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­Base area = 24.5
Volume = Base area x height = 24.5 * 9 = 220.5
Cost = Volume * 2 = 441

Base area = 32.75
Volume = Base area x height = 32.75 * 9 = 294.75
Cost = Volume * 2 = 589.50

So, we choose 440 and 590
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­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.

volume of 1st cuboid = 24.5*9 =220.5
cost = 220.5*2 = 441 approximated to $440

volume of 2nd cuboid = 32.75*9 =294.75
cost = 294.75*2 = 589.5 approximately $ 590
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­Base area 24.5 square inches
Volume = 24.5*9 = 220.5
Cost = 220.5*2 = 441

Base area 32.75 square inches
Volume = 24.5*9 = 294.75
Cost = 220.5*2 = 589.5

Base area 24.5 square inches: 440
Base area 32.75 square inches: 590
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Step 1: Understand the given information
- Both boxes are 6 inches long and 9 inches high
- They differ in width
- Price is $2 per cubic inch
- Volume formula: length x width x height
- Base area formula: length x width

Step 2: Calculate the width for each box
Box 1: Base area = 24.5 sq inches
24.5 = 6 x width
Width = 24.5 / 6 = 4.083 inches

Box 2: Base area = 32.75 sq inches
32.75 = 6 x width
Width = 32.75 / 6 = 5.458 inches

Step 3: Calculate the volume of each box
Box 1: 6 x 4.083 x 9 = 220.482 cubic inches
Box 2: 6 x 5.458 x 9 = 294.732 cubic inches

Step 4: Calculate the cost of each box
Box 1 (24.5 sq inches): 220.482 x $2 =~ $440
Box 2 (32.75 sq inches): 294.732 x $2 =~ $590
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­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.



Solution: Length of each box = 6 inches
Height of each box = 9 inches

Base area of Box 1 = 24.5 sq. inches
Base area of Box 2 = 32.75 sq. inches

Since Volume of cuboid = Length x Width x Height
Or Volume = Base Area x Height

Volume of Box 1 = 24.5 x 9 = 220.5 cubic inches
Price per box = $2 per cubic inch
Total Price for Box 1 = $220.5 x 2
Approx. Price of Box with Base area 24.5 sq. inches = $440

Volume of Box 2 = 32.75 x 9 = 294.75 cubic inches
Price per box = $2 per cubic inch
Total Price for Box 1 = $294.75 x 2
Approx. Price of Box with Base area 32.75 sq. inches = $590

 ­
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Bunuel
­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.


­
 


This question was provided by Experts' Global
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­

Since the base areas that are given are in terms of length x width, to calculate volume, we’ll multiply both of them by height, which is 9 inches.

Cuboid with base area 24.5 square inches has the volume= 24.5 * 9 = 220.5 cubic inches
Thus cost at the rate of $2 per cubic inch will be= 220.5 * 2 = 441 ≈ $440

Cuboid with base area 32.75 square inches has the volume= 32.75 * 9 = 294.75 cubic inches
Thus cost at the rate of $2 per cubic inch will be= 294.75 * 2 = 589.5≈ $590

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Volume of cuboid is length x width x height

base area 24.5 square inches
length x width x height * 2 (length x width = 24.5)
= 24.5 * 9 * 2 = 441

base area 32.75 square inches
=  32.75 * 9 * 2  = 589.5

Therefore, the ans choices are 440 and 590 for base area 24.5 square inches and base area 32.75 square inches respectively. 
 ­
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Bunuel
­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.


­
 


This question was provided by Experts' Global
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­
­Box A: Volume = 6 * x * 9 ; Base Area = 6 * x = 24.5; Total Volume = 24.5 * 9
Box B: Volume = 6 * y * 9; Base Area = 6 * y = 32.75; Total Volume = 32.75 * 9
Cost per cubic inch = 2 dollars
Cost of A= 24.5 * 9 * 2 = 441 ~440
Cost of B = 32.75 * 9 * 2 = 589.5 ~590
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Bunuel
­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.


­
 


This question was provided by Experts' Global
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­
­l = 6 in
h = 9 in
w = ?

Volume = l * h * w
Base area = l * w

cost = $2 per cubic inch

=> Volume = base area * h = base area * 9

1) base area 24.5 square inches
=> Cost = Volume * 2
=> Cost = 24.5 * 9 * 2
=> Cost ~ $440

2) base area 32.75 square inches

=> Cost = Volume * 2
=> Cost = 32.75 * 9 * 2
=> Cost ~ $590

 
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Bunuel
­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.


 
­Volume of first cuboid = 24.5 * 9 = 220.5
Cost = 220.5 * 2 = 441 ~ 440

Volume of second cuboid = 32.75 * 9 = 294.75
Cost = 294.75 * 2 = 589.5 ~ 590­
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Quote:
­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.
Height = 9 inch

Volume = base area*height

Cost = 2*volume = 2*9*base area => 18*base area

Small Box = 18*24.5 = 441 ~ 440$

Large Box = 18*32.75 = 589.5 ~ 590$
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­Cost of one box of base area 24.5 square inches:
\(length * width * height* cost/per sq.in. = 24.5*9*2 = 440 \)

Cost of one box of base area 32.75 square inches­
\(length * width * height* cost/per sq.in. = 32.75*9*2 = 590 \)­
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Given

The boxes are priced by volume at $2 per cubic inch.
Base Area= length x width

Height is common =9 inches

base Area of box1 =24.5 square inches
base Area of box2 =32.75 square inches

Volume of Box1=24.5*9 cubic inch
Volume of Box2=32.75*9 cubic inch

Cost of Box1=24.5*9*2=$441
Cost of Box2=32.75*9*2=$589.5

Ans-CE.
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\(\text{Volume = l*w*h}\)

\(\text{Base Area, a = l*w}\)

Cost of box \(= $2*Volume = 2*l*w*h=2*a*h\)

\(\text{l=6 in, h=9 in}\)

Cost of Box 1 with a=24.5 \(in^2\), approx 25 \(in^2\)

\(\text{Cost of box 1}= 2*25*9=450\)

Cost of Box 2 with a=32.75 \(in^2\), approx 33 \(in^2\)

\(\text{Cost of box 2}= 2*33*9=594\)

The closest options to the answers are C. 440 & E. 590
 ­
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Bunuel
­A retailer needs to purchase cuboidal boxes of two different sizes. The boxes are both 6 inches long and 9 inches high but differ in width. The boxes are priced by volume at $2 per cubic inch. The volume of a cuboid is length x width x height.

The base area of a cuboid is length x width. In the table below, select the value that is closest to the cost of one box of base area 24.5 square inches as well as the cost of one box of base area 32.75 square inches. Make only one selection in each column.


­
 


This question was provided by Experts' Global
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­
­
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­For a 24.5 sq.inch base area, we have 6*w where w is the width of the cuboid.

Therefore, w= 24.5/6

We need to find the cost of the cuboid 

=> 6*9*(24.5/6)*2 = 440 dollars

Similarly for 32.75 square inch base area, the cost would be

=> 6*9*(32.75/6)*2 = 590 dollars.

Therefore, Option C and Option E respectively.
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Answer: $440, $590

Price = 2*volume.

Box 1: Price = 2*L*W*H

Price = 2*24.5*9 = $441

Box 2: Price = 2*L*W*H

Price = 2*32.75*9 = $589.5­
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