ziyuenlau
For consecutive integers \(x\) and \(y\), where \(x>y\), what is the value of \(x\)?
(1) \(x^2−y^2=37\)
(2) \(x^2+y^2=685\)
Target question: What is the value of x? Given: x and y are CONSECUTIVE integers, and x > y Since x and y are consecutive integers, and since x is bigger than y, we can conclude that y is ONE LESS than x.
In other words,
y = x - 1 Statement 1: x² - y² = 37 Take this equation, and replace y with
x - 1 to get: x² - (
x - 1)² = 37
Expand: x² - (x² - 2x + 1) = 37
Simplify: 2x - 1 = 37
Solve to get:
x = 19PERFECT!
Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: x² + y² = 685 Take this equation, and replace y with
x - 1 to get: x² + (
x - 1)² = 685
Expand: x² + (x² - 2x + 1) = 685
Simplify: 2x² - 2x + 1 = 685
Subtract 685 from both sides to get: 2x² - 2x - 684 = 0
Divide both sides by 2 to get: x² - x - 342 = 0
Factor to get: (x - 19)(x + 18) = 0
So, EITHER
x = 19 OR
x = -18Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
ASIDE: Notice that
x = 19 and
x = -18 both satisfy statement 2.
If x = 19, then y = 18, in which case x² + y² = 19² + 18² = 685
If x = -18, then y = -19, in which case x² + y² = (-18)² + (-19)² = 685
Answer: A
Cheers,
Brent