10*(225) + 25 * 35 C
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17 Jul 2019, 08:34
C.
Total 95 tickets are purchased.
Using the cost criterion discussed in the question, total amount paid should be: 10*50 + 10*45 +10*40 +10*35 +10*30 +10*25 +(9560)*25  note that ticket price remains same after it hits $25/
So, total price: 10*(50+45+40+35+30+25) + 35*25 = 225*10 + (30+5)*(305)



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17 Jul 2019, 08:37
Total price paid till he reaches 25 bucks per ticket
= 50*10+ 45*10+40*10+35*10+30*10+25*10
= 225*10
Total tickets purchased till that time= 60
Rest, 35 tickets at 25 per ticket
So answer C
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A movie theatre rewards its loyal customers by offering them discounts
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Updated on: 18 Jul 2019, 08:35
Assuming that the first of 95 movies John has watched is the first he's watched at the theater: (10*$50)+(10*$45)+(10*$40)+(10*$35)+(10*$30)+(10*$35)+(45*25) Once John has watched 50 movies, the price is set at 25. So the remaining 45 (of the 95) would be 45*35 Take the 10 out (10*(50+45+40+35+30+25)+(45*25) (10*225)+(45*25) The answers further divide out the (45*25) piece which is equivalent to (40+5)(30−5) *Edit* Messed up the math on number of movies remaining...
Originally posted by coloredflash on 17 Jul 2019, 08:38.
Last edited by coloredflash on 18 Jul 2019, 08:35, edited 1 time in total.



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A movie theatre rewards its loyal customers by offering them discounts
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Updated on: 17 Jul 2019, 18:43
First we have to consider the starting price of $50 per movie for the first 10 movies.
Then, For each subsequent set of 10 movies, the ticket price reduces by $5 per movie till the point where the ticket price equals $25 per movie, so we have:
P*Q 45(we start from 45 since it is 505)*10 40*10 35*10 30*10 25*10
Quantity until now? 50 + 10 (of the first 10 movies priced at $50) = 60
And finally, the units to get 9 in total are going to be priced $25 per movie, so 9560 = 35
Formula will be like this: (50+45+40+35+30+25)*10 + 35*25 = 225*10 + (30+5)*(305)
So (C) is the answer.
Originally posted by Mizar18 on 17 Jul 2019, 08:41.
Last edited by Mizar18 on 17 Jul 2019, 18:43, edited 1 time in total.



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17 Jul 2019, 08:43
Total spend = 50*10+45*10+35*10+30*10+25*45=3125 Only C = 3125 Hence C
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17 Jul 2019, 08:45
So first we calculate the total dollar amount that John paid. For the first 50 tickets John paid
10(50+45+40+35+30) =2000 For the rest 45 tickets he paid 45*25 =1125
Total amount spent is 2000+1125 =3125
Then we calculate the amount from the options. If we can find the approx value first we can eliminate option a,b,e from c and d we calculate and get the answer as c
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17 Jul 2019, 08:45
A movie theatre rewards its loyal customers by offering them discounts on the ticket price. For the first 10 movies that a person watches in the movie theatre, the ticket price is $50 per movie. For each subsequent set of 10 movies, the ticket price reduces by $5 per movie till the point where the ticket price equals $25 per movie. The person then gets a lifetime discount and can watch all subsequent movies at a ticket price of $25 per movie. If John watched 95 movies in this movie theatre last year, then the dollar amount that he paid for the tickets of the 95 movies is equivalent to which of the following?
A. 200×10+35×25200×10+35×25 B. 60×25+45×3560×25+45×35 C. 225×10+(30+5)(30−5)225×10+(30+5)(30−5) D. 225×10+(40+5)(30−5)225×10+(40+5)(30−5) E. 225×10+(40+5)(40−5)
Pure calculation question. Highly unlikely that you will see this type of question on the GMAT. The answer is A.



