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Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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24 Jul 2015, 01:13
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Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
Solution -
Its given that, (m – r) > (s – n), which is equivalent to (m + n) > (r + s). So we need to determine the inequality holds true or false.
Stmt1 - 250 > r + s --> From the question m + n = 250, so the inequality m + n > r + s is true. Sufficient.
Stmt2 - m + r + s = 375 --> We know that m + n = 250 and m > n, m must be greater than 125. Subtracting 125 from 375 yields 250, so if m is greater than 125, then r + s must be smaller than 250. So the inequality m + n > r + s is true. Sufficient. ANS D
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Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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24 Jul 2015, 02:59
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Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
Given, m>n, m+n=250
Question: is (m – r) > (s – n)? or is (m+n)>(s+r) ---> s+r<250 ?
Statement 1 , sufficient to say yes fr s+r<250.
Statement 2, m+r+s=375 ---> assuming (m – r) > (s – n) ---> m+n>375-m ---> 2m+n>375 or n >375-2m and n = 250-m
Thus, 250-m > 375-2m --- m >125
Thus, if m+n = 250 and m >125 ---> m>n which is a give. Thus our assumption above of (m – r) > (s – n) holds TRUE. Thus this statement is sufficient as well.
Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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26 Jul 2015, 11:49
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1
Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
800score Official Solution:
Statement (1) tells us that 250 > r + s. Since the question statement tells us that m + n = 250, we can determine that m + n > r + s.
Now, let us manipulate this inequality to see whether it is equivalent to the inequality in the question: (m + n) > (r + s) m > (r + s) – n (m – r) > (s – n)
This is exactly what we were looking for. We can answer the question using Statement (1), hence it is sufficient.
Statement (2) tells us that m + r + s = 375. Because we know that m + n = 250 and m > n, m must be greater than 125. Subtracting 125 from 375 yields 250, so if m is greater than 125, then r + s must be smaller than 250. We are now left with the same inequality that we were given in Statement (1), which can be manipulated to show that (m – r) > (s – n). So Statement (2) is also sufficient.
Since both statements are sufficient alone, the correct answer is choice (D). _________________
Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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09 Sep 2016, 13:25
Top Contributor
Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
Target question:Is (m - r) > (s - n)?
This is a great candidate for rephrasing the target question. We have a video on this at the bottom of this post
If we take the inequality in the target question and add r and n to both sides, we get . . . REPHRASED target question:Is (m + n) > (s + r)?
Since m + n = 250, we can also rephrase it this way . . . REPHRASED target question:Is 250 > (s + r)?
Given Information: m + n = 250 and m > n If m and n were EQUAL, then m and n would both equal 125 Since m is GREATER THAN n, we can conclude that m > 125
Statement 1: 250 > r + s Perfect! One of our REPHRASED target questions is Is 250 > (s + r)? Since statement 1 allows us to answer the REPHRASED target question with certainty, it is SUFFICIENT
Statement 2: m + r + s = 375 Earlier (in the Given Information part of the solution), we determined that m > 125 So, we can reword statement 2 as: (a number bigger than 125) + (r + s) = 375 This means that (r + s) must be LESS THAN 250 In other words, 250 > (s + r) One of our REPHRASED target questions is Is 250 > (s + r)? Since statement 2 allows us to answer the REPHRASED target question with certainty, it is SUFFICIENT
Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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10 Sep 2016, 03:21
Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
From the question stem we have to prove that s+r< 250 1. SUFFICIENT 2. m+r+s =375, m+n= 250 i.e. r+s=125+n, now it is given that m > n. So maximum value of n can be 124. Hence we use n=124 r+s would be 249 <250. Hence SUFFICIENT Correct answer is D.
Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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11 Sep 2016, 13:07
Hello Bunuel,
I have a doubt. Please help me see what am I missing...
m, n, r, and s are integers-> nowhere it's mentioned that it is positive integer, it can as well be negative integer... in that case how can we reduce the equation (m – r) > (s – n) into (m + n) > (r + s)
thanks
Bunuel wrote:
Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
800score Official Solution:
Statement (1) tells us that 250 > r + s. Since the question statement tells us that m + n = 250, we can determine that m + n > r + s.
Now, let us manipulate this inequality to see whether it is equivalent to the inequality in the question: (m + n) > (r + s) m > (r + s) – n (m – r) > (s – n)
This is exactly what we were looking for. We can answer the question using Statement (1), hence it is sufficient.
Statement (2) tells us that m + r + s = 375. Because we know that m + n = 250 and m > n, m must be greater than 125. Subtracting 125 from 375 yields 250, so if m is greater than 125, then r + s must be smaller than 250. We are now left with the same inequality that we were given in Statement (1), which can be manipulated to show that (m – r) > (s – n). So Statement (2) is also sufficient.
Since both statements are sufficient alone, the correct answer is choice (D).
_________________
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Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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12 Sep 2016, 03:25
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1
DaenerysStormborn wrote:
Hello Bunuel,
I have a doubt. Please help me see what am I missing...
m, n, r, and s are integers-> nowhere it's mentioned that it is positive integer, it can as well be negative integer... in that case how can we reduce the equation (m – r) > (s – n) into (m + n) > (r + s)
thanks
Bunuel wrote:
Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
800score Official Solution:
Statement (1) tells us that 250 > r + s. Since the question statement tells us that m + n = 250, we can determine that m + n > r + s.
Now, let us manipulate this inequality to see whether it is equivalent to the inequality in the question: (m + n) > (r + s) m > (r + s) – n (m – r) > (s – n)
This is exactly what we were looking for. We can answer the question using Statement (1), hence it is sufficient.
Statement (2) tells us that m + r + s = 375. Because we know that m + n = 250 and m > n, m must be greater than 125. Subtracting 125 from 375 yields 250, so if m is greater than 125, then r + s must be smaller than 250. We are now left with the same inequality that we were given in Statement (1), which can be manipulated to show that (m – r) > (s – n). So Statement (2) is also sufficient.
Since both statements are sufficient alone, the correct answer is choice (D).
We are concerned about the sign of a number when multiplying/dividing an inequality by that number. However we can safely add/subtract a number from both sides of an inequality, which is done in that example: add n+r to both sides of (m – r) > (s – n) to get (m + n) > (r + s).
Re: For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r)
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01 Oct 2016, 20:42
Bunuel wrote:
For the integers m, n, r, and s, if m + n = 250 and m > n, is (m – r) > (s – n)?
(1) 250 > r + s (2) m + r + s = 375
Kudos for a correct solution.
To prove : m-r > s-n => m-r+n > s => m+n > s+r => 250 > s+r or s+r < 250 Also from the question stem m+n = 250 , m > n so maximum value for n can be 124 and minimum value of m can be 126
1. 250 > r+s ...... sufficient 2. m + r + s = 375 r + s = 375 - m
lets take minimum value of m ie 126 as this will give us maximum value of r+s
r + s = 375 - 126 => r + s = 249 => r + s < 250 This is also sufficient
close
48% (02:18) correct 
