In a survey of political preferences, 85% of those asked were in favou

85%= A+B+C-AnB-BnC-CnA-2(AnBnC)
85= 52+35+25-AnB-BnC-CnA-20
AnB+BnC+CnA= 92-85= 7
Thus number of candidates who supported more than one
= 7+10= 17%

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[quote="ankitahyd2013"][quote="gmatbusters"]

In a survey of political preferences, 85% of those asked were in favour of at least one of the three candidates – Ann, Bann and Cann. 52% of those asked favoured Ann, 35% favoured Bann and 25% favoured Cann. If 10% favoured all the three candidates, what percentage of those asked favoured more than one of the three candidates?
A) 7
B) 10
C) 17
D) 27
E) 37


% of people favouring Ann =52%
% of people favouring Bann=35%
% of people favouring Cann=25%
% of people favouring all three=10%
% of people favouring more than one canditate=[(52-10)+(35-10)+(25-10)-85]
=7%



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This question can be answered in 2 ways,

1) Total = In favor of A + In favor of B + In favor of C + In favor of neither - In favor of two + In favor of all three
that is, 100 = 52+35+25+15- In favor of two + 10
that is, In favor of two = 37
In favor of two includes In favor of all three twice as well, so we need to subtract that out.
Hence, required answer = 37 - 2*10 = 17 = C.

2) Total = In favor of A + In favor of B + In favor of C + In favor of neither - In favor of two only - 2*In favor of all three
that is, 100 = 52+35+25+15- In favor of two only - 2*10
that is, In favor of two only = 7
In favor of 2 only does not include In favor of all three, so we need to add it.
Hence, required answer = 7 + 10 = 17 = C.

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