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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
4
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Total score required = 160 * 11 = 1760

Average of Team Alpha = 10

Average of Team Beta = 12.2 (Inference: The number of people in Team Beta is in multiples of 5 and the number of employees is greater than 0)

Statement 1

Number of employees of team gamma = 75

Average goals = 12

Total by team gamma = 900

Remaining points = 1760 - 900 = 860

Remaining Employees = 160 - 75 = 85

Case 1

Team Alpha has 80 members

Contribution by team alpha = 800

Team Beta has 5 members

Contribution by team beta = 61

Total = 861

Hence the avg > 11

Case 2

Team Alpha has 5 members

Contribution by team alpha = 50

Team Beta has 80 members

Contribution by team beta = 976

Total > 860

Hence Statement 1 is sufficient

Statement 2

Number of employees in Team Alpha = \(\frac{16}{32}\) * 160 = 80

Number of employees in Team Beta= \(\frac{1}{32} \)* 160 = 05

Number of employees in Team Gamma= \(\frac{15}{32} \)* 160 = 75

Case 1

Lets assume the average (arithmetic mean) number of goals scored by the employees of Team Gamma is 1

Total = 75 + 800 + 61 = 936

Therefore the average is < 11

Case 2

Lets assume the average (arithmetic mean) number of goals scored by the employees of Team Gamma is 100

The average is > 11.

Hence this statement is insufficient

IMO A
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
2
Kudos
IMO, Option A is the answer.

Statement I Alone.

From the question, Beta members must be a minimum of 5 members. Average is 12.2. Beta employee goals 12.2*5 = 61 goals
Alpha members will be a maximum of 80 members. 80*10 = 800 goals
Gamma Employees goals = 75*12 = 900 goals.

Total goals = 900+800+61 = 1761 goals
Average is = 1761/160 . Average is greater than 11 because 1760/160 =11
1761 is the minimum total number of goals possible based on the information in the question and in statement 1.
Therefore Statement I alone is sufficient.

Statement II Alone.

The ratio of the number of employees of Alpha Ltd to Beta Ltd to Gamma Ltd was 16:1:15. Or
The number of employees of Alpha Ltd to Beta Ltd to Gamma Ltd was 80:5:75.
We do not know about the scores of each member of Gamma. It is possible each member of Gamma scores 100. The average will be greater than 11.
On the other hand, if each member of Gamma scores 0 goal, the average will be smaller than 11.
Therefore Statement II alone is NOT sufficient.


Therefore IMO, Option A is the answer.
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
1
Kudos
Total no. of employees of A, B and G combined = 160
Average goals of A = 10
Average goals of B = 12.2
Ques: was average goals of all 160 employees more than 11 i.e. was total goals of all 160 employees more than 1760?

Statement 1: Average goals of 75 employees of G = 12
So, total goals of G = 900
If total goals of A and B combined is more than 1760-900=860, the answer to the ques would be a definite YES.
No. of employees of A and B combined is 160-75=85
If we assume that B scored bare min. goals, then total goals of B = 12.2*5=61 (should be a whole number)
So, total goals of A = 10*80 = 800
So, total goals of A and B combined = 861. Answer is a definite YES.
This statement alone is sufficient.

Statement 2: By using the ratio of no. of employees, we come to know that no. of empl of A/B/G = 80/5/75 respectively.
We can calculate total goals of A and B = 800+61 = 861
However, we don't know either average or total goals of G. Just knowing no. of employees of G won't help us to arrive at the answer.
Hence, this statement alone is not sufficient.

Answer is A.
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
1
Kudos
On a joint company picnic, 160 employees of Alpha Ltd, Beta Ltd and Gamma Ltd were engaged in several football matches. The average (arithmetic mean) number of goals scored by the employees of Alpha Ltd was 10, and the average (arithmetic mean) number of goals scored by the employees of Beta Ltd was 12.2. Was the average (arithmetic mean) number of goals scored by all 160 employees more than 11 ?

(1) The 75 employees of Gamma Ltd scored the average of 12 goals.
(2) The ratio of the number of employees of Alpha Ltd to Beta Ltd to Gamma Ltd was 16:1:15.

Using (1)

Min goals scored by Beta (atleast 5 players) = 12.2 *5 = 61 (No of Goals will be an integer)
Goals scored by 75 players of Gamma = 900
Goals scored by at most 80 players of Alpha = 800

Total = 1761
Average = 1761/160 > 11

YES is the unique answer..SUFFICIENT

Using (2)

Employees of Alpha , Beta and Gamma will be 80, 5 , and 75
Goals scored by 80 players of Alpha = 800
Goals scored by 05 players of Beta = 61
Goals scored by 75 players of Beta = (no information about the average of these players)

So, overall average can not be ascertained

NOT SUFFICIENT

Hence, (A) is the correct answer
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
Expert Reply
This one turned out to be 800+ Level question!!! Posted a solution.
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
lovely question! request you to post more such questions on the club...
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
Expert Reply
tanishqgirotra wrote:
lovely question! request you to post more such questions on the club...

­
Thank you! This is a GMAT Club Tests' question. Arguably one of the best sources of DS and PS questions on the market. I see you are already a subscriber, so you can check more there.
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
Option A. ­Alpha and Beta together average (10+12.2)/2 =11.1 and Gamma averages 12. Combined average will definitely be greater than 11.1

A is sufficient. 

Option B: There are 80, 15 and 75 employess respectively in Alpha, Beta and Gamma.  Average of Alpha and Beta is 11.1. But without how many goals Gamma scored or their average we cant say for sure what the average is. 

Not sufficient
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Re: GMAT Club World Cup 2022 (DAY 10): On a joint company picnic, 160 [#permalink]
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