Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 02 Dec 2012
Posts: 178

Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
12 Dec 2012, 06:31
Question Stats:
71% (02:18) correct 29% (02:10) wrong based on 2372 sessions
HideShow timer Statistics
Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members? (A) 1 (B) 2 (C) 3 (D) 4 (E) 5
Official Answer and Stats are available only to registered users. Register/ Login.




Math Expert
Joined: 02 Sep 2009
Posts: 49251

Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
12 Dec 2012, 06:39
Walkabout wrote: Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?
(A) 1 (B) 2 (C) 3 (D) 4 (E) 5 3 members at one table and 4 members at each of the other tables, means that the total number of members is 3 more than a multiple of 4: x=4m+3. 3 members at one table and 5 members at each of the other tables, means that the total number of members is 3 more than a multiple of 5: x=5n+3. Thus x3 is a multiple of both 4 and 5, so a multiple of 20. Therefore x is 3 more than a multiple of 20. Since 10<x<40, then x=23. The remainder when 23 is divided by 6 is 5. Answer: E.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics




Intern
Joined: 21 Oct 2012
Posts: 25
GMAT Date: 01192013

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
18 Dec 2012, 13:20
It took me 2 minutes of understanding and stupid calculation: 1) 3+4n=x 7 11 15 19 23 27 31 35 39 2) 3+5m=x 8 13 18 23 28 33 38 X=23 only. 23 (mod 6)=5
_________________
MGMAT1  610 MGMAT2  670 MGMAT3  640
OMG




Intern
Joined: 24 Apr 2012
Posts: 48

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
14 Dec 2012, 03:16
Ans: let the number of people be n , now 10<n<40. Also n=(3+ multiple of 4) and n=(3+ multiple of 5). Therefore n3 is a multiple of both 4 and 5, one such number is 20. N=23, when 6 members sit at tables then people left are 5, therefore the answer is (E).
_________________
www.mnemoniceducation.com
TURN ON YOUR MINDS!!!



Intern
Joined: 26 Feb 2014
Posts: 2

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
30 Apr 2014, 06:26
I did it this way and also got to the correct answer... is my reasoning correct here?
3+4+4 = 11 members 3+5+5 = 13 members 6+x = needs to be more than 10 so x is minimum of 5
x=5



Manager
Joined: 28 Apr 2014
Posts: 235

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
01 May 2014, 02:15
Bunuel wrote: Bumping for review and further discussion. How much time should a question like this take in exam ?



Math Expert
Joined: 02 Sep 2009
Posts: 49251

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
01 May 2014, 09:43



Intern
Joined: 26 Oct 2013
Posts: 22

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
28 May 2014, 10:09
My solution:
10<Members of Club X<40
X=4q+3 X=5p+3
Therefore, general formula based on both statements is X= 20k+23 Thus according to this particular statement X could ONLY take as values 23
23/6 gives a remainder of 5
Answer: E



Retired Moderator
Joined: 29 Oct 2013
Posts: 272
Concentration: Finance
GPA: 3.7
WE: Corporate Finance (Retail Banking)

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
01 Jun 2014, 21:42
GDR29 wrote: Therefore, general formula based on both statements is X= 20k+23
Answer: E Is there a typo? Did u mean X= 20k+3?
_________________
Please contact me for super inexpensive quality private tutoring
My journey V46 and 750 > http://gmatclub.com/forum/myjourneyto46onverbal750overall171722.html#p1367876



Math Expert
Joined: 02 Sep 2009
Posts: 49251

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
02 Jun 2014, 01:10



Intern
Joined: 06 Jan 2013
Posts: 11
Location: United States
Concentration: Finance, Economics
GMAT Date: 11152013
GPA: 3.5
WE: Education (Education)

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
27 Aug 2014, 02:58
I did this the long way, wrote out the seating arrangements possible under each scenario and found that 23 people is the only situation which applies to both seat configurations. Then as the others have pointed out 23 / 6 = 3 remainder 5
Attachments
Tables.png [ 4.85 KiB  Viewed 29867 times ]



Manager
Joined: 07 Apr 2014
Posts: 117

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
11 Sep 2014, 12:27
Walkabout wrote: Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?
(A) 1 (B) 2 (C) 3 (D) 4 (E) 5 10<x<40 x= k4+3 ...11,15,19,23 x=a5+3...13,18,23 x=b6+? x= 23 then 23/6 = remainder = 5



Intern
Joined: 25 May 2014
Posts: 9

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
30 Oct 2014, 22:54
Simple solution quickly would be  E We know that the remainder is 3 in both cases when 4 or 5 people sit > such one number is 23 (which also is between 20 and 40). And hence, 23/6 gives remainder =5 .



