Let the distance between the stations be x
First train(A) left station P- 6 AM and reached station Q - 11 AM, Time taken :5 hours.
Second train(B) left the station Q - 7 AM and reached station P - 10 AM, Time taken : 3 hours
Also since one of the trains left an hour later, the other train would have
traveled for an hour, covering \(\frac{x}{5}\) of the distance(Since Time: 5 hours)
For the remaining \(\frac{4x}{5}\) of the distance, the trains, together travel a distance of \(\frac{x}{3} + \frac{x}{5}(\frac{8x}{15})\) in an hour
Time taken for the trains to meet is \((\frac{4x}{5}/\frac{8x}{15}) = \frac{4*15}{5*8}= \frac{3}{2} hours\)
The trains meet at
8:30 am(Option C), one and an half hours after train B leaves the station Q.
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