Last visit was: 23 Apr 2026, 07:45 It is currently 23 Apr 2026, 07:45
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,778
Own Kudos:
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,778
Kudos: 810,789
 [30]
10
Kudos
Add Kudos
20
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
ske
Joined: 31 Aug 2014
Last visit: 06 Feb 2020
Posts: 17
Own Kudos:
228
 [15]
Given Kudos: 167
Posts: 17
Kudos: 228
 [15]
15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 23 Apr 2026
Posts: 6,976
Own Kudos:
16,906
 [8]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,976
Kudos: 16,906
 [8]
6
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
General Discussion
User avatar
HardWorkBeatsAll
Joined: 17 Aug 2015
Last visit: 19 Jul 2020
Posts: 89
Own Kudos:
344
 [4]
Given Kudos: 341
Location: India
Concentration: Strategy, General Management
GMAT 1: 750 Q49 V42
GPA: 4
WE:Information Technology (Finance: Investment Banking)
GMAT 1: 750 Q49 V42
Posts: 89
Kudos: 344
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(D) - each alone is sufficient.

And happily, no one on the train will miss their meetings :)


7 am (A) ---------------- 10 min (B) ------------- 10 min (C) --------------- 2 pm (D)

Time available (without any delays) = 7 hours - 20 mins = 6.66 hours or 6 (2/3) hours (mixed fraction).

(A) -> Time is reduced to 6 hours 10 mins because of 30 min delay. i.e. Time available = 6 (1/6) (mixed fraction).
Speed (max) = 60 mph. Time taken at this speed is - 320/60 = 5 hrs 20 min.

So, time available is greater than time taken at max speed. Train reaches in time. Sufficient.

(B) -> Dist covered in 75% = 3*320/4 = 240 miles
Time taken for this 75% = 240/60 = 4 hours
Remaining track = 320 - 240 = 80 miles
Remaining time = 6(2/3) - 4 hours = 2(2/3) hours (mixed fraction = 2 hours 40 min). Note that the 30 min delay is NOT to be considered here.
Speed required = 80/(2(2/3)) = 80/(8/3) = 80*3/8 = 30 mph.
This is doable. Sufficient.

So, both (A) and (B) are independently sufficient.

Answer: (D)
User avatar
patodrums89
Joined: 25 Jul 2014
Last visit: 09 Oct 2017
Posts: 58
Own Kudos:
15
 [5]
Given Kudos: 30
Location: Mexico
Concentration: Entrepreneurship, Sustainability
GMAT 1: 680 Q49 V33
WE:Business Development (Energy)
GMAT 1: 680 Q49 V33
Posts: 58
Kudos: 15
 [5]
5
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMATinsight
Bunuel
A train runs over a straight route from town A to town D. It is scheduled to depart town A at 7am and arrive at town D at 2pm, with 10 minute stops in towns B and C. The train’s top speed is 60mph. The entire length of the route is 320 miles. Will the train arrive on time?

(1) The train experiences a 30 minute delay in town B in addition to its scheduled stop.

(2) The train travels at its top speed for exactly 75% of the trip.

Kudos for a correct solution.

Total Distance = 320 Miles
Total Time = 7 hours (7 AM to 2 PM) = 7*60 = 420 minutes
Time of Break = 2*10 = 20 minutes
Travel time to cover 320 Miles = 420 - 20 = 400 Mins
Max. Speed = 60 mph
Min speed required throughout to travel 320 miles in 400 mins = 320*60/400 = 48 mph

Question : Is Time taken to cover distance of 320 miles = 400 minutes ?

Statement 1: The train experiences a 30 minute delay in town B in addition to its scheduled stop.
Time taken by train when it travels the complete distance at max speed = 320*60/60 = 320 mins
including 10 mins break, total time = 320+20 = 340 Mins
Maximum delay acceptable = 420 - 340 = 80 mins
i.e. a train can reach on time even with 80 mins delay if it travels at top speed for all the time
30 mins delay may cause delay or on time journey. Hence,
NOT SUFFICIENT

Statement 2: The train travels at its top speed for exactly 75% of the trip.
75% of Trip = 320*75/100 = 240 miles
Time to travel 240 miles at Top speed = 240/60 = 4 hours = 240 mins
But Min speed is unknown which may or may NOT have caused any delay, Hence
NOT SUFFICIENT

Combining the two statements:
240 mins exhausted to travel 240 miles
Remaining travel time = 400-240 = 160 mins
Remaining distance = 320-240 = 80 miles
Speed required to travel remaining distance in remaining time to be on schedule = 80*60/160 = 30 miles/hr
But Minimum Speed is unknown. Hence
NOT SUFFICIENT

Answer: Option E

Agreed with GMAT Insight.

