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Eco Wildlife Preserve contains 5x zebras and 2x lions
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20 Sep 2013, 14:55

5

6

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

67% (01:53) correct 33% (02:15) wrong based on 289 sessions

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Eco Wildlife Preserve contains 5x zebras and 2x lions, where x is a positive integer. If the lions succeed in killing z of the zebras, is the new ratio of zebras to lions less than 2 to 1 ?

Eco Wildlife Preserve contains 5x zebras and 2x lions, where x is a positive integer. If the lions succeed in killing z of the zebras, is the new ratio of zebras to lions less than 2 to 1 ?

The question asks: is \(\frac{5x-z}{2x}<\frac{2}{1}\)? --> is \(x<z\)?

Eco Wildlife Preserve contains 5x zebras and 2x lions, where x is a positive integer. If the lions succeed in killing z of the zebras, is the new ratio of zebras to lions less than 2 to 1 ?

(1 ) z > x (2 ) z = 4

I did by picking numbers. In option 1 the equation (5x-z)/2x is always less than 2 no matter what values of x and z you pick. In option 2 we only have one value and this is not sufficient
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Eco Wildlife Preserve contains 5x zebras and 2x lions, where x is a positive integer. If the lions succeed in killing z of the zebras, is the new ratio of zebras to lions less than 2 to 1 ?

(1 ) z > x (2 ) z = 4

When you modify the original condition and the question, they become (5x-z):2x<2:1?, (5x-z)/2x<2?, 5x-z<4x?, x<z?. Therefore, the answer is A.

-> Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
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Hello a quick query for resolution. here is a DS question :-

A forest has 5x zebras and 2x lions Lions kill z number of the zebras, is the new ratio of zebras to lions less than 2 to 1 ? (1) z > x (2) z = 4

MY approach ORIGINAL RATIO = # of zebras : # of lions = 5x : 2x Now am I wrong in cancelling x from both num. and denom. at this stage? Should I keep the expression (5x : 2x) and work with x or should I cancel out x and simplify work forward with (5 : 2)

my next step is NEW RATIO = # of surviving zebras : # of lions

5x-z : 2x < 2: 1

or

5-z : 2 < 2: 1

AND THEN SOLVE STATEMENTS A AND B

Thanks in advance
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Posting an answer without an explanation is "GOD COMPLEX". The world doesn't need any more gods. Please explain you answers properly. FINAL GOODBYE :- 17th SEPTEMBER 2016. .. 16 March 2017 - I am back but for all purposes please consider me semi-retired.

Re: COMBINATION OF RATIO AND INEQUALITY
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09 Jun 2016, 19:27

1

LogicGuru1 wrote:

Hello a quick query for resolution. here is a DS question :-

A forest has 5x zebras and 2x lions Lions kill z number of the zebras, is the new ratio of zebras to lions less than 2 to 1 ? (1) z > x (2) z = 4

MY approach ORIGINAL RATIO = # of zebras : # of lions = 5x : 2x Now am I wrong in cancelling x from both num. and denom. at this stage? Should I keep the expression (5x : 2x) and work with x or should I cancel out x and simplify work forward with (5 : 2)

my next step is NEW RATIO = # of surviving zebras : # of lions

5x-z : 2x < 2: 1

or

5-z : 2 < 2: 1

AND THEN SOLVE STATEMENTS A AND B

Thanks in advance

Hi,

ratio is correct if you are dealing only in ratios of various things but not when you have some numeric value... this Q has number z, so you will have to work on 5x, because z are going out of 5x and not 5.. so\(\frac{5x-z}{2x}< \frac{2}{1}......5x-z<4x.........x<z\) so we are looking for is x<z.. statement I gives you that info so suff....
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Eco Wildlife Preserve contains 5x zebras and 2x lions, where x is a positive integer. If the lions succeed in killing z of the zebras, is the new ratio of zebras to lions less than 2 to 1 ?

(1 ) z > x (2 ) z = 4

Once Lions kill zebras.

\(\frac{Zebras}{Lions}\) = \(\frac{5x-z}{2x}\)

If \(\frac{5x-z}{2x}\) < \(\frac{2}{1}\)

Then (since x and z have to be positive values, we can cross multiply)

5x-z < 4x

x < z--> We will check options if this condition is satisfied

We find that Statement 1 is sufficient.

Statement 2 is not sufficient because it dies not say anything about x.

Eco Wildlife Preserve contains 5x zebras and 2x lions, where x is a positive integer. If the lions succeed in killing z of the zebras, is the new ratio of zebras to lions less than 2 to 1 ?

(1 ) z > x (2 ) z = 4

Given: Eco Wildlife Preserve contains 5x zebras and 2x lions, where x is a positive integer. The lions kill z of the zebras

Target question:Is the new ratio of zebras to lions less than 2 to 1 ?

This is the perfect candidate for rephrasing the target question.

ASIDE: If we take the time to rephrase the question in a simpler form, then we can save a ton of time evaluating the statements.

The NEW population of zebras is 5x - z

So, we can ask "Is (5x - z)/2x < 2/1?"

Not bad, but we can go much further than this!.

Since 2x is POSITIVE, we can safely take (5x - z)/2x < 2/1 and multiply both sides by 2x. When we do this, we get: 5x - z < 4x Subtract 4x from both sides: x - z < 0 Add z to both sides: x < z

So, we can write.... REPHRASED target question:Is x < z?

Now onto the statements....

Statement 1: z > x Perfect!! The answer to the REPHRASED target question is YES, x < z! Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: z = 4 Given this information, there is no way to conclude whether x < z Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT