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17 Jul 2024, 06:33
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let B1=6 inches long and 9 inches high
B2= 6 inches long and 9 inches high
volume of B1=6*9*w
volume of B2=6*9*w
area of B1=6*w
area of B2=6*w
Area = 2 π r h + 2 π r 2 Where radius of the circular base Height
V o l u m e = π r 2 h
then B1 =24.5 square
B2= 32.75 square
B2= 6 inches long and 9 inches high
volume of B1=6*9*w
volume of B2=6*9*w
area of B1=6*w
area of B2=6*w
Area = 2 π r h + 2 π r 2 Where radius of the circular base Height
V o l u m e = π r 2 h
then B1 =24.5 square
B2= 32.75 square
said.tojiboev
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17 Jul 2024, 06:37
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Bunuel
The formula for the volume of a cuboid is Volume=length×width×height
- Length = 6 inches
- Height = 9 inches
- Width is derived from the base area.
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17 Jul 2024, 06:45
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Bunuel
For smaller box
6*9*w
6*w = 24.5
W=4.1
Cost
6*4.1*9*2 = 441
For bigger box
6*9*w1
6*w1 =32.75
Cost
6*9*5.45*2 = 589
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