Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included!
Sep 1810:00 AM IST
-11:00 PM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.
Sep 2601:00 PM EDT
-04:00 PM EDT
Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included. Class starts Saturdays Sept. 26, 2026 - Dec. 19, 2026, 1:00pm-4:00pm ES
06 Jul 2026, 08:50
Kudos
Bookmarks
Given that,
Six Cars ( A, B, C, D, E, F) and Six Places (1, 2, 3, 4, 5, 6) and cars (A, B) are parked together.
To find: Is Car F at 1?
Statement 1: B and C both parked at even-numbered spaces.
Even number spaces available: 2, 4, 6
Let (B, C) be at (2 & 4) in any order, then since (A, B) are together, the possible places for A can be at (1, 3, 5)
Let (B, C ) be at (4 & 6) in any order, then since (A, B) are together, the possible places for A can be (3,5)
Let (B, C) be at (2 & 6) in any order, then the possible places for A can be (1, 3, 5)
But in all the cases, we don't know anything about the positions of D, E & F.
Hence, this statement alone is Insufficient.
Statement 2: D and E both parked at odd-numbered spaces.
Odd-number spaces available: 1,3,5
Let (D, E) be at (1, 3) or (1,5) in any order, then since place 1 is occupied by either D or E, hence car F can't be parked there anymore.
Let (D, E) be at (3,5) in any order, also (A, B) need to be parked together, hence the only possible options for A, B together are (1,2), thus in this case as well, F can't be parked at 1.
Thus, in all the cases F can't be parked at 1.
Hence this Statement alone is Sufficient.
Thus, the final answer is B. Statement 2 alone is sufficient, but Statment 1 is not
Six Cars ( A, B, C, D, E, F) and Six Places (1, 2, 3, 4, 5, 6) and cars (A, B) are parked together.
To find: Is Car F at 1?
Statement 1: B and C both parked at even-numbered spaces.
Even number spaces available: 2, 4, 6
Let (B, C) be at (2 & 4) in any order, then since (A, B) are together, the possible places for A can be at (1, 3, 5)
Let (B, C ) be at (4 & 6) in any order, then since (A, B) are together, the possible places for A can be (3,5)
Let (B, C) be at (2 & 6) in any order, then the possible places for A can be (1, 3, 5)
But in all the cases, we don't know anything about the positions of D, E & F.
Hence, this statement alone is Insufficient.
Statement 2: D and E both parked at odd-numbered spaces.
Odd-number spaces available: 1,3,5
Let (D, E) be at (1, 3) or (1,5) in any order, then since place 1 is occupied by either D or E, hence car F can't be parked there anymore.
Let (D, E) be at (3,5) in any order, also (A, B) need to be parked together, hence the only possible options for A, B together are (1,2), thus in this case as well, F can't be parked at 1.
Thus, in all the cases F can't be parked at 1.
Hence this Statement alone is Sufficient.
Thus, the final answer is B. Statement 2 alone is sufficient, but Statment 1 is not
06 Jul 2026, 08:50
Kudos
Bookmarks
I think option B is the answer .
- 1 2 3 4 5 6 so ,, six spaces now if we saw each statement
-- statement 1 - if b and c both parked even number of places if b,c = 2,4 then a b 3 c 5 6 here , we got one case where k is not 1 ,,
now if b,c = 4,6 ,, then 1 2 3 b a c or 1 2 a b 5 c here k can be 1 so we are getting two cases that's why statement 1 It's not
possible ......... now we can exclude option no A , D
-- Statement 2 - If D and E both on odd numbers then if then d / e if 1 then the ans k is not 1
and if d and e respectively 3 , 5 then 1 2 d 4 e 6 or 1 2 e 4 d 6 for each only 1,2 left where we can put a , b as
Adjacent .
so now d is not 1 ,, So for each of the cases we are getting D is not equals to 1 ,, We can conclude that statement 2
alone is sufficient .
** I think people will tend to Separate statement one and statement two and do it together and get a wrong answer as option C **
That's my approach if anyone has any better Ways to do it feel free to share : )
- 1 2 3 4 5 6 so ,, six spaces now if we saw each statement
-- statement 1 - if b and c both parked even number of places if b,c = 2,4 then a b 3 c 5 6 here , we got one case where k is not 1 ,,
now if b,c = 4,6 ,, then 1 2 3 b a c or 1 2 a b 5 c here k can be 1 so we are getting two cases that's why statement 1 It's not
possible ......... now we can exclude option no A , D
-- Statement 2 - If D and E both on odd numbers then if then d / e if 1 then the ans k is not 1
and if d and e respectively 3 , 5 then 1 2 d 4 e 6 or 1 2 e 4 d 6 for each only 1,2 left where we can put a , b as
Adjacent .
so now d is not 1 ,, So for each of the cases we are getting D is not equals to 1 ,, We can conclude that statement 2
alone is sufficient .
** I think people will tend to Separate statement one and statement two and do it together and get a wrong answer as option C **
That's my approach if anyone has any better Ways to do it feel free to share : )
Maesha
Joined: 11 Jun 2026
Last visit: 31 Jul 2026
Posts: 29
Own Kudos:
Given Kudos: 4
Concentration: Leadership, Economics
Schools: HBS '28 (S)
06 Jul 2026, 08:55
Kudos
Bookmarks
If , A and B are together and B as well as C is in even position - the location of A,B,C can be 124 / 234/346/456 , F's position cant be determined by this as it can fall into 1 to 6 , any slot . so option one is not sufficient to solve this .
If A,B are together and D as well as E in odd slot then it is still not sufficient to solve this problem as F call occupy any slot among 2,4 ,6 , as if D and E occupies 1 and 3 , A B occupies 4,5 the remaining space are 2 and 6 . Also if D and E occupies 3 5 , A B must occupy 1 2 , so only possible space for B are 4,6 . so , option two is also not sufficient .
If we use consider both statement , when D and E sit in 3 , 5 space , AB must occupy 1 ,2 . So only left space for F will be 4 and 6 . If D and E sit is 1 , 3 space A, B, C are destined to occupy 4,5,6 as A and B are always together . In conclusion , the only possible sit for F is 2 or 4 or 6 .
Hence, both statement together are sufficient to solve this problem. As they answered the question - does F sit in space 1 . Ans is No.
If A,B are together and D as well as E in odd slot then it is still not sufficient to solve this problem as F call occupy any slot among 2,4 ,6 , as if D and E occupies 1 and 3 , A B occupies 4,5 the remaining space are 2 and 6 . Also if D and E occupies 3 5 , A B must occupy 1 2 , so only possible space for B are 4,6 . so , option two is also not sufficient .
If we use consider both statement , when D and E sit in 3 , 5 space , AB must occupy 1 ,2 . So only left space for F will be 4 and 6 . If D and E sit is 1 , 3 space A, B, C are destined to occupy 4,5,6 as A and B are always together . In conclusion , the only possible sit for F is 2 or 4 or 6 .
Hence, both statement together are sufficient to solve this problem. As they answered the question - does F sit in space 1 . Ans is No.