Intern
Joined: 24 Jan 2014
Posts: 35
Location: France
Concentration: General Management, International Business
GPA: 3
WE: General Management (Advertising and PR)

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
29 Mar 2015, 02:32
I got tricked by "tables" in the problem stem and I considered more than 1 table of 3 person eacg. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables... Isn't the problem poorly worded?
_________________
THANKS = KUDOS. Kudos if my post helped you!
Napoleon Hill — 'Whatever the mind can conceive and believe, it can achieve.'



Intern
Joined: 16 Feb 2015
Posts: 4

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
15 Jun 2015, 18:21
I got 5 as my answer.
For people that are more visual (like me)..
I put a 3 down and another 3 down representing the first two tables, then figured out how many "4s" were needed for the first set and how many "5s" were needed for the second set to add up and equal to the same number for both sets. Since 3 was constant between the two sets, it meant that 4 and 5 needed to have the same number of people, or the LCM, which is 20. Therefore 20 plus 3 is a total of 23 people.
Now you know that the table with a set of 6s needs to add up to 23, but the last table needs to still be less than 6. So the only combination for 6s is 3 tables of 6 people to equal 18 and then a table of 5 people.



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8281
Location: Pune, India

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
15 Jun 2015, 23:17
TudorM wrote: I got tricked by "tables" in the problem stem and I considered more than 1 table of 3 person eacg.
Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables...
Isn't the problem poorly worded? No, it isn't. This is GMAT language  especially considering that the question is official  and hence you will be required to successfully comprehend such questions. "Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables," The statement explains how the members sit at tables: 3 at ONE table and 4 at EACH of the other tables. Practice questions from the official guide to get comfortable with "GMAT language".
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >
GMAT selfstudy has never been more personalized or more fun. Try ORION Free!



Intern
Joined: 11 Nov 2014
Posts: 37
Concentration: Marketing, Finance
WE: Programming (Computer Software)

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
11 May 2016, 00:35
10<x<40 in both cases 3 members sit on one table remaining members = x3 so 7<x3<37 x3 should be multiple of 4 and 5 to fit all members perfectly on tables. between 7 and 37 only 20 is such number. x3 = 20 x= 23 If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table => 23/6 remainder > 5



Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 3497
Location: United States (CA)

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
11 May 2016, 07:05
Walkabout wrote: Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?
(A) 1 (B) 2 (C) 3 (D) 4 (E) 5 Although this problem appears to be a general word problem it is actually testing us on our understanding of remainders when dividing integers. We are first told that the total number of members, which we can denote as “T”, is between 10 and 40. Next, we are told two important pieces of information: 1) “Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables.” 2) “Sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables.” Let’s now translate these into two mathematical expressions. 1) T/4 = Quotient + Remainder 3 2) T/5 = Quotient + Remainder 3 Because T is being divided by 4 and 5, we are really looking for the following: T/20 = Quotient + remainder 3. Since T must be between 10 and 40, there is only one value in that range which, when divided by 20, produces a remainder of 3. That value is 23. We can now use this value to complete the question. We are finally asked: “If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?” This is same as asking the following: what is the remainder when 23 is divided by 6? We can see that 6 divides into 23 3 times with a remainder of 5. Answer: E.
_________________
Scott WoodburyStewart
Founder and CEO
GMAT Quant SelfStudy Course
500+ lessons 3000+ practice problems 800+ HD solutions



Intern
Joined: 22 Dec 2015
Posts: 42

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
14 May 2016, 22:36
If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table What does the statement above means? specially the "Except one". I got tricked by it thinking that 22 (23 except 1 or 221) members were seated with 6 members at each table



Math Expert
Joined: 02 Aug 2009
Posts: 6787

Re: Club X has more than 10 but fewer than 40 members. Sometimes
[#permalink]
Show Tags
14 May 2016, 23:09
powellmittra wrote: If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table What does the statement above means? specially the "Except one". I got tricked by it thinking that 22 (23 except 1 or 221) members were seated with 6 members at each table hi Quote: If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table this tells us that if there were x tables, x1 tables had 6 members on those table and <6, say y, on the ONE remaining table.. MEANS  y is the remainder when you divide TOTAL by 6
_________________
1) Absolute modulus : http://gmatclub.com/forum/absolutemodulusabetterunderstanding210849.html#p1622372 2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html 3) effects of arithmetic operations : https://gmatclub.com/forum/effectsofarithmeticoperationsonfractions269413.html
GMAT online Tutor




Re: Club X has more than 10 but fewer than 40 members. Sometimes &nbs
[#permalink]
14 May 2016, 23:09



Go to page
1 2
Next
[ 38 posts ]



