Over a 4-hour shift, Mark loaded a total of 80 boxes into a truck.
What was the average (arithmetic mean) weight of the boxes he loaded during the shift?
(1) During the first 2 hours of the shift, the average (arithmetic mean) weight of the boxes Mark loaded was 20 kilograms.
Total weight of boxes loaded during first 2 hours of the shift = 20x; x = number of boxes loaded during first 2 hours of the shift
Since there is no information about last 2 hours of the shift, average weight of the boxes he loaded during the shift can not be derived
NOT SUFFICIENT
(2) During the last 2 hours of the shift, the average (arithmetic mean) weight of the boxes Mark loaded was 30 kilograms.
Total weight of boxes loaded during last 2 hours of the shift = 30y; y = number of boxes loaded during last 2 hours of the shift
Since there is no information about first 2 hours of the shift, average weight of the boxes he loaded during the shift can not be derived
NOT SUFFICIENT
(1) + (2)
(1) During the first 2 hours of the shift, the average (arithmetic mean) weight of the boxes Mark loaded was 20 kilograms.
(2) During the last 2 hours of the shift, the average (arithmetic mean) weight of the boxes Mark loaded was 30 kilograms.
Total weight of boxes loaded during first 2 hours of the shift = 20x; x = number of boxes loaded during first 2 hours of the shift
Total weight of boxes loaded during last 2 hours of the shift = 30(80-x) = 2400 - 30x;
Total weight of boxes loaded during the 4 hours shift = 2400 - 30x + 20x = 2400 - 10x
Average weight of boxes loaded during the 4 hours shift = (2400 - 10x)/80 = 30 - x/8
Since x is unknown
NOT SUFFICIENT
IMO E