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Brian spent 1/4 of his paycheck to repair his car, and then paid the

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Brian spent 1/4 of his paycheck to repair his car, and then paid the  [#permalink]

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New post 01 Nov 2018, 00:17
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Question Stats:

53% (01:07) correct 47% (02:00) wrong based on 17 sessions

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Brian spent 1/4 of his paycheck to repair his car, and then paid the registration and insurance, which each cost 1/4 of the remainder of his paycheck. If Brian had $0 before he was paid, and he now has $231 left, what was the amount of his paycheck?

A. $2772
B. $1622
C. $924
D. $870
E. $693

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Re: Brian spent 1/4 of his paycheck to repair his car, and then paid the  [#permalink]

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New post 01 Nov 2018, 01:56
Total amount = X.
Money spent on repair = X/4
Remaining = 3X/4
Money left after registration and Insurance = 3X/4-28 = 231
Solving X gives 345\(\frac{1}{3}\)

Bunuel. Are the options correct?
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Re: Brian spent 1/4 of his paycheck to repair his car, and then paid the  [#permalink]

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New post 01 Nov 2018, 05:08
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Bunuel: Is 14 supposed to be 1/4 by any chance?

If that is the case, 1-1/4 - 1/4 - 1/4 = 1/4 is left.
Let x be the paycheck
x/4 = 231
x = 924

Option C maybe!
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Re: Brian spent 1/4 of his paycheck to repair his car, and then paid the  [#permalink]

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New post 01 Nov 2018, 06:16
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Brian spent 1/4 of his paycheck to repair his car, and then paid the  [#permalink]

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New post Updated on: 02 Nov 2018, 21:22
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Im not sure- my answer doesnt match the given options at all. I think the issue may be in my interpretation of the registration and insurance.

Eg. paycheck= 100.
Repair= 25, remander= 75.

Is registration and insurance each 1/4 of 100 or 75? According to the question, it is the remainder, ie, 75.

-------------------------------------------

Let x be the total amount in the paycheck.
Repair= x/4
Registration and Insurance cost 1/4 of the remainder amount each= 3x/4 *1/4*2= 3x/8

x/4+3x/8+231=x
231= x-(x/4+3x/8)=(8x-5x)/8
231 (8)= 3x
x= 77*8= 616.


I did the recheck by plugging the answer.
Repair cost= 154
Insurance and Registration each= 115.5
615-154-115.5-115.5=231


Bunuel could you please advise.

Originally posted by taniad on 01 Nov 2018, 06:34.
Last edited by taniad on 02 Nov 2018, 21:22, edited 2 times in total.
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Re: Brian spent 1/4 of his paycheck to repair his car, and then paid the  [#permalink]

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New post 02 Nov 2018, 02:44
Brian spent 1/4 of his paycheck to repair his car, and then paid the registration and insurance, which each cost 1/4 of the remainder of his paycheck. If Brian had $0 before he was paid, and he now has $231 left, what was the amount of his paycheck?

A. $2772
B. $1622
C. $924
D. $870
E. $693

Let total paycheck be x
total expense = 3x/4

Amount left= x-3x/4=231
=> 231*4=924 option C
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Re: Brian spent 1/4 of his paycheck to repair his car, and then paid the  [#permalink]

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New post 02 Nov 2018, 15:07
Bunuel wrote:
Brian spent 1/4 of his paycheck to repair his car, and then paid the registration and insurance, which each cost 1/4 of the remainder of his paycheck. If Brian had $0 before he was paid, and he now has $231 left, what was the amount of his paycheck?

A. $2772
B. $1622
C. $924
D. $870
E. $693


Why the cost of the registration and insurance is not each 1/4 of the remainder pay check (3x/4)?

X= Total pay check

(1/4)*x + 2 * (1/4) * (3x/4) + 231 = x ??? x = 616

I think I am not understanding the English here....
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Re: Brian spent 1/4 of his paycheck to repair his car, and then paid the &nbs [#permalink] 02 Nov 2018, 15:07
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Brian spent 1/4 of his paycheck to repair his car, and then paid the

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