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Director  Joined: 01 Apr 2008
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Name: Ronak Amin
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At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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Difficulty:   65% (hard)

Question Stats: 62% (02:16) correct 38% (02:08) wrong based on 546 sessions

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At their respective rates, pump A, B, and C can fulfill an empty tank, or pump-out the full tank in 2, 3, and 6 hours. If A and B are used to pump-out water from the half-full tank, while C is used to fill water into the tank, in how many hours, the tank will be empty?

A. 2/3
B. 1
C. 3/4
D. 3/2
E. 2

Originally posted by Economist on 02 Apr 2009, 20:12.
Last edited by Bunuel on 29 Sep 2013, 09:37, edited 1 time in total.
Renamed the topic and edited the question.
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Joined: 24 Jun 2008
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Re: PS: Pool fills  [#permalink]

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11
13
Economist wrote:
At their respective rates, pump A, B, and C can fulfill an empty tank, or pump-out the full tank in 2, 3, and 6 hours. If A and B are used to pump-out water from the half-full tank, while C is used to fill water into the tank, in how many hours, the tank will be empty?
A. 2/3
B. 1
C. 3/4
D. 3/2
E. 2

You can use a rates formula here, or convert each worker to the same amount of time (6 hours) :

A empties 3 tanks every 6 hours
B empties 2 tanks every 6 hours
C fills 1 tank every 6 hours
Together, they empty 4 tanks every 6 hours
So they empty 1 tank every 6/4 hours, and empty half of a tank in 3/4 hours. C.
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Re: PS: Pool fills  [#permalink]

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6
1
Rate(A)=1/2
Rate(B)=1/3
Rate(C)=1/6

A + B - C

1/2 + 1/3 - 1/6 = 4/6 (Combined rate per the question)

Rate * Time = Work

4/6 * Time = 1/2

Time = 3/4
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Manager  Joined: 13 Aug 2009
Posts: 126
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Re: PS: Pool fills  [#permalink]

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5
2
12.At their respective rates, pump A, B, and C can fulfill an empty tank, or pump-out the full tank in 2, 3, and 6 hours. If A and B are used to pump-out water from the half-full tank, while C is used to fill water into the tank, in how many hours, the tank will be empty?
A. 2/3
B. 1
C. 3/4
D. 3/2
E. 2

let X = # of hours for the tank to empty

X*Rate A + X*Rate B - X*Rate C = 1/2 tank

X*(1/2) + X*(1/3) - X*(1/6) = 1/2
X = 3/4

It takes 3/4 hrs to empty the tank

Manager  Joined: 17 Mar 2009
Posts: 196
Re: PS: Pool fills  [#permalink]

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IanStewart wrote:
You can use a rates formula here, or convert each worker to the same amount of time (6 hours) :

A empties 3 tanks every 6 hours
B empties 2 tanks every 6 hours
C fills 1 tank every 6 hours
Together, they empty 4 tanks every 6 hours
So they empty 1 tank every 6/4 hours, and empty half of a tank in 3/4 hours. C.

that looks so simple and easy.. thanks Ian.
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Re: PS: Pool fills  [#permalink]

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Quote:
You can use a rates formula here, or convert each worker to the same amount of time (6 hours) :

A empties 3 tanks every 6 hours
B empties 2 tanks every 6 hours
C fills 1 tank every 6 hours
Together, they empty 4 tanks every 6 hours
So they empty 1 tank every 6/4 hours, and empty half of a tank in 3/4 hours. C.

Good job Ian. You made it all simple. _________________
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Will do anything for Kudos! Please feel free to give one. Manager  Joined: 15 Jun 2009
Posts: 95
Re: PS: Pool fills  [#permalink]

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3
2
Effective rate(empty) : 1/2+1/3-1/6 = 4/6 = 2/3

So whole tank will be emptied in 3/2 hrs..and half will be in 3/4 hrs. C...
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Re: PS: Pool fills  [#permalink]

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TGC wrote:
Rate(A)=1/2
Rate(B)=1/3
Rate(C)=1/6

A + B - C

1/2 + 1/3 - 1/6 = 4/6 (Combined rate per the question)

Rate * Time = Work

4/6 * Time = 1/2

Time = 3/4

Hi,

I could understand this method.
But my doubt is
Work = Rate * time
Time = Work / Rate

So as per this problem
Rate(A)=1/2
Rate(B)=1/3
Rate(C)=1/6

So total time is:
(1/2)/(1/2) + (1/2) / (1/3) - (1/2) / (1/6) = -1/2

thanks,
Rrsnathan.
Math Expert V
Joined: 02 Sep 2009
Posts: 58434
Re: PS: Pool fills  [#permalink]

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3
1
rrsnathan wrote:
TGC wrote:
Rate(A)=1/2
Rate(B)=1/3
Rate(C)=1/6

A + B - C

1/2 + 1/3 - 1/6 = 4/6 (Combined rate per the question)

Rate * Time = Work

4/6 * Time = 1/2

Time = 3/4

Hi,

I could understand this method.
But my doubt is
Work = Rate * time
Time = Work / Rate

So as per this problem
Rate(A)=1/2
Rate(B)=1/3
Rate(C)=1/6

So total time is:
(1/2)/(1/2) + (1/2) / (1/3) - (1/2) / (1/6) = -1/2

thanks,
Rrsnathan.

When adding rates you get combined rate not time. Also, why are you multiplying combined rate by 1/2?

