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Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added

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Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 11 Nov 2018, 23:37
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Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the value of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0

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Krunali Gokani
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 11 Nov 2018, 23:45
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KrunaliG wrote:
Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the view of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0

Posted from my mobile device



SD is minimised by having maximum terms at the mean.
The mean of 5,10,15,20, 25 is 15.

So the new number should be 15 too so that the SD does not increase but in fact decreases to get the minimum SD.

Answer (B)

Note: When you post a question, please ensure that you write it verbatim. Also, use the standard format of putting down options (A) (B) etc. A - makes one think that the numbers are negative.

For more on SD, check: https://www.veritasprep.com/blog/2012/0 ... deviation/
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 11 Nov 2018, 23:48
VeritasKarishma wrote:
KrunaliG wrote:
Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the view of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0

Posted from my mobile device



SD is minimised by having maximum terms at the mean.
The mean of 5,10,15,20, 25 is 15.

So the new number should be 15 too so that the SD does not increase but in fact decreases to get the minimum SD.

Answer (B)

Note: When you post a question, please ensure that you write it verbatim. Also, use the standard format of putting down options (A) (B) etc. A - makes one think that the numbers are negative.



Thank you so much for such a brief solution!
And yes will take care of the note too, thank you for the guidance.
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Krunali Gokani
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 12 Nov 2018, 00:20
KrunaliG wrote:
VeritasKarishma wrote:
KrunaliG wrote:
Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the view of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0

Posted from my mobile device



SD is minimised by having maximum terms at the mean.
The mean of 5,10,15,20, 25 is 15.

So the new number should be 15 too so that the SD does not increase but in fact decreases to get the minimum SD.

Answer (B)

Note: When you post a question, please ensure that you write it verbatim. Also, use the standard format of putting down options (A) (B) etc. A - makes one think that the numbers are negative.



Thank you so much for such a brief solution!
And yes will take care of the note too, thank you for the guidance.


Sure! Check out the link I have provided. You will find it useful.
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 09 Jan 2019, 04:30
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KrunaliG wrote:
Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the view of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0


Dear Moderator,
Just came across this question, the term "view" confused me a lot , then I realized it was meant to be " Value ", seems this is a typo. Hope you will look into this and do the needful. Thank you.
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 09 Jan 2019, 04:35
stne wrote:
KrunaliG wrote:
Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the view of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0


Dear Moderator,
Just came across this question, the term "view" confused me a lot , then I realized it was meant to be " Value ", seems this is a typo. Hope you will look into this and do the needful. Thank you.

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Edited. Thank you.
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 09 Jan 2019, 05:21
Please remove the - sign on the answer choices! They look like a negative sign

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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 16 Mar 2019, 08:21
Bunuel wrote:
stne wrote:
KrunaliG wrote:
Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the view of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0


Dear Moderator,
Just came across this question, the term "view" confused me a lot , then I realized it was meant to be " Value ", seems this is a typo. Hope you will look into this and do the needful. Thank you.

___________________
Edited. Thank you.



Why Option D is wrong ?
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added  [#permalink]

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New post 22 Mar 2019, 05:59
VeritasKarishma wrote:
KrunaliG wrote:
Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added in the list, what will be the view of X so that the standard deviation (S.D.) of the final list of 6 terms is minimum?

A - 20
B - 15
C - 30
D - 10
E - 0

Posted from my mobile device



SD is minimised by having maximum terms at the mean.
The mean of 5,10,15,20, 25 is 15.

So the new number should be 15 too so that the SD does not increase but in fact decreases to get the minimum SD.

Answer (B)

Note: When you post a question, please ensure that you write it verbatim. Also, use the standard format of putting down options (A) (B) etc. A - makes one think that the numbers are negative.

For more on SD, check: https://www.veritasprep.com/blog/2012/0 ... deviation/


Responding to a pm:
Quote:
Why option D is wrong ?


SD is minimised not by minimising the numbers but bringing them as close as possible to the average.
Here, the average is 15. The option closest to the average is 15. Hence it is correct.
Adding 10 instead will increase the SD. Check the link on the Veritas Prep blog I have mentioned above.
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Re: Given a list of 5 terms as: 5,10,15,20 and 25. A 6th Term X is added   [#permalink] 22 Mar 2019, 05:59
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