The answer has to be B, but I'm getting a slightly different number when I do the math.
First, we know
n number of employees is odd. That is reinforced when we see the median value is the 16th salary on the list. That means that the total number of employees is (16*2)-1 = 31 total employees.
$942,000 divided by 31 is just under $30,400. I guess since no one employee has the same annual salary, this accounts for the difference, but I'm probably missing something.
puma wrote:
Company A has a total of n emloyees, where n is an odd integer, and no two employees have the same annual salary. The annual salary of the n employees are listed in increasing order, and the 16th salary in the list is the median of the annual salaries. If the sum of the annual salaries of Company A's employees is $942,000, what is the average (arithmetic mean) of the annual salaries of Company A's employees?
a) $29,450
b) $30,400
c) $32,500
d) $47,120
e) $58,900
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J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.
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