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23 Jun 2022, 06:30
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E
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Difficulty:
25%
(medium)
Question Stats:
69% (00:58) correct
31%
(01:29)
wrong
based on 26
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ABC and DEF are right triangles. Each side of triangle ABC is twice the length of the corresponding side of triangle DEF.
(The area of DEF)/(The area of ABC) =
(A) 4
(B) 2
(C) 1
(D) 1/2
(E) 1/4
(The area of DEF)/(The area of ABC) =
(A) 4
(B) 2
(C) 1
(D) 1/2
(E) 1/4
23 Jun 2022, 06:52
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Bunuel
ABC and DEF are right triangles. Each side of triangle ABC is twice the length of the corresponding side of triangle DEF.
(The area of DEF)/(The area of ABC) =
(A) 4
(B) 2
(C) 1
(D) 1/2
(E) 1/4
(The area of DEF)/(The area of ABC) =
(A) 4
(B) 2
(C) 1
(D) 1/2
(E) 1/4
A = 0.5bh
Area of DEF = 0.5bh
Area of ABC = 0.5(2b)(2h) = 2bh
(The area of DEF)/(The area of ABC) = 0.5bh/2bh = 1/4
Answer choice E.
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23 Jun 2022, 06:54
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Observe what is given in the question :
1) ABC and DEF are right triangles
2) Each side of triangle ABC is twice the length of the corresponding side of triangle DEF i.e. ABC is a bigger triangle
What to find:
(The area of DEF)/(The area of ABC)
Suppose the Sides of DEF are x,y,z
then from statement 2, we can infer Sides of ABC are 2x,2y,2z
We can find the area of right triangle = 1/2 * b * h
(The area of DEF)/(The area of ABC) = (1/2 *x*y)/(1/2 * 2x * 2y)
Answer = 1/4 (OE)
1) ABC and DEF are right triangles
2) Each side of triangle ABC is twice the length of the corresponding side of triangle DEF i.e. ABC is a bigger triangle
What to find:
(The area of DEF)/(The area of ABC)
Suppose the Sides of DEF are x,y,z
then from statement 2, we can infer Sides of ABC are 2x,2y,2z
We can find the area of right triangle = 1/2 * b * h
(The area of DEF)/(The area of ABC) = (1/2 *x*y)/(1/2 * 2x * 2y)
Answer = 1/4 (OE)
