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https://s3.eu-central-1.amazonaws.com/ultramsgmedia/2026/2/104644/bf75ff4d974b0d452127bfc8472d0e2d Hope this is visible lol Oops https://s3.eu-central-1.amazonaws.com/ultramsgmedia/2026/2/104644/b6d06e2badaecebf38fdb3f3fea913ac

X = 5a + 3 X = 7b + 4 Y = 5c + 3 Y = 7d + 4 X-Y = 5a - 5c + 3 - 3 X-Y = 7b - 7d + 4 - 4 X-Y = 5(a-c) X-Y = 7(b-d) X-Y must be a multiple of 5 and 7 .. So Option E... Alternatively Values can be 3,8,13,18,23,28,33,38,43 Values can also be 4,11,18,25,32,39,46 Common is 18 - Now 18 is a number that that has both 3 remainder when divided by 5 and 4 remainder when divided by 7.... So the next number which gives us the same when we will had 7 x 5 =35 in it.... And then again thr next will be when we add 35 again... Suppose Y is 18 X is 35+18=53 X-Y = 35 You pick any two numbers it will always give a multiple of 35... X = 5a + 3 X = 7b + 4 Y = 5c + 3 Y = 7d + 4 X-Y = 5a - 5c + 3 - 3 X-Y = 7b - 7d + 4 - 4 X-Y = 5(a-c) X-Y = 7(b-d) X-Y must be a multiple of 5 and 7 .. So Option E... Alternatively Values can be 3,8,13,18,23,28,33,38,43 Values can also be 4,11,18,25,32,39,46 Common is 18 - Now 18 is a number that that has both 3 remainder when divided by 5 and 4 remainder when divided by 7.... So the next number which gives us the same when we will had 7 x 5 =35 in it.... And then again thr next will be when we add 35 again... Suppose Y is 18 X is 35+18=53 X-Y = 35 You pick any two numbers it will always give a multiple of 35...

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This question is discussed in detail here: https://gmatclub.com/forum/when-positiv ... 28470.html Hope it helps.

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To divide anything by 3 you have to add all the digits of that number, now if there is a number that 9999 it is divisible by 3 but add one to it making it 10^4 and you get remainder 1 What's the answer to this though , E ?

https://s3.eu-central-1.amazonaws.com/ultramsgmedia/2026/2/104644/0951277953169d59162a4f0d350eaac3 Guys.. I’m reviewing the official mock.. the yellow one is the correct answer and the black marked is the one candidate chose right? Or its the opposite

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