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Given a<0, what is another way of expressing -ax<1?

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Given a<0, what is another way of expressing -ax<1?  [#permalink]

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New post 16 Jan 2019, 06:48
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Given a<0, what is another way of expressing -ax<1?

A) x<1/a
B) x>1/a
C) x<-1/a
D) x>-1/a
E) x<1
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Re: Given a<0, what is another way of expressing -ax<1?  [#permalink]

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New post 16 Jan 2019, 06:54
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Re: Given a<0, what is another way of expressing -ax<1?  [#permalink]

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New post 16 Jan 2019, 06:56
Bunuel, how is it different to b?
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Re: Given a<0, what is another way of expressing -ax<1?  [#permalink]

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New post 16 Jan 2019, 07:03
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philipssonicare wrote:
Bunuel, how is it different to b?


You multiply only right hand side by -1 change the sign and leave left hand side as is

x<-1/a multiply by -1 is -x>1/a
not
x>1/a
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Re: Given a<0, what is another way of expressing -ax<1?  [#permalink]

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New post 16 Jan 2019, 07:04
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Re: Given a<0, what is another way of expressing -ax<1?   [#permalink] 16 Jan 2019, 07:04
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Given a<0, what is another way of expressing -ax<1?

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