For consecutive even integers a and b, a > b. If a2+b2=340a2+b2=340, which of the following could be the value of a?

A. -14

B. -12

C. -8

D. 12

E. 16

Note that all the answers are values and none of them is like it cannot be determined. So we can put the values and test the values for answer

(P.S: I found it easier to solve this by testing the values rather than by solving algebraically)A. a= -14, b= -16 since a > b

so, a^2+b^2 = 196 + 256 = 452

B. a= -12, b= -14 since a > b

so, a^2+b^2 = 144 + 196 = 340 .....

Hence B is the ANSWERC. a= -8, b= -10 since a > b

so, a^2+b^2 = 64 + 100 = 164

D. a= 12, b= 10 since a > b

so, a^2+b^2 = 144 + 100 = 244

E. a= 16, b= 14 since a > b

so, a^2+b^2 = 256 + 196 = 452

Thanks in advance for the Kudos I will receive