The Questions ask if the train WILL ARRIVE ON TIME, so is a must be true question, hence we will need some speed constraints to know if the train will cover certain distance in the given time.

If we had the average speed or a minimum allowable speed in the question stem, the answer would be C. Since we do not have it, answer is (E).

Cheers!
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 23 Apr 2026
Posts: 6,976
Own Kudos:
16,906
 [5]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,976
Kudos: 16,906
 [5]
5
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ske
Bunuel
A train runs over a straight route from town A to town D. It is scheduled to depart town A at 7am and arrive at town D at 2pm, with 10 minute stops in towns B and C. The train’s top speed is 60mph. The entire length of the route is 320 miles. Will the train arrive on time?

(1) The train experiences a 30 minute delay in town B in addition to its scheduled stop.

(2) The train travels at its top speed for exactly 75% of the trip.

Kudos for a correct solution.



ANSWER E

TOTAL TIME 7 HOURS
STOPPAGE 20 MINS
AFTER SUBTRACTION WE WILL GET 6 HOURS 40 MINS

TOTAL JOURNEY 320 MILES

TOP SPEED DOES NOT MEANS ACTUAL SPEED ,ITS BASICALLY A PEAK SPEED WHICH A TRAIN CAN ATTAIN .

FROM A SUBTRACTING 30 MINS ,WE WILL GET 6 HOURS 10 MINS ,
WHICH MEANS TRAIN HAS TO COVER JOURNEY AT THE SPEED OF 51 MILES PER HOUR TO COMPLETE THE JOURNEY,

ITS NOT GIVEN SO ANS A IS INSUFF


POINT 2

75 % OF THE JOURNEY = 240 MILES
BALANCE 80 MILES ,WE DON'T KNOW THE EXACT SPEED, SO B INSUFFICIENT


OA MUST BE E

GIVE KUDOS FOR MOTIVATION :-D

Post For those who struggle for High order of accuracy in Data Sufficiency

Hi ske

I don't agree to the highlighted reasoning that you have given for statement 2, to prove the statement-2 'Insufficient'.

In case, the required Speed to travel the remaining Distance, to be on time at destination, had gone above 60 mph then the statement 2 would have been sufficient to answer the question in form of 'NO' 'Train will NOT arrive on Time'.

Therefore, to answer such questions we , sometimes, don't require exact speed. :-)

We can say the statement as "Not SUFFICIENT" only when the statement gives us an Inconsistent answer of the question asked in question stem.

I hope this helps!
User avatar
Mo2men
Joined: 26 Mar 2013
Last visit: 09 May 2023
Posts: 2,426
Own Kudos:
Given Kudos: 641
Concentration: Operations, Strategy
Schools: Erasmus (II)
Products:
Schools: Erasmus (II)
Posts: 2,426
Kudos: 1,508
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMATinsight
Bunuel
A train runs over a straight route from town A to town D. It is scheduled to depart town A at 7am and arrive at town D at 2pm, with 10 minute stops in towns B and C. The train’s top speed is 60mph. The entire length of the route is 320 miles. Will the train arrive on time?

(1) The train experiences a 30 minute delay in town B in addition to its scheduled stop.

(2) The train travels at its top speed for exactly 75% of the trip.

Kudos for a correct solution.

Total Distance = 320 Miles
Total Time = 7 hours (7 AM to 2 PM) = 7*60 = 420 minutes
Time of Break = 2*10 = 20 minutes
Travel time to cover 320 Miles = 420 - 20 = 400 Mins
Max. Speed = 60 mph
Min speed required throughout to travel 320 miles in 400 mins = 320*60/400 = 48 mph

Question : Is Time taken to cover distance of 320 miles = 400 minutes ?

Statement 1: The train experiences a 30 minute delay in town B in addition to its scheduled stop.
Time taken by train when it travels the complete distance at max speed = 320*60/60 = 320 mins
including 10 mins break, total time = 320+20 = 340 Mins
Maximum delay acceptable = 420 - 340 = 80 mins
i.e. a train can reach on time even with 80 mins delay if it travels at top speed for all the time
30 mins delay may cause delay or on time journey. Hence,
NOT SUFFICIENT

Statement 2: The train travels at its top speed for exactly 75% of the trip.
75% of Trip = 320*75/100 = 240 miles
Time to travel 240 miles at Top speed = 240/60 = 4 hours = 240 mins
But Min speed is unknown which may or may NOT have caused any delay, Hence
NOT SUFFICIENT

Combining the two statements:
240 mins exhausted to travel 240 miles
Remaining travel time = 400-240 = 160 mins
Remaining distance = 320-240 = 80 miles
Speed required to travel remaining distance in remaining time to be on schedule = 80*60/160 = 30 miles/hr
But Minimum Speed is unknown. Hence
NOT SUFFICIENT

Answer: Option E

Is Statement 1 suff as we deduce that train will arrive on time even with delay ? or do I miss something?
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 23 Apr 2026
Posts: 6,976
Own Kudos:
16,906
 [1]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,976
Kudos: 16,906
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Mo2men


Is Statement 1 suff as we deduce that train will arrive on time even with delay ? or do I miss something?

