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If m and n are the positive integers such that m is prime and
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15 Feb 2020, 18:29
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GMATBusters’ Quant Quiz Question 8 If m and n are the positive integers such that m is prime and n is composite. Then A. mn cannot be an even number B. mn cannot be odd number C. mn cannot be even D. (m+n)/m cannot be even E. None of the above statements is true
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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 18:30
If m and n are the positive integers such that m is prime and n is composite. Then A. mn cannot be an even number FALSE: 119 = 2 even B. mn cannot be odd number FALSE: 54= 1 odd C. mn cannot be even FALSE: 3*4= 12 Even D. (m+n)/m cannot be even FALSE: (3+25)/2 = 14 Even E. None of the above statements is true Hence E is the right answer
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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 18:43
If m and n are the positive integers such that m is prime and n is composite. Then
A. mn cannot be an even number B. mn cannot be odd number C. mn cannot be even D. (m+n)/m cannot be even E. None of the above statements is true
A. m=17, n=15 => mn = even  possible B. m = 17, n=14 => mn = odd  possible C. m=2, n=14 => mn = even  possible D. m=3, n=9 => \(\frac{m+n}{m}\) = 4 = even
Answer  E



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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 18:55
If m and n are the positive integers such that m is prime and n is composite. Then A. mn cannot be an even number...This cannot be as m= 23 and n =15 (3*5) and hence m n is even B. mn cannot be odd number...this cannot be as m= 23 and n = 6 (2*3) and hence mn = 17 is odd C. mn cannot be even...this cannot be as m = 23 and n = 6(2*3) and hence mn= 23*6= 138 is even D. (m+n)/m cannot be even....this cannot be as m = 23 and n = 69 (3*23) and (m+n)=92 and m+n/m= 92/23= 4 which is even E. None of the above statements is true
E is the answer



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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 19:18
A. mn cannot be an even number: m=11 and n=9 mn=2 even B. mn cannot be odd number: m=11 and n=8 mn=3 odd C. mn cannot be even: m=11 and n=4 mn=44 even D. (m+n)/m cannot be even: m=2 n=14 (m+n)/m=8 even E. None of the above statements is true RIGHT



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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 19:37
If m and n are the positive integers such that m is prime and n is composite. Then Let's assume, case I: m=2 and n=6 or case II: m=2 and n=4, or case III: m=2 and n=15, or case IV: m=3 and n=15, then go to the options directly.
A. mn cannot be an even number, by considering all four cases, mn can be even or odd. So out B. mn cannot be odd number, by considering all four cases, mn can be even or odd. So out C. mn cannot be even, by considering all four cases, mn can be even or odd. So out D. (m+n)/m cannot be even, by considering all four cases, m+n/m can be even or odd. So out E. None of the above statements is true. So E is correct as all above options are incorrect.
Ans. E



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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 20:56
m is prime then m can be of form 2 , 3, 5, 7 n can be any number of the form having 2 or more factors A. mn cannot be an even number ex 62 =4 , 93 = 6 possible (false) B. mn cannot be odd number: 83 = 5 odd possible (false) C. mn cannot be even = 2*5 = 10 possible (false) D. (m+n)/m cannot be even = 1+m/n example 1+21/3 = 1+7 = 8 even possible (false) Thus E is correct E. None of the above statements is true
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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 21:17
If m and n are the positive integers such that m is prime and n is composite. Then
A. mn cannot be an even number if m = 11 and n = 9 then mn = 2 can be an even number (incorrect)
B. mn cannot be odd number if m = 11 and n = 4 then mn = 7 can be odd number (incorrect)
C. mn cannot be even if m = 11 and n = 4 then mn = 44 can be even (incorrect)
D. (m+n)/m cannot be even if m = 2 and n = 10 then (m+n)/m = 6 can be even (incorrect)
E. None of the above statements is true (correct)



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Re: If m and n are the positive integers such that m is prime and
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15 Feb 2020, 21:25
IMO E
A. mn cannot be an even number
if m happens to be 2 then (mn) will be even.
B. mn cannot be odd number.
if m happens to be 3 then (mn) will be odd.
C. mn cannot be even
mn is even since n is a composite no.
D. (m+n)/m cannot be even.
Value of(m+n)/m depends on value of M.
E. None of the above statements is true.
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Re: If m and n are the positive integers such that m is prime and
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16 Feb 2020, 01:33
Solution:
Question 8: If m and n are the positive integers such that m is prime and n is composite. Then
A. mn cannot be an even number B. mn cannot be odd number C. mn cannot be even D. (m+n)/m cannot be even E. None of the above statements is true
According to this question, m and n are positive integers. Therefore, m and n cannot be equal to 0. Moreover, m is prime and n is composite or n also has factors other than 1 and number 'n' itself. We need to select the option in which the statement is true.
Considering the options:
Option A: mn cannot be an even number. Let m = 13 and n = 9. Then, \(m  n = 13  9 = 4\), which is an even number. Thus, option A is eliminated. Option B: mn cannot be odd number. Let, m = 7 and n = 6. Then, \(m  n = 7  6 = 1\), which is an odd number. Thus, option B is eliminated. Option C: mn cannot be even . This statement is also false. If m = 7 and n = 6 then, \(mn = 7*6 = 42\), which is even number. Thus, option C is eliminated. Option D: \(\frac{(m+n)}{m}\) cannot be even. This statement is not true. If \(m = 2\) as 2 is the lowest prime number and \(n = 14\). Then, \(\frac{(m + n)}{m} = \frac{(2 + 14)}{2} = \frac{16}{2} = 8\), which is even number. Thus, option D is also eliminated.
Therefore, the correct answer is Option E that states 'None of the above statements is true'.



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Re: If m and n are the positive integers such that m is prime and
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16 Feb 2020, 04:59
This question can easily be solved by substituting different values for m and n.
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Re: If m and n are the positive integers such that m is prime and
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16 Feb 2020, 06:00
Solution:
Lets do it by options: A.mn cannot be an even number, not possible: m =5,n=1, mn is even B. mn cannot be odd number, m17,n=4 , mn is odd C. mn cannot be even = m=17, n=4 =>17*4 = 68, even D. (m+n)/m cannot be even true, it will always be a fraction.
Answer D




Re: If m and n are the positive integers such that m is prime and
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