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Since 4 out of 7 days exceeded RT, Hence when arranging the list in ascending order, 3rd highest value must be below and 4th highest value must be higher than RT.

796<RT<810

Requests on Monday = 812 (Given)

Case 1 - For minimum request rejected post the limit of RT,
This will be true when the RT is nearest to higher value of range, i.e, 809

Hence rejected requests = 812-809 = 3

Case 2 - For maximum request rejected post the limit of RT,
This will be true when the RT is nearest to lower value of range, i.e, 796

Hence rejected requests = 812-796= 17
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4/7 days atleast one request was not addressed, therefore the min an RT can process is 795, therefore the max requests not addressed on the following Monday would be 17 (i.e., 812-795)
Similarly, the max req an RT can process is 809, therefore the min req not addressed would be 3 (i.e, 812-809)
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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.
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First, we write the request numbers in the week given, in ascending order:
780, 790, 795, 810, 820, 823, 830
We know that 4 of these numbers are greater than RT, but the rest are less than or equal to RT.
So RT must be at least 795 and at most 809 to satisfy these conditions.

\(795<=RT<=809\)

Now, if we have 812 requests for one day, the smallest amount of not addressed requests would be if RT=809, which will result in 3 requests being discarded.
The largest amount of not addressed requests would be if RT=795, which will leave 812-795=17 requests being discarded.

So the answers to the first and second columns are 3 and 17, respectively.



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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.
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Given Requests from Monday to Sunday
810, 790, 830, 823, 780, 795, 820

Given request Threshold= RT

If on 4 out of 7 days, there were requests that were not addressed, the number of requests on those days are:
810, 830, 823, 820

The smallest number in this data is 810.
If atleast one request was discarded(not addressed) on each of these 4 days, the RT = 810 - 1 =809

Considering there are more than 1 request that were discarded(not addressed), the minimum value of RT = 795

Next Monday, the requests received = 812
Minimum number of requests that were not addressed = 812-809 = 3
Maximum number of requests that were not addressed = 812-795 = 17

Answer: 3 and 17 respectively
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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.
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question asks us to find out the possible values of RTmax to get minimum no of discarded complaints and RTmin to get maximum no of discarded complaints which correspond to the given choices.
as is given that on exact 04 days at least one complaint was discarded in that week.
so, RTmax can be 809 corresponding to largest 4 of the given values(810,820,823,830)
hence for 812 complaints received on the next Monday, discarded minimum value is 3.
&
RTmin is 794 if any 4 values above 795 are taken into consideration (below than this value is not discussed as results aren't among the given choices)
so for 812 complaints received on the next Monday, discarded maximum value is 6+12=18
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Let RT = request threshold.
Exactly 4 days had requests > RT.
Requests per day: 810, 790, 830, 823, 780, 795, 820.
RT must be between 795 and 800 to have exactly 4 days exceeding RT.
For Monday (812 requests), not addressed = 812 - RT.
If RT = 795 --> not addressed = 17
If RT = 797 --> not addressed = 15
If RT = 794 --> not addressed = 18 (possible upper bound)
So minimum not addressed = 15, maximum = 18.
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Minimum: 812-810-1= 3 votes
Maximum: 810-795 = 15 + 2= 17 votes


[quote=
 


This question was provided by GMAT Club
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]
A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.[/quote]
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810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.
On the following Monday, the site received 812 requests.
For Minimum
3 lowest, 780, 790 and 795
4 atleast 1 unaddressed, then next smallest is 810, for maximizing and 1 unaddressed threshold will be 809
then gap of 812 -0

For Maximum, we will push the threshold to minimum side, for 810, lowest threshold can be 796, as 795 is addressed
then Gap 812-796 = 16
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ased on the given weekly data, where exactly four days exceeded the requests and three days did not, the RT must be an integer between 795 and 809, inclusive. On the following Monday, 812 requests were received. To find the minimum discarded requests, we use the highest possible RT (809), resulting in 812−809=3. For the maximum discarded requests, we use the lowest possible RT (795), resulting in 812−795=17.

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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.
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This question was provided by GMAT Club
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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.

Request Threshold (RT) is defined as the maximum number of requests it can handle in a single day.

If number of request per day > RT , the excess requests are discarded.

From Monday to Sunday, the RT values are : 810, 790, 830, 823, 780, 795 and 820.

So the maximum 4 values can be greater than RT. The values are 830, 823, 820, and 810.

The request on the following Monday is 812.

If we assume RT to be 809, then 810,820,823,830 are values greater than RT.