At their respective rates, pump A, B, and C can fulfill an empty tank, or pump-out the full tank in 2, 3, and 6 hours. If A and B are used to pump-out water from the half-full tank, while C is used to fill water into the tank, in how many hours, the tank will be empty?
A. 2/3
B. 1
C. 3/4
D. 3/2
E. 2

Rate of A = 1/2 tank/hour;
Rate of B = 1/3 tank/hour;
Rate of C = 1/6 tank/hour.

Combined rate when A and B are used to pump-out water, while C is used to fill water into the tank is 1/2+1/3-1/6=2/3 tank hour.

So, to empty the full tank 3/2 hours (reciprocal of rate) are needed. To empty the half-full tank half of that time would be needed: 1/2*3/2=3/4 hours.

Hope it's clear.
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t*[C's rate - (A's rate+B's rate)] + current tank size = 0
t*[1/6 - (1/2+1/3)] + .5 = 0
t = 3/4
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Re: At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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2
Effective rate of A, B & C respectively

$$= \frac{1}{2} + \frac{1}{3} - \frac{1}{6}$$
(-ve as tank is getting empty)

$$= \frac{3+2-1}{6}$$

$$= \frac{4}{6}$$

$$= \frac{2}{3}$$

Time required for full tank $$= \frac{3}{2}$$

$$Time required for half tank = \frac{3}{2} * \frac{1}{2} = \frac{3}{4}$$

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Re: At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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Time required to half the tank by each = (time for full tank)/2
Therefore
A=1hour
B=3/2 hour
C=6/2 hour
Now A and B empties and C adds
=> 1/A + 1/B - 1/C = 1+2/3-2/6 =8/6=4/3
hence 3/4 ans
Intern  Joined: 14 May 2013
Posts: 1
Re: At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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Bunuel wrote:
rrsnathan wrote:
TGC wrote:
Rate(A)=1/2
Rate(B)=1/3
Rate(C)=1/6

A + B - C

1/2 + 1/3 - 1/6 = 4/6 (Combined rate per the question)

Rate * Time = Work

4/6 * Time = 1/2

Time = 3/4

Hi,

I could understand this method.
But my doubt is
Work = Rate * time
Time = Work / Rate

So as per this problem
Rate(A)=1/2
Rate(B)=1/3
Rate(C)=1/6

So total time is:
(1/2)/(1/2) + (1/2) / (1/3) - (1/2) / (1/6) = -1/2

thanks,
Rrsnathan.

When adding rates you get combined rate not time. Also, why are you multiplying combined rate by 1/2?

At their respective rates, pump A, B, and C can fulfill an empty tank, or pump-out the full tank in 2, 3, and 6 hours. If A and B are used to pump-out water from the half-full tank, while C is used to fill water into the tank, in how many hours, the tank will be empty?
A. 2/3
B. 1
C. 3/4
D. 3/2
E. 2

Rate of A = 1/2 tank/hour;
Rate of B = 1/3 tank/hour;
Rate of C = 1/6 tank/hour.

Combined rate when A and B are used to pump-out water, while C is used to fill water into the tank is 1/2+1/3-1/6=2/3 tank hour.

So, to empty the full tank 3/2 hours (reciprocal of rate) are needed. To empty the half-full tank half of that time would be needed: 1/2*3/2=3/4 hours.

Hope it's clear.

how did the reciprocal come. I mean 2/3 tank per hour into 3/2 I did not get that logic
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At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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Let’s say work = 12 then:
Rate A = 6
Rate B = 4
Rate C = 2
There combined rate $$= 6+4-2=8$$ and 50% of the tank $$=\frac{12}{2}=6$$, $$hence 8*t=6, \frac{t=3}{4}$$
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Re: At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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Economist wrote:
At their respective rates, pump A, B, and C can fulfill an empty tank, or pump-out the full tank in 2, 3, and 6 hours. If A and B are used to pump-out water from the half-full tank, while C is used to fill water into the tank, in how many hours, the tank will be empty?

A. 2/3
B. 1
C. 3/4
D. 3/2
E. 2

Let the volume of the tank be 12 units

Efficiency of tank A = -6 { -ve since they are pumpung out water}
Efficiency of tank B = -4 { -ve since they are pumpung out water}
Efficiency of tank C = 2

We are given the information that the tank is half filled, so 6 units is filled

Net/Effective work done by the 3 pipes is (-6)+ (-4) +(2) =>-8 units

So, the three pipes will drain out water and the time required to do the same from the half filled tank is 6/8 => 3/4

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At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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t=time to empty tank
t(1/6-5/6)=-1/2➡t(-2/3)=-1/2
t=3/4 hour
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Re: At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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lets set the equation as:
water in the tank + water pump in = water pump out

This will give you the following:
1/2 + 1/6(T) = (1/2)T + (1/3)T where T is the required time so that the tank is empty
solve for T,
you will get T = 3/4 hr

so the answer is C
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Re: At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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Economist wrote:
At their respective rates, pump A, B, and C can fulfill an empty tank, or pump-out the full tank in 2, 3, and 6 hours. If A and B are used to pump-out water from the half-full tank, while C is used to fill water into the tank, in how many hours, the tank will be empty?

A. 2/3
B. 1
C. 3/4
D. 3/2
E. 2

We can calculate the net outflow rate (i.e., the sum of the rates of A and B minus the rate of C) as:

1/2 + 1/3 - 1/6 = 3/6 + 2/6 - 1/6 = 4/6 = 2/3

Since only ½ of a tank needs to be emptied, the time it takes to do that is (1/2)/(2/3) = 1/2 x 3/2 = 3/4 hour.

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Re: At their respective rates, pump A, B, and C can fulfill an  [#permalink]

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_________________ Re: At their respective rates, pump A, B, and C can fulfill an   [#permalink] 19 Apr 2019, 04:38
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