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A rectangular floor 18 feet by 10 feet is to be completely covered wit

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A rectangular floor 18 feet by 10 feet is to be completely covered wit  [#permalink]

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New post 26 Sep 2017, 23:21
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Re: A rectangular floor 18 feet by 10 feet is to be completely covered wit  [#permalink]

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New post 27 Sep 2017, 01:02
A rectangular floor 18 feet by 10 feet is to be completely covered with carpeting that costs x dollars per square yard. In terms of x, how many dollars will the carpeting cost? (1 yard = 3 feet)

Rectangular floor = 18 feet * 10 feet
3 feet = 1 yard => 18 feet = 18/3 = 6 yard and 10 feet = 10/3 yard

Total floor area = 6* 10/3 = 20 square yards

Carpeting cost = 20x

Answer: A
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Re: A rectangular floor 18 feet by 10 feet is to be completely covered wit  [#permalink]

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New post 27 Sep 2017, 21:13
Area of rectangle in yards = 18/3 * 10/3 = 20
Carpeting Cost = 20x
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Re: A rectangular floor 18 feet by 10 feet is to be completely covered wit  [#permalink]

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New post 01 Oct 2017, 12:18
1
Bunuel wrote:
A rectangular floor 18 feet by 10 feet is to be completely covered with carpeting that costs x dollars per square yard. In terms of x, how many dollars will the carpeting cost? (1 yard = 3 feet)

(A) 20x
(B) 28x
(C) 60x
(D) 180x
(E) 540x


The area of the floor is 18 x 10 = 180 ft^2. Since 1 yd = 3 ft, 1 yd^2 = 3^2 ft^2 = 9 ft^2. Thus, the area of the floor is 180/9 = 20 yd^2. Since each square yard costs x dollars in carpeting, the entire floor costs 20x in carpeting.

Answer: A
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Re: A rectangular floor 18 feet by 10 feet is to be completely covered wit  [#permalink]

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New post 01 Oct 2018, 16:11
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Re: A rectangular floor 18 feet by 10 feet is to be completely covered wit   [#permalink] 01 Oct 2018, 16:11
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