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17 Jul 2019, 08:46
Quote: A movie theatre rewards its loyal customers by offering them discounts on the ticket price. For the first 10 movies that a person watches in the movie theatre, the ticket price is $50 per movie. For each subsequent set of 10 movies, the ticket price reduces by $5 per movie till the point where the ticket price equals $25 per movie. The person then gets a lifetime discount and can watch all subsequent movies at a ticket price of $25 per movie. If John watched 95 movies in this movie theatre last year, then the dollar amount that he paid for the tickets of the 95 movies is equivalent to which of the following? Let us recap what we are given: First 10 movies  price per movie is $50 2nd set of 10 movies  price per movie is \($50  $5\) nth set of 10 movies  price per movie is \($50  $5 * (n  1)\) until \($50  $5 * n = $25\) After price per movie is $25, all future tickets will remain at this price John watched 95 movies T=95 What is the dollar amount he paid? First, let us find what n is equal to: \(50  5*(n1) = 25\) => \(50  5n + 5 = 25\) => \(5n = 30\) => \(n =6\) Now, as we have n, we can write down what is the total amount of money for the movies: For the first 10 movies set n=1 and the sum of money is \(10 * 50\) For the second 10 movies n=2 and the sum of money is \(10 * (50  5 * (2  1))\) For the 6th set of 10 movies n=6 and the sum of money is \(10 * (50  5 * (6  1))\) For the movies after the 6th set of movies, the price is \((95  (n * 10) * 25)\) The final formula is \(10 * 50 + 10 * (50  5) + 10 * (50  10) + 10 * (50  15) + 10 * (50  20) + 10 * (50  25) + (95  10 * 6) * 25 = 10 * (50 + 45 + 40 + 35 + 30 + 25) + (95  60) * 25 = 10 * 225 + 35 * 25\) \(10 * 225 + 35 * 25 = 10 * 225 + (30 + 5) * (30  5)\) Answer: C



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17 Jul 2019, 08:46
For 95 tickets John would have paid  10*50+10*45+10*40+10*35+10*30+45*25 = 10(50+45+40+35+30)+45*25= 200*10+45*25Now go to answer options  PoE A. 200×10+35×25  Incorrect, As Option in same format as above but numbers are different B. 60×25+45×35  Incorrect, As Option in same format as above but numbers are different C. 225×10+(30+5)(30−5)  Correct, First part has 200*10+25*10 that is is compensated by 25*(4525) in the second partD. 225×10+(40+5)(30−5)  Incorrect, as first part is excess by 250 which is not compensated E. 225×10+(40+5)(40−5)  Incorrect as both first and second part have excess. IMO C
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17 Jul 2019, 08:50
Ok, I made a table 110 50 1120 45 2130 40 3140 35 4150 30 5195 25
I just calculated it 35*50+25*55=3125
First of all, I started with the last 3 options and substracted 225*10 from 3125 31252250=875 Then I just tried to divide it on 35 and got 25. We could divide it on 25 or 45 and after all, we would got the answer ^^
So, The correct answer is C



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17 Jul 2019, 08:57
John watched 95 movies last year, so the dollar he spent for all movie tickets is cumulative of the following: \(1^{st}\) ten movies: 10 x $50 \(2^{nd}\) ten movies: 10 x $45 \(3^{rd}\) ten movies: 10 x $40 \(4^{th}\) ten movies: 10 x $35 \(5^{th}\) ten movies: 10 x $30 \(6^{th}\) ten movies: 10 x $25 \(61^{th}  95^{th}\) movies: 35 x $25
Thus, he spent in total \(($50+$45+$40+$35+$30+$25)*10 + $25*35 = $225*10 + $(30+5)*(305)\)
Answer is (C) \(: 225×10+(30+5)(30−5)\)



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17 Jul 2019, 09:06
IMO B.
Customer is charged at $50 for first 10 then 45,40,35,30 and the rest 6 at 25 in batches of 10. The customer bought 95 tickets. This can be broken into: 1. First 10 tickets charged at $50 = 50*10=$500. 2. Next 8 batches of 10 tickets charged at $300 = 300*8 = $2400. 3. Next 5 tickets according to the batch of 10, will be charged as  45,40,35,30 and 25 = $175. Hence, the total amount = 500 + 2400 + 175 = $3075. The option which gives the same value is B.




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