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Could you please elaborate on D..Why is it not possible and what is possible in such a scenario(when an expression has both squares and roots and we want to eliminate them)?I'm having trouble with this concept.
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Hi Ralphcuisak,

Here's why you can't re-write/reduce/simplify the prompt to what's listed in Answer D:

We're given.....

4X^2 = Y^2 - 9

The basic rule when dealing with equations is that you can do ANYTHING to both sides of an equation as long as you do it EQUALLY to BOTH sides. Everything gets a bit more complex when you're dealing with variables in the denominator of a fraction and/or inequalities, but neither of those subjects is a factor in this prompt.

Looking at Answer D, we have....

2X = Y - 3

While you COULD take the square root of both sides of the original equation, it's important to note that the square root of Y^2 - 9 is NOT (Y-3).

Y^2 - 9 can be factored into (Y-3)(Y+3), but neither of these parentheses is the square root of Y^2 - 9.

You can see the proof when you square either of the two parentheses:
(Y-3)^2 = Y^2 - 6X + 9
(Y+3)^2 = Y^2 + 6x + 9

Thus, D is NOT equivalent to the prompt.

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Do we need to tag functions and custom characters in this? I think it is plain algebra with all standard characters (no custom characters)?
abhisheknandy08
Which of the following equations is NOT equivalent to 4x^2 = y^2 - 9 ?

(A) 4x^2 + 9 = y^2
(B) 4x^2 - y^2 = -9
(C) 4x^2= (y + 3)(y - 3)
(D) 2x = y - 3
(E)x^2 = (y^2-9)/4
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Which of the following equations is NOT equivalent to \(4x^2\) = \(y^2\)- 9 ?

(A) \(4x^2\)+ 9 = \(y^2\)
(B) \(4x^2\) - \(y^2\) = -9
(C) \(4x^2\)= (y + 3)(y - 3)
(D) 2x = y - 3
(E) \(x^2\) = (\(y^2\)-9)/4

Edit: Formatting

We can always look for number plugging method as well because sometimes equations get difficult to be compared.

Here taking x =2 & y =5 satisfies the equation, plugging the same number in the list of options only D : 2x = y -3 does not satisfy the equation.

Hence D
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A quick look at the options and you see that Option D looks odd.

Squaring both sides, we have \((2x)^2 = (y + 3)^2\). Therefore \(4x^2 = y^2 + 6x + 9\) and this is not the same as the original expression.


All other options are just another form of the basic equation

Option A: \(4x^2 + 9 = y^2\). Therefore \(4x^2 = y^2 - 9\)


Option B: \(4x^2 - y^2 = -9\). Therefore \(4x^2 = y^2 - 9\)


Option C: \(4x^2 = (y + 3)(y - 3)\). Therefore \(4x^2 = y^2 - 9\)


Option E: \(x^2 = \frac{y^2 - 9}{4}\). Therefore \(4x^2 = y^2 - 9\)



Option D

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Asked: Which of the following equations is NOT equivalent to \(4x^2 = y^2 - 9\) ?


(A) \(4x^2+ 9 = y^2\)
Equivalent
(B) \(4x^2 - y^2 = -9\)
Equivalent
(C) \(4x^2= (y + 3)(y - 3)\)
Equivalent
(D) \(2x = y - 3\)
Not equivalent
(E) \(x^2 = \frac{(y^2 - 9)}{4}\)
Equivalent

IMO D
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what is the level of this question?
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what is the level of this question?

You can check the difficulty level of a question along with the stats on it in the first post. For this question Difficulty = Sub-600 Level. The difficulty level of a question is calculated automatically based on the timer stats from the users which attempted the question.
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