Statement 1 is Not sufficient because train May or May NOT reach on time depending on at what speed it travels for the rest of the journey.

The statement defines the reasoning that train has potential to reach on time but rest the question is NOT "Can train reach on time?" the question is "Will the train arrive on time?" i.e. we need to answer with certainty which we lack even after combine the two statements.

I hope this helps
User avatar
MathRevolution
User avatar
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Last visit: 27 Sep 2022
Posts: 10,063
Own Kudos:
20,000
 [1]
Given Kudos: 4
GMAT 1: 760 Q51 V42
GPA: 3.82
Expert
Expert reply
GMAT 1: 760 Q51 V42
Posts: 10,063
Kudos: 20,000
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem.
Remember equal number of variables and independent equations ensures a solution.

A train runs over a straight route from town A to town D. It is scheduled to depart town A at 7am and arrive at town D at 2pm, with 10 minute stops in towns B and C. The train’s top speed is 60mph. The entire length of the route is 320 miles. Will the train arrive on time?

(1) The train experiences a 30 minute delay in town B in addition to its scheduled stop.

(2) The train travels at its top speed for exactly 75% of the trip.

From the original condition, we do not know the velocity and the distance from A to B, B to C and C to D, therefore there are 6 variables. Since we only have 1 equation (Distance from A to D which is 320), we need 5 more equations and there is only 1 each in 1) and 2) therefore we need 3 more equations. E has high probability of being the answer, and it turns out that E actually is.

Normally for cases where we need 3 more equation, such as original conditions with 3 variable, or 4 variables and 1 equation, or 5 variables and 2 equations, we have 1 equation each in both 1) and 2). Therefore E has a high chance of being the answer (especially about 90% of 2by2 questions where there are more than 3 variables), which is why we attempt to solve the question using 1) and 2) together. Here, there is 80% chance that E is the answer, while C has 15% chance. These two are the key questions. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since E is most likely to be the answer according to DS definition, we solve the question assuming E would be our answer hence using ) and 2) together. (It saves us time). Obviously there may be cases where the answer is A, B, C or D.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,778
Own Kudos:
810,789
 [3]
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,778
Kudos: 810,789
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A train runs over a straight route from town A to town D. It is scheduled to depart town A at 7am and arrive at town D at 2pm, with 10 minute stops in towns B and C. The train’s top speed is 60mph. The entire length of the route is 320 miles. Will the train arrive on time?

(1) The train experiences a 30 minute delay in town B in addition to its scheduled stop.

(2) The train travels at its top speed for exactly 75% of the trip.

Kudos for a correct solution.

GROCKIT OFFICIAL SOLUTION:

This is a yes/no data sufficiency. In order to answer yes or no, we need to know the time it takes the train to make its journey. From the question, we can see that the train is supposed to take 7 hours to go from Town A to Town D with two 10-minute stops. Thus, the total travel-time of the train is 7 hours – 20 minutes = 6 hours, 40 minutes, or 6.67 hours. A train that takes the full 6.67 hours to travel 320 miles would need to travel at a speed of approx 48mph or faster to make its timetable. Remember that this is what the train is supposed to do. Let’s see how each statement affects the time-table.

With a 30 minute delay, the train’s travel-time is now 6 hours, 10 minutes, or 6.167 hours. With that delay, the train needs to travel at approx 51mph to make its timetable. However, what is missing from this statement is proof that the train actually did increase its speed to make its timetable. Just because it was possible the train arrived on time, doesn’t mean it did. Statement (1) is insufficient.

Let’s look at Statement (2). 75% of the trip is 240 miles out of the total 320 miles. This means the train has to travel the remaining 80 miles in a little less than 3 hours, an average speed of approximately 25 miles an hour in order to make the timetable. This is clearly within the train’s limits, but we do not know anything about the train’s speed for these remaining 80 miles. Statement (2) is insufficient.

