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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
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Expert Reply
Hi All,

These types of 'spacial relations' questions are rare on Test Day (chances are that you will NOT see any), but there is often a 'twist' to the question - involving placing the 'tiles' in a specific way. This question doesn't actually have a twist though (the numbers 2 and 3 are BOTH factors of 6 and 12, so you can orient the 'tiles' up-down or left-right and fill the space.

Since the total area is (6)(12) = 72 and the area of each tile is (2)(3) = 6, we know that the number of tiles needed to fill the space is 72/6 = 12 total tiles.

Final Answer:

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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
This kind of sum I prefer graphical approach to avoid mistake

two orientations possible

Please refer the attachment for figure

in both 6*2 orientation or 3*4 orientation , there will be 12 tiles
Attachments

1.png
1.png [ 2.96 KiB | Viewed 8527 times ]

2.gif
2.gif [ 3.42 KiB | Viewed 8544 times ]

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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
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Spikey243 wrote:
Why is E marked as the right answer?


Hi,
Answer is E itself, most have not read/understood the Q correctly..

there is a 6'*12' garden with a 2'*3' patch..
How many 2"*3" tiles can be placed and not 2'*3'
So VERY IMPORTANT TO READ Q PROPERLY

ans \(\frac{{6*12*12*12}}{{2*3}}- \frac{{2*12*3*12}}{{2*3}}=12*12*12-12*12= 11*12*12\), which is 1000+ and hence E
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
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Bunuel wrote:
Spikey243 wrote:
Why is E marked as the right answer?


Edited. Thank you.


Bunuel,
E is ok..
people have not read Q properly
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
damn that was tricky :D
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
total number of tiles is 1584. Convert 12 ft x 6 ft to inches and then find out how many tiles can fit in the shaded region.
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
chetan2u wrote:
Bunuel wrote:
Spikey243 wrote:
Why is E marked as the right answer?


Edited. Thank you.


Bunuel,
E is ok..
people have not read Q properly


so what is the answer E or? why is E ok im so confused
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
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sabxu1 wrote:
chetan2u wrote:
Bunuel wrote:
quote="Spikey243": Why is E marked as the right answer?

Edited. Thank you.


Bunuel,
E is ok..
people have not read Q properly


so what is the answer E or? why is E ok im so confused

The international symbols for feet and inches are ft and in, respectively. But sometimes in the USA, people use the prime and double prime symbols to represent feet and inches, respectively. The OP did not include a definition of prime and double prime. IMHO, it's quite unlikely people outside the USA may be aware that the single prime is not an inch, but a foot. I seriously doubt the GMAT exam contains a question exactly as specified in the OP.
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
chetan2u wrote:
sabxu1 wrote:
chetan2u wrote:
Bunuel,
E is ok..
people have not read Q properly


so what is the answer E or? why is E ok im so confused


hi answer is E itself

there is a 6'*12' garden with a 2'*3' patch..
Q is -How many 2"*3" tiles can be placed and not 2'*3'
convert all feet into inches as we arelooking into tiles which are in inches

so total area of garden = 6*12*12*12
shaded region = 12*12(6*12-2*3) = 12*12*2*3(12-1)..
no of 2"*3" tiles required =\(\frac{12*12*12*2*3*11}{2*3} = 12*12*11= 1584 > 1500\)
so ans is 1500+
E

Apologies for finding a doubt with figure
nowhere in the figure it is showing that the rectangle is 12 feet * 6 feet
or are we supposed to assume 12' as 12 feet?
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
Bunuel wrote:

How many 2-inch by 3-inch rectangular tiles are required to tile this shaded region?

A. Less than 10
B. 10—100
C. 101—1,000
D. 1,001—1,500
E. 1,500+

Attachment:
2016-01-24_1704.png

Apologies for finding a doubt with figure
nowhere in the figure it is showing that the rectangle is 12 feet * 6 feet
or are we supposed to assume 12' as 12 feet?
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
chetan2u wrote:
sabxu1 wrote:
chetan2u wrote:
Bunuel,
E is ok..
people have not read Q properly


so what is the answer E or? why is E ok im so confused


hi answer is E itself

there is a 6'*12' garden with a 2'*3' patch..
Q is -How many 2"*3" tiles can be placed and not 2'*3'
convert all feet into inches as we arelooking into tiles which are in inches

so total area of garden = 6*12*12*12
shaded region = 12*12(6*12-2*3) = 12*12*2*3(12-1)..
no of 2"*3" tiles required =\(\frac{12*12*12*2*3*11}{2*3} = 12*12*11= 1584 > 1500\)
so ans is 1500+
E


Bunuel,
Can you give us your solution too..
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
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Kudos
" stands for Inches
' stands for feet .

And this question is god to know how much you are attentive about units.
(12*12*6*12)/(3*2) > 1500
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
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Kudos
This is tricky!!!
" = Inch, ' = ft !
1 ft = 12 inch
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
I am not from the US, I am not aware that ' is ft and '' is inch.
Do we really need to know this for GMAT?
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
frankgraves wrote:
I am not from the US, I am not aware that ' is ft and '' is inch.
Do we really need to know this for GMAT?


frankgraves, probably not. But for me, the takeaway was not that ' is ft and " is inch. I knew it before seeing this question, but did not pay attention to this while solving this question and got the answer wrong. Bunuel this was awesome even if it's not likely to be tested on the GMAT.
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
chetan2u wrote:
sabxu1 wrote:
chetan2u wrote:
Bunuel,
E is ok..
people have not read Q properly


so what is the answer E or? why is E ok im so confused


hi answer is E itself

there is a 6'*12' garden with a 2'*3' patch..
Q is -How many 2"*3" tiles can be placed and not 2'*3'
convert all feet into inches as we arelooking into tiles which are in inches

so total area of garden = 6*12*12*12
shaded region = 12*12(6*12-2*3) = 12*12*2*3(12-1)..
no of 2"*3" tiles required =\(\frac{12*12*12*2*3*11}{2*3} = 12*12*11= 1584 > 1500\)
so ans is 1500+
E



Hey, can you explain the shaded region and the fraction thereafter? should 3'2' not necessarily be 3'*12*2'*12?
and the unshaded portion as 6*12*12*12/ 3'*12*2'*12?
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Re: How many 2-inch by 3-inch rectangular tiles are required to tile this [#permalink]
Expert Reply
Jaya6 wrote:
chetan2u wrote:

hi answer is E itself

there is a 6'*12' garden with a 2'*3' patch..
Q is -How many 2"*3" tiles can be placed and not 2'*3'
convert all feet into inches as we arelooking into tiles which are in inches

so total area of garden = 6*12*12*12
shaded region = 12*12(6*12-2*3) = 12*12*2*3(12-1)..
no of 2"*3" tiles required =\(\frac{12*12*12*2*3*11}{2*3} = 12*12*11= 1584 > 1500\)
so ans is 1500+
E



Hey, can you explain the shaded region and the fraction thereafter? should 3'2' not necessarily be 3'*12*2'*12?
and the unshaded portion as 6*12*12*12/ 3'*12*2'*12?


The unshaded portion is 3’*2’=3*12*2*12.

While, the shaded will become total-unshaded. => 6*12*12*12-3*12*2*12
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