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23 Jun 2018, 07:57
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gmatbusters
I think B
1) A C B E F D
2) A B C E F D
3) A B C D E F
the answer will change if we have to interchange the blocks. Then the ans will be 4. There can be various ways to solve then.
1) A B E F D C
2) A B C F D E
3) A B C D F E
4) A B C D E F
but as the question demands moving the blocks first approach needs to be followed i think, thus answer is 3
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03 Jul 2018, 17:46
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At the Canterbury Dog Fair, 1/4 of the poodles are also show dogs and 1/7 of the show dogs are poodles. What is the least possible number Of dogs at the fair?
A) 10
B) 11
C) 15
D) 25
E) 70
A) 10
B) 11
C) 15
D) 25
E) 70
A
12 Jul 2018, 10:15
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Let the number of Canterbury dogs = C
and number of show dogs = S
now, C/4 = S/7
For min value of total dogs, min value of C = 4, min value of S = 7.
now the min value of total no of dogs = number of Canterbury dogs+ number of show dogs- Common dogs
= 4+7-1 = 10
answer = 10
and number of show dogs = S
now, C/4 = S/7
For min value of total dogs, min value of C = 4, min value of S = 7.
now the min value of total no of dogs = number of Canterbury dogs+ number of show dogs- Common dogs
= 4+7-1 = 10
answer = 10
gmatbusters
