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Bunuel
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IMO C

x>0, y>0
x and y not both even
case 1: x=even, y=odd
case 2: x=odd, y = even
case 3: x=odd, y=odd

A. x/y
for case 1: even/odd = may be even integer or decimal
eg: x=6, y=3 x/y = 2
for case 2: x/y = odd/even - not an integer

B. 3xy
for case1 and case2 - 3*even*odd = even

C. 2xy - 1
for all cases 2*number = even
even -1 (odd) = odd
Correct

D. x + y
for case 3: odd + odd = even

E. x - y
for case 3: odd - odd = even
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Either one will be odd or both will be odd

A. x/y : 12/3 = 4. Eliminate

B. 3xy : 3*2*1 = 6 Eliminate

C. 2xy - 1: irrespective of the values of x&y, 2xy will be even, so even-odd = odd. Correct

D. x + y: can be odd/even. Eliminate

E. x - y: can be odd/even. Eliminate

IMO Option C
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Imo-C

Either x or y is even or both are odd integer
2xy-1
Even*odd*odd =even
Or
Even*even*even= even
And
Even -1 = odd

Posted from my mobile device
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given, positive integers x and y are not both even, So, x, y can be (odd,odd), (even,odd) or (odd,even).

A. x/y -> Not sure, if integer.
B. 3xy -> Not always odd.
C. 2xy - 1 -> even-odd= odd always.
D. x + y -> odd +odd = even, Not always odd.
E. x - y ->odd -odd = even, Not always odd.

So, I think C. :)
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2 possibilities

1 is even and the other odd
2 are odds

2xy is even whatever x and y are. So an even number minus 1 is always odd

PUSH C
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Correct Answer C

If positive integers x and y are not both even, which of the following must be odd?
Means
x----------Y
odd------odd
Even-----odd
odd (O)-------Even(E)


A. x/y
-Maybe a fraction

B. 3xy
3 *O*O =O
3 *E*O =E
3 *O*E =E


C. 2xy - 1
2 *O*O -O =O
2 *E*O -O =O
2 *O*E -O =O


D. x + y
O+O =E
E+O =O
O+E =O

E. x - y
O-O =E
E-O =O
O-E =O
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We are given,
x and y are positive integers
They are not both even so they can be either even or odd or they can both be odd. Now lets evaluate the answer choices:
A. x/y will be odd if both x and y are odd and even if they are odd-even number pair
B. 3xy will be odd if both x and y are odd, and even if they are odd-even number pair
C. 2xy - 1 will be always odd because 2xy will be always even and subtracting an odd number from even number gives odd number.
D. x + y will be even if both x and y are odd and odd if they are odd-even number pair
E. x-y will be even if both x and y are odd and odd if they are odd-even number pair

Hence the answer will be C
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