Bunuel wrote:

A rectangular lawn of length 200m by 120m has two roads running along its center, one along the length and the other along the width. If the width of the roads is 5m what is the area covered by the two roads?

A. 400

B. 1550

C. 1575

D. 1600

E. 1625

IMO: C

Attachment:

1.jpg [ 11.62 KiB | Viewed 9262 times ]
Area of the road parallel to the length of the rectangular lawn = 200*5 = 1000 sq m

Area of the road parallel to the breadth of the rectangular lawn = 120*5 = 600 sq m

Area of the intersection of the two perpendicular roads = 5*5 = 25 sq m

Since we calculated the intersection road area twice( once while calculating along length and again while calculating along breadth), we need to subtract from the total sum once to make it even.

Thus area of the paths = 1000+600-25 = 1575 sq m

_________________

I'm happy, if I make math for you slightly clearer

And yes, I like kudos ¯\_(ツ)_/¯