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Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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01 Nov 2019, 04:04
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44% (01:55) correct 56% (02:20) wrong based on 188 sessions
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Halle, Julia and Drew have 5 donuts to share. If one of them can be given any whole number of donuts from 0 to 5, in how many different ways can the donuts be distributed. A. 19 B. 20 C. 21 D. 23 E. 37 Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
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Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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01 Nov 2019, 04:24
Bunuel wrote: Halle, Julia and Drew have 5 donuts to share. If one of them can be given any whole number of donuts from 0 to 5, in how many different ways can the donuts be distributed. A. 19 B. 20 C. 21 D. 23 E. 37 Are You Up For the Challenge: 700 Level Questions: 700 Level Questionstotal possible ways to distribute donuts as whole no 5c1+5c2+5c3+5c4+5c5 = 5+10+10+5+1 ; 21 IMO C



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Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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01 Nov 2019, 12:00
ABC 5 identical donuts 2 separators and 5 donuts = 7! Separators are identical and so are donuts. Hence ans = 7!/(5!*2!) = 21
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Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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01 Nov 2019, 12:02
Or n+r1 C r1 N=8 R=3 So ans = 7C2
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Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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09 Nov 2019, 23:51
ShankSouljaBoi wrote: ABC 5 identical donuts 2 separators and 5 donuts = 7! Separators are identical and so are donuts. Hence ans = 7!/(5!*2!) = 21
Posted from my mobile device I do not get your approach, could you please explain what you mean by separators? Thank you very much!
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Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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Updated on: 26 Dec 2019, 04:12
Use this, its basically the same thing n+r1 C r1 N=5 R=3 So ans = 7C2
Now coming to your query.
How many people are there ? Three, who ? A B and C. Are these 3 people identical? Not possible ! How many donuts have ti be distributed ? 5 . Are these identical ? Yes . Heck, over counting will happen. Just keep this thought in mind and lets move forward.
For explaining to u in a better manner lets assume A B C be three bags and not people. Further lets assume i am Donut 1 . Cool So mr soulja where you gonna jump ? I say, any one. Same with other 4 Mr. Soulja's.
... What this means is any donut can go in any bag , right ? Bag A can have all 5 or even Zero.
So when such a distribution problem comes you can apply the illustrated method.
Now lets see what i exactly did there.
Lets introduce two sticks or separators or in our explanation i would like to call them partitions. These partitions are a deciding factor. How ?
A partition 1 B partition 2 C  this combination reprsents any number of donuts in any bag. But at least one in each bag. partition 1 partition 2 ABC  this combination means No donuts to anyone imagine this OOOOOABC partition 1 A Partition2 BC  this combination means at least one is before partition 1 , at least one is in A, and remaining can be distributed anywhere.
So basically this is a permutation of 7 items 2 idenctical partitions and 5 exact (donuts or Mr soulja's)
Hence, 7!/(5!2!)
Ill be happy to entertain further questions.
If this was helpful, kindly give Kudo.



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Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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16 Nov 2019, 06:09



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Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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25 Feb 2020, 21:14
The possible combinations possible 023 : No of ways =6 014 : No of ways = 6 122 : No of ways = 3 005 : No of ways = 3 113 : No of ways = 3 Hence the total no of ways =21



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Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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27 Mar 2020, 23:30
Bunuel wrote: Halle, Julia and Drew have 5 donuts to share. If one of them can be given any whole number of donuts from 0 to 5, in how many different ways can the donuts be distributed. A. 19 B. 20 C. 21 D. 23 E. 37 Are You Up For the Challenge: 700 Level Questions: 700 Level QuestionsHalle  Julia  Drew Number of ways = 7C2 = 21 IMO C



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Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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07 Apr 2020, 04:41
Bunuel can you explain this in a simpler manner please.




Re: Halle, Julia and Drew have 5 donuts to share. If one of them can be gi
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07 Apr 2020, 04:41