Combining the two statements, we know that the train only has 2 hours and 10 minutes to travel the remaining 80 miles. This requires traveling almost 40 mph. This is possible, but we have no certainty that the train accomplished this. The answer, therefore, is (E).
User avatar
KrishnakumarKA1
Joined: 05 Jan 2017
Last visit: 13 Oct 2020
Posts: 398
Own Kudos:
Given Kudos: 15
Location: India
Posts: 398
Kudos: 314
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Solution:

Given: The total distance from town A to town D = 320 miles
Total time taken (7 am to 2 pm) = 7 ×60=420 mins
Maximum speed = 60 mph
Stoppage time (in town B and town C) = 10 + 10 = 20 mins
To find: Will train reach town D at 4 PM?

Analysis of statement 1: The train experiences a 30-minute delay in town B in addition to its scheduled stop.
In this statement they have given there is an additional delay of 30 mins, as we do not know what is the average speed of the train we cannot find whether the train arrived on time to town D or not! (Top speed is mentioned to be 60 mph but not necessarily that train will be travelling at the top speed all the time).
So statement 1 is insufficient to answer. We can eliminate options A and D.

Analysis of statement 2: The train travels at its top speed for exactly 75% of the trip.
Being at the top speed for exactly 75% of the trip doesn’t mean the train will arrive town D at exact time! Because we do not know what is the speed of the train for the rest 25% of the journey. We need to know the average speed of the train to find the answer. Hence statement 2 is insufficient to answer. We can eliminate option B.

Combining the statements 1 & 2: We get:
Even after combining we cannot comment anything about the average speed of the train. Hence it is insufficient.

The correct answer option is “E”.
User avatar
aronbhati
Joined: 13 Jul 2024
Last visit: 21 Apr 2026
Posts: 44
Own Kudos:
Given Kudos: 112
Location: India
Concentration: Operations, Finance
GPA: 8.25
Posts: 44
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Sir,

but as per question, you solved that minimum speed is 48 MPH then for option C, minimum speed is coming around 30 MPH which is lower than 48 mph so it can be answer C. please correct me where i was wrong
GMATinsight


Total Distance = 320 Miles
Total Time = 7 hours (7 AM to 2 PM) = 7*60 = 420 minutes
Time of Break = 2*10 = 20 minutes
Travel time to cover 320 Miles = 420 - 20 = 400 Mins
Max. Speed = 60 mph
Min speed required throughout to travel 320 miles in 400 mins = 320*60/400 = 48 mph

Question : Is Time taken to cover distance of 320 miles = 400 minutes ?

Statement 1: The train experiences a 30 minute delay in town B in addition to its scheduled stop.
Time taken by train when it travels the complete distance at max speed = 320*60/60 = 320 mins
including 10 mins break, total time = 320+20 = 340 Mins
Maximum delay acceptable = 420 - 340 = 80 mins
i.e. a train can reach on time even with 80 mins delay if it travels at top speed for all the time
30 mins delay may cause delay or on time journey. Hence,
NOT SUFFICIENT

Statement 2: The train travels at its top speed for exactly 75% of the trip.
75% of Trip = 320*75/100 = 240 miles
Time to travel 240 miles at Top speed = 240/60 = 4 hours = 240 mins
But Min speed is unknown which may or may NOT have caused any delay, Hence
NOT SUFFICIENT

Combining the two statements:
240 mins exhausted to travel 240 miles
Remaining travel time = 400-240 = 160 mins
Remaining distance = 320-240 = 80 miles
Speed required to travel remaining distance in remaining time to be on schedule = 80*60/160 = 30 miles/hr
But Minimum Speed is unknown. Hence
NOT SUFFICIENT

Answer: Option E
User avatar
Gmat860sanskar
Joined: 05 May 2023
Last visit: 23 Apr 2026
Posts: 212
Own Kudos:
Given Kudos: 79
Schools: ISB '26
GMAT Focus 1: 605 Q82 V78 DI80
Products:
Schools: ISB '26
GMAT Focus 1: 605 Q82 V78 DI80
Posts: 212
Kudos: 113
Kudos
Add Kudos
Bookmarks
Bookmark this Post
aronbhati
Hi Sir,

but as per question, you solved that minimum speed is 48 MPH then for option C, minimum speed is coming around 30 MPH which is lower than 48 mph so it can be answer C. please correct me where i was wrong

Hello Aron,

In GMAT Data insight section, most important skill is to keep track of the question stimulus and solve it accordingly. Here the main question is :
Will the train arrive on time?

So as we can figure out remaining travel time and distance is 160 min and 80 miles respectively, so here there can be multiple cases :

Case 1: Speed in the remaining time is above 30 miles/hr then yes, we can say that it will arrive on time, However this information is not given explicitly, so we can make another case

Case 2 : Speed in remaining time is below 30 miles/hr then our answer will be No.

So here we are getting both the answer Yes and No. Clearly both statement combined is not enough.

That's why our answer here is E.
Moderators:
Math Expert
109778 posts
498 posts
212 posts