Minimum value of RT that are not addressed on Monday = (812 - 809) = 3.

Maximum value of RT that are not addressed on Monday = (812 - 796) = 16.

The maximum RT value out of the remaining that was addressed is max ( 790, 780, 795) . So the threshold can be 796.

Minimum and maximum request that is not addressed on Monday are 3 and 16 respectively.
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It is told that exactly 4 out of 7 days that week, there was at least one request that was not addressed.
For request to not get addressed, number of requests > RT

arranging the number of requests in descending order: 830, 823, 820, 810, 795, 790, 780

On next Monday, number of requests = 812,
So For minimum, RT<810
With RT = 809, exactly 4 days there was at least one request that was not addressed.
So 812 - 809 = 3

For Maximum, RT=795, so system will not address more than 795 and will have exactly 4 such days
812-795 = 17

Hence Minimum = 3
Maximum = 17
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This question was provided by GMAT Club
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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.
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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:

810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.



=> the information indicates that during 4 days the RT has been exceeded.
Ranking the request from low to high : 780 < 790 < 795 < 810 < 820 < 823 < 830

Indicating that the threshold (X) should lie between 795 < X < 810. => min 796 - max 809

If the website would receive 812 Requests the mimimum amount of request that would not be addressed will amount to => 812-809 = 3

If the website would receive 812 Requests the maximum amount of request that would not be addressed will be 812-796= 16
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Arrange the daily count in asc. order : 780, 790, 795, 810, 820, 823, 830
Since exactly 4 days must exceed RT,
-> the top 4 counts > RT
-> the bottom 3 counts <= RT
so RT can be anywhere between 795 to 809

On Monday there are 812 requests, so the no. of requests that couldn't be addressed is 812 - RT
Min of unaddressed= 812 - 809 = 3
Max of unaddressed = 812 - 795 = 17
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Given,

let Request Threshold be RT

number of requests received over the week:
810, 790, 830, 823, 780, 795, 820

given condition, On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

arrange number of requests in ascending order:
780, 790, 795, 810, 820, 823, 830

from above condition, we can conclude that
For 4 days, the number of requests was more than the RT
For 3 days, the number of requests was less than or equal to the RT

from the arranged list, we can observe that
780, 790, 795 must have been fully processed . So, RT <= 795.
810, 820, 823, 830 must have had some requests turned away. So, RT < 810.

we can conclude as 795 <= RT < 809

as per given data, on the following Monday, the site received 812 requests.

minimum number of requests not addressed on Monday:

If RT = 809, and 812 requests came in:

Requests not addressed = 812 (total) - 809 (processed) = 3 requests

maximum number of requests not addressed on Monday:

If RT = 795, and 812 requests came in:

Requests not addressed = 812 (total) - 795 (processed) = 17 requests
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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.

Arranging in ascending order

780, 790, 795, 810, 823, 820, 830

As the requests are not addressed post a threshold, the request will not have been addressed for the days the request was one of the following - 810, 823, 820, 830

Maximum rejects = 812 - 795 = 17
Minimum rejects = 812 - 809 = 3

Answer

Minimum = 3
Maximum = 17
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Question analysis: To answer the question, we must evaluate the given requests and find what are the maximum and minimum value of RT

Finding possible values of RT: First thing is to order the number of requests: 780, 790, 795, 810, 820, 823, 830
If 4 of 7 days passed RT limit, 795 < RT < 810. Min(RT) = 796 and Max(RT) = 809

So for 812 requests, the minimum denied is 3 and maximum is 16


----------------------
A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.
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Bunuel
 


This question was provided by GMAT Club
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A certain website has a request threshold (RT), defined as the maximum number of requests it can handle in a single day. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests. The remaining requests are not addressed and are permanently discarded.

During one week, from Monday to Sunday, the number of requests received on each day was as follows:


810, 790, 830, 823, 780, 795, 820

On exactly 4 out of the 7 days that week, there was at least one request that was not addressed.

On the following Monday, the site received 812 requests.

Based on this information, select the Minimum and the Maximum number of requests that could have been not addressed on that Monday. Make only two selections, one in each column.


The last four packets will get dropped. As shown above the minimum requests not catered will be in scenario when the threshold is at 809. This is because we know that the threshold can't be 810.

Min: 812 - 809 = 3

The maximum requests that will be not be catered is when the threshold is at 795. This is because we know that the request with 795 gets catered to

Max : 812 - 795 = 17

Minimum = 3
Maximum = 17

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