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Updated on: 20 Jul 2018, 23:11
Originally posted by EgmatQuantExpert on 20 Jul 2018, 05:21.
Last edited by EgmatQuantExpert on 20 Jul 2018, 23:11, edited 2 times in total.
Last edited by EgmatQuantExpert on 20 Jul 2018, 23:11, edited 2 times in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
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71% (01:23) correct
29%
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Permutation and Combination - Practice Question #1
1-A palindrome is a number that reads the same forward and backward. For example, 1221 and 232 are palindromes. By using the numbers from 1-9, how many 5-digit palindromes can be created.
Options
To solve Question 2: Question 2
To solve Question 3: Question 3
To read our article: Must Read Articles and Practice Questions to score Q51 !!!!
1-A palindrome is a number that reads the same forward and backward. For example, 1221 and 232 are palindromes. By using the numbers from 1-9, how many 5-digit palindromes can be created.
Options
- a) 648
b) 729
c) 800
d) 900
e) 1000
To solve Question 2: Question 2
To solve Question 3: Question 3
To read our article: Must Read Articles and Practice Questions to score Q51 !!!!
Updated on: 23 Jul 2018, 05:44
Originally posted by EgmatQuantExpert on 20 Jul 2018, 05:23.
Last edited by EgmatQuantExpert on 23 Jul 2018, 05:44, edited 2 times in total.
Last edited by EgmatQuantExpert on 23 Jul 2018, 05:44, edited 2 times in total.
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Solution
Given:
- • A palindrome is a number that reads the same forward and backward.
To find:
- • By using the numbers from 1-9, how many 5-digit palindromes can be created
Approach and Working:
Let the 5-digit number is abcba.
So, we need to find the in how many we can fill a, b, and c since the last two digits will take the same number.
- • a can take 9 numbers from 1-9.
• b can take 9 numbers from 1-9.
• c can take 9 numbers from 1-9.
Thus, way to form a 5-digit palindrome number= 9 * 9 * 9 *1 *1= 729.
Hence, the correct answer is option B.
Answer: B
20 Jul 2018, 06:20
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EgmatQuantExpert
I am getting 5 arrangements
ABCBA- Total arrangement A(9)*B(8)*C(7)=504 , A can be selected in 9,b in 8 and C in 7 ways
ABBBA- Total arrangement A(9)*B(8)=72
ABABA- Total arrangement A(9)*B(8)=72
AAAAA- Total arrangement A(9)=9
ABBBA- Total arrangement A(9)*B(8)=72
Total=504+72+72+72+